GMAT Math : Calculating the length of an arc

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Example Questions

Example Question #1 : Calculating The Length Of An Arc

Chords

Note: Figure NOT drawn to scale

Refer to the above diagram.

\(\displaystyle \widehat{ABC} = 220 ^{\circ }\)

\(\displaystyle \widehat{BCA} = 230 ^{\circ }\)

What is \(\displaystyle m \angle BAC\) ?

Possible Answers:

\(\displaystyle 50^{\circ }\)

\(\displaystyle 40^{\circ }\)

\(\displaystyle 60^{\circ }\)

\(\displaystyle 55^{\circ }\)

\(\displaystyle 45^{\circ }\)

Correct answer:

\(\displaystyle 45^{\circ }\)

Explanation:

The degree measure of \(\displaystyle \angle BAC\) is half the degree measure of the arc it intercepts, which is \(\displaystyle \widehat{BC}\). We can use the measures of the two given major arcs to find \(\displaystyle m \widehat{BC}\), then take half of this:

\(\displaystyle m\widehat{AC} = 360 ^{\circ } - m\widehat{ABC} = 360 ^{\circ } - 220 ^{\circ } = 140^{\circ }\)

\(\displaystyle m\widehat{AB} = 360 ^{\circ } - m\widehat{BCA} = 360 ^{\circ } - 230 ^{\circ } = 130^{\circ }\)

\(\displaystyle m\widehat{BC} +m\widehat{AB} + m\widehat {AC} =360 ^{\circ }\)

\(\displaystyle m\widehat{BC} +130^{\circ }+ 140^{\circ } =360 ^{\circ }\)

\(\displaystyle m\widehat{BC} +270^{\circ } =360 ^{\circ }\)

\(\displaystyle m\widehat{BC} +270^{\circ } -270^{\circ } =360 ^{\circ }-270^{\circ }\)

\(\displaystyle m\widehat{BC} =90 ^{\circ }\)

\(\displaystyle \angle BAC = \frac{1}{2}m\widehat{BC} = \frac{1}{2} \cdot 90 ^{\circ } = 45^{\circ }\)

Example Question #11 : Circles

A giant clock has a minute hand that is eight feet long. The time is now 2:40 PM. How far has the tip of the minute hand moved, in inches, between noon and now?

Possible Answers:

\(\displaystyle 448 \pi \textrm{ in}\)

\(\displaystyle 512 \pi \textrm{ in}\)

\(\displaystyle 128 \pi \textrm{ in}\)

\(\displaystyle 256 \pi \textrm{ in}\)

\(\displaystyle 112 \pi \textrm{ in}\)

Correct answer:

\(\displaystyle 512 \pi \textrm{ in}\)

Explanation:

Between noon and 2:40 PM, two hours and forty minutes have elapsed, or, equivalently, two and two-thirds hours. This means that the minute hand has made \(\displaystyle 2 \frac{2}{3} = \frac{8}{3}\)  revolutions.

In one revolution, the tip of an eight-foot minute hand moves \(\displaystyle C = 2 \pi r =2 \pi \cdot 8 = 16 \pi\) feet, or \(\displaystyle 16 \pi \cdot 12 = 192 \pi\) inches.

After  \(\displaystyle \frac{8}{3}\) revolutions, the tip of the minute hand has moved \(\displaystyle 192 \pi \cdot 2 \frac{2}{3} = \frac{192}{1} \cdot \frac{8}{3} \cdot \pi = 512 \pi\) inches.

Example Question #253 : Problem Solving Questions

In the figure shown below, line segment \(\displaystyle AB\) passes through the center of the circle and has a length of \(\displaystyle 8\:cm\). Points \(\displaystyle A\)\(\displaystyle B\), and \(\displaystyle C\) are on the circle. Sector \(\displaystyle COB\) covers \(\displaystyle \frac{1}{6}th\) of the total area of the circle. Answer the following questions regarding this shape.

Circle1

What is the length of the arc formed by angle \(\displaystyle AOB\)?

Possible Answers:

\(\displaystyle 12\pi \:cm\)

\(\displaystyle 4 \pi \:cm\)

\(\displaystyle 16 \pi \:cm\)

\(\displaystyle 8 \pi \:cm\)

\(\displaystyle 64 \pi \:cm\)

Correct answer:

\(\displaystyle 4 \pi \:cm\)

Explanation:

To find arc length, we need to find the total circumference of the circle and then the fraction of the circle we are interested in. Our circumference of a circle formula is:

\(\displaystyle C=2\pi *r=d \pi\)

Where \(\displaystyle r\) is our radius and \(\displaystyle d\) is our diameter.

In this problem, our diameter is the length of \(\displaystyle AB\), which is \(\displaystyle 8\:cm\), so our total circumference is:

\(\displaystyle C=8\pi \:cm\)

Now, to find the fraction of the circle we are interested in, we need to realize that angle \(\displaystyle AOB\) is \(\displaystyle 180\) degrees. We know this because it is made by straight line \(\displaystyle AB\). Armed with this knowledge, we can safely calculate the length of our arc using the following formula:

\(\displaystyle Arc Length=d \pi *\frac{\Theta }{360}=8 \pi *\frac{180 }{360}=8 \pi *\frac{1 }{2}=4 \pi \:cm\)

Example Question #21 : Sectors

Consider the Circle \(\displaystyle O\):

Circle3

(Figure not drawn to scale.)

Suppose \(\displaystyle \angle BOX\) is \(\displaystyle 100^{\circ}\). What is the measure of arc \(\displaystyle BX\) in meters?

Possible Answers:

\(\displaystyle 30\pi\:m\)

\(\displaystyle 5\pi\:m\)

\(\displaystyle \frac{5}{3}\pi\:m\)

\(\displaystyle 18\pi\:m\)

\(\displaystyle \frac{25}{3}\pi\:m\)

Correct answer:

\(\displaystyle \frac{25}{3}\pi\:m\)

Explanation:

To find arc length, multiply the total circumference of a circle by the the fraction of the total circle that defines the arc with the length for which you are solving.

In this case, to find the total circumference:

\(\displaystyle C=2 \pi r=2*(15\:m)*\pi=30 \pi\:m\)

To find the fraction with which we are concerned, make a fraction with the number of degrees in \(\displaystyle \angle BOX\) in the numerator and the total degrees in a circle in the denominator:

\(\displaystyle \frac{100}{360}=\frac{10}{36}=\frac{5}{18}\)

Multiply together and simplify:

\(\displaystyle Arc\:Length=\frac{5}{18}*30 \pi= \frac{150\pi}{18}= \frac{25}{3}\pi\)

Example Question #22 : Sectors

What is the arc length for a sector with a central angle of \(\displaystyle 45^{\circ}\) if the radius of the circle is \(\displaystyle 3\) ?

Possible Answers:

\(\displaystyle \frac{\pi }{2}\)

\(\displaystyle \frac{\pi }{4}\)

\(\displaystyle \pi\)

\(\displaystyle \frac{3\pi }{2}\)

\(\displaystyle \frac{3\pi }{4}\)

Correct answer:

\(\displaystyle \frac{3\pi }{4}\)

Explanation:

Using the formula for arc length, we can plug in the given angle and radius to calculate the length of the arc that subtends the central angle of the sector. The angle, however, must be in radians, so we make sure to convert degrees accordingly by multiplying the given angle by \(\displaystyle \frac{\pi }{180}\) :

\(\displaystyle S=r\theta\)

\(\displaystyle S=3(45^{\circ})(\frac{\pi }{180^{\circ}})=3(\frac{\pi }{4})=\frac{3\pi}{4}\)

Example Question #23 : Sectors

The arc \(\displaystyle \widehat{AB}\) of a circle measures \(\displaystyle 90^{\circ }\). The chord of the arc, \(\displaystyle \overline{AB}\), has length \(\displaystyle x + 2\). Give the length of the arc \(\displaystyle \widehat{AB}\).

Possible Answers:

\(\displaystyle \pi x \sqrt{2}+ 2 \pi \sqrt{2}\)

\(\displaystyle \frac{ \sqrt{2}}{\pi}x + \frac{ \sqrt{2}}{\pi}\)

\(\displaystyle \frac{ \pi \sqrt{2}}{2} x + \pi \sqrt{2}\)

\(\displaystyle \frac{ \pi \sqrt{2}}{4} x + \frac{ \pi \sqrt{2}}{2}\)

\(\displaystyle \frac{2 \sqrt{2}}{\pi}x + \frac{4 \sqrt{2}}{\pi}\)

Correct answer:

\(\displaystyle \frac{ \pi \sqrt{2}}{4} x + \frac{ \pi \sqrt{2}}{2}\)

Explanation:

Examine the figure below, which shows the arc and chord in question.

Circle x

If we extend the figure to depict the circle as the composite of four quarter-circles, each a \(\displaystyle 90^{\circ }\) arc, we see that \(\displaystyle x+2\) is also the side of an inscribed square. A diagonal of this square, which measures \(\displaystyle \sqrt{2}\) times this sidelength, or

\(\displaystyle (x+2) \sqrt{2} = x\sqrt{2} + 2\sqrt{2}\),

is a diameter of this circle. The circumference is \(\displaystyle \pi\) times the diameter, or

\(\displaystyle \pi ( x\sqrt{2} + 2\sqrt{2}) = x \pi \sqrt{2} + 2 \pi \sqrt{2}\).

Since a \(\displaystyle 90^{\circ }\) arