All GMAT Math Resources
Example Questions
Example Question #1 : Graphing Complex Numbers
Raise to the power of four.
None of the other responses gives the correct answer.
Squaring an expression, then squaring the result, amounts to taking the original expression to the fourth power. Therefore, we can first square :
Now square this result:
Example Question #2 : Graphing Complex Numbers
Raise to the power of eight.
For any expression , . That is, we can raise an expression to the power of eight by squaring it, then squaring the result, then squaring that result.
First, we square:
Square this result to obtain the fourth power:
Square this result to obtain the eighth power:
Example Question #1 : Graphing Inverse Variation
Give the vertical asymptote of the graph of the equation
The vertical asymptote is , where is found by setting the denominator equal to 0 and solving for :
This is the equation of the vertical asymptote.
Example Question #1072 : Problem Solving Questions
Give the -intercept(s), if any, of the graph of the equation
The graph has no -intercept.
The graph has no -intercept.
Set in the equation and solve for .
This is impossible, so the equation has no solution. Therefore, the graph has no -intercept.
Example Question #192 : Graphing
Give the -intercept(s), if any, of the graph of the equation
The graph has no -intercept.
Set in the equation and solve for .
The -intercept is
Example Question #2 : Graphing Inverse Variation
Give the horizontal asymptote, if there is one, of the graph of the equation
The graph of the equation has no horizontal asymptote.
To find the horizontal asymptote, we can divide both numerator and denominator in the right expression by :
As approaches positive or negative infinity, and both approach 0. Therefore, approaches , making the horizontal asymptote the line of the equation .
Example Question #2 : Graphing Inverse Variation
Give the -intercept of the graph of the equation .
The graph has no -intercept.
Set in the equation:
The -intercept is .
Example Question #91 : Graphing
Which of the following inequalities is graphed above?
First, we determine the equation of the boundary line. This line includes points and , so the slope can be calculated as follows:
We can find the slope-intercept form of the line by substituting
in the following equation:
The equation of the boundary line is .
The boundary is excluded, as is indicated by the line being dashed, so the equality symbol is replaced by either or . To find out which one, we can test a point in the solution set - for ease, we will choose :
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0 is greater than so the correct symbol is .
The correct choice is .
Example Question #1 : Graphing A Two Step Inequality
First, consider the characteristics of the line. The slope is equal to 2 and the y-intercept is equal to 3. Because the line is solid, that indicates that the inequality is "greater than or equal to" or "less than or equal to". Finally, choose a point to determine the direction of the shading. The origin (0,0) is usually a good choice unless it falls on the line. If the chosen point makes the statement true, it must be included in the shaded region. If it is false, it must not.
Because 0 is less than 3 and the origin is not included in the shaded region, the correct answer must include "greater than or equal to"
Example Question #2 : Graphing A Two Step Inequality
Which of the following inequalities is graphed above?
None of the above.
In order to graph the inequality pictured above, we must first find the equation of its boundary line. Based on the image, we see that the line includes the points and , so the slope of the line is
.
We can now find the -intercept form of the line by substituting and the point into the slope-intercept equation and solving for :
The equation of the boundary line is therefore . Since we see that the boundary line is dashed, we know that the values on the line are excluded from the inequality, so the sign will be replaced by a or a .
In order to determine which one, we can test a point in the solution set; let's test since it's the simplest to substitute:
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, so the correct symbol is :