GMAT Math : Radius

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Example Questions

Example Question #21 : Radius

A circle has a radius of $7\:cm$ . Calculate the area of the circle.

Possible Answers:

$49\pi\:cm^2$

$3.5\pi\:cm^2$

$14\pi\:cm^2$

$7\pi\:cm^2$

$56\pi\:cm^2$

Correct answer:

$49\pi\:cm^2$

Explanation:

Using the formula for the area of a circle, we can plug in the given value for its radius and calculate our solution:

$A=\pi r^2=\pi (7\:cm)^2=49\pi\:cm^2$

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Example Question #282 : Problem Solving Questions

What is the area of a circle with a diameter of 18cm ?

Possible Answers:

$90\pi cm^2$

$81\pi cm^2$

$324\pi cm^2$

$54\pi cm^2$

$36\pi cm^2$

Correct answer:

$81\pi cm^2$

Explanation:

The area of a circle is defined by $A=\pi r^{2}$ , where is the radius of the circle. We are provided with the diameter of the circle, which is twice the length of .

If d=18cm , then $r=\frac{d}{2}=\frac{18cm}{2}=9cm$

Then, solving for :

$A=\pi r^{2}$

$A=\pi (9cm)^{2}$

$A=81\pi cm^2$

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Example Question #51 : Circles

A circle on the coordinate plane is defined by the equation $x^{2}+y^{2}=25$ . What is the area of the circle?

Possible Answers:

$25\pi$

$5\pi$

$50\pi$

$60\pi$

Not enough information provided.

Correct answer:

$25\pi$

Explanation:

The equation of a circle centered at the origin of the coordinate plane is $x^{2}+y^{2}=r^{2}$ , where is the radius of the circle.

The area of the circle, in turn, is defined by the equation $A=\pi r^{2}$ .

Since we are provided with the equation $x^{2}+y^{2}=25$ , we can deduce that $r^{2}=25$ and that $A=25\pi$ .

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Example Question #21 : Calculating The Area Of A Circle

What is the area of a circle with a diameter of 20cm ?

Possible Answers:

$100\pi cm^2$

Not enough information provided.

$20\pi cm^2$

$400\pi cm^2$

$40\pi cm^2$

Correct answer:

$100\pi cm^2$

Explanation:

The area of a circle is defined by $A=\pi r^{2}$ , where is the radius of the circle. We are provided with the diameter of the circle, which is twice the length of .

If d=20cm , then $r=\frac{d}{2}=\frac{20cm}{2}=10cm$

Therefore:

$A=\pi r^{2}$

$A=\pi (10cm)^{2}$

$A=100\pi cm^2$

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Example Question #51 : Geometry

4c 43438 lg A square is inscribed in a circle of r=5 .

What is the area of the region inside the circle but not inside the square?

Possible Answers:

$25\pi - 50$

$25\pi - 25$

$25\pi$

$\textup{Cannot be determined}$

Correct answer:

$25\pi - 50$

Explanation:

Our first step will be to draw two radii, from the circle's center to two adjacent vertexes of the square, forming a triangle, the third side of which is the edge of the square. Because these radii bisect the square's right angles, we can determine that the triangle we drew is a 45˚ - 45˚ - 90˚ right triangle. Because of the rules governing those isoceles right triangles, we can then determine that, because the two legs of the triangle are 5 (radius = 5), the hypotenuse (the square's side) must equal $5\sqrt{2}$ .

Now we can find the square's area:

$A_{s} = (5\sqrt{2})^{2} = 50$

and the circle's area:

$A_{c} = \pi(5)^{2} = 25\pi$

Finally we subtract the square's area from the circle's area:

$A_{c} - A_{s} = 25\pi - 50$

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Example Question #292 : Problem Solving Questions

An engineer is designing a circular hatch for a submarine. If the hatch must have a circumference of 4.56m , what will its area be?

Possible Answers:

3.45m^2

1.65m^2

.73m^2

3.14m^2

Correct answer:

1.65m^2

Explanation:

An engineer is designing a circular hatch for a submarine. If the hatch must have a circumference of 4.56m , what will its area be?

To find area, we will need the radius. We can find the radius using the following formula:

$Circumference=2 \pi r$

So, plug in and solve for r

$4.56m=2 \pi r$

$r\approx.73m$

Next, use the area formula to find the area:

$A_{circle}=\pi r^2$

$A_{circle}=\pi (.73m)^2\approx 1.65m^2$

So we have our answer!

1.65m^2

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Example Question #27 : Calculating The Area Of A Circle

and are the area and the diameter of the same circle.

$A = \frac{1}{L}$

$d = t^{2}$ .

Which of the following is a true statement?

Possible Answers:

varies directly as the square of .

varies directly as the fourth power of .

varies directly as the square root of .

varies inversely as the fourth power of .

varies inversely as the square of .

Correct answer:

varies inversely as the fourth power of .

Explanation:

The area and the diameter of a circle are related by the formula

$A = \frac{1}{4} \pi d^{2}$

Substituting:

$\frac{1}{L} = \frac{1}{4} \pi (t^{2}) ^{2}$

$\frac{1}{L} = \frac{\pi t^{4} }{4}$

$L= \frac{4}{\pi t^{4} }$

If $K = \frac{4}{\pi}$ , then

$L = \frac{K}{t^{4}}$ ,

and varies inversely as the fourth power of .

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Example Question #21 : Calculating The Area Of A Circle

A circle has radius $\pi ^{t}$ . Give its area.

Possible Answers:

$\pi ^{t+1}$

$\pi ^{t+2}$

$2 \pi ^{2t}$

$2 \pi ^{t+1}$

$\pi ^{2t+1}$

Correct answer:

$\pi ^{2t+1}$

Explanation:

The area of a circle is found using the following formula:

$A = \pi r^{2}$

Set $r= \pi ^{t}$ :

$A = \pi \cdot ( \pi ^{t}) ^{2}$

$A = \pi^{1} \cdot \pi ^{2t}$

$A = \pi ^{2t+1}$

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Example Question #26 : Calculating The Area Of A Circle

If the pitcher plant Sarracenia purpurea has a circular opening with a circumference of 6 inches, what is the area of the opening?

Possible Answers:

$A\approx0.95 in^2$

$A\approx 2.86 in^2$

$A\approx 37.70 in^2$

$A\approx 11.45 in^2$

Correct answer:

$A\approx 2.86 in^2$

Explanation:

If the pitcher plant Sarracenia purpurea has a circular opening with a circumference of 6 inches, what is the area of the opening?

We need to work backward from circumference to find area.

Circumference can be found as follows:

$Circ=\pi 2 r$

Use this to find "r" which we will use to find the area:

$6=2 \pi r$

$r=\frac{3}{\pi}$

Next, find area using the following:

$A=\pi r^2$

$A=\pi (\frac{3}{\pi})^2$

$A\approx 2.86 in^2$

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Example Question #51 : Circles

A square and a circle have the same area. What is the ratio of the length of one side of the square to the radius of the circle?

Possible Answers:

$2 \textrm{ to }\sqrt{\pi }$

$\pi \textrm{ to }1$

$\sqrt{\pi } \textrm{ to }1$

$1 \textrm{ to }\pi$

$1 \textrm{ to }\sqrt{\pi }$

Correct answer:

$\sqrt{\pi } \textrm{ to }1$

Explanation:

Let be the sidelength of the square is the square and be the radius of the circle. Then since the areas of the circle and the square are equal, we can set up this equation:

$s^{2 }= \pi r^{2}$

We find the ratio of to - that is, $\frac{s}{r}$ - as follows:

$s^{2 }\div r^{2}= \pi r^{2} \div r^{2}$

$\frac{s^{2 } }{r^{2}} = \pi$

$\sqrt{\frac{s^{2 } }{r^{2}}} =\sqrt{ \pi}$

$\frac{s}{r} =\sqrt{\pi } = \frac{\sqrt{\pi }}{1}$

The correct ratio is $\sqrt{\pi } \textrm{ to }1$ .

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GMAT Math : Radius

Study concepts, example questions & explanations for GMAT Math

All GMAT Math Resources

Example Questions

Example Question #21 : Radius

Example Question #282 : Problem Solving Questions

Example Question #51 : Circles

Example Question #21 : Calculating The Area Of A Circle

Example Question #51 : Geometry

Example Question #292 : Problem Solving Questions

Example Question #27 : Calculating The Area Of A Circle

Example Question #21 : Calculating The Area Of A Circle

Example Question #26 : Calculating The Area Of A Circle

Example Question #51 : Circles

All GMAT Math Resources

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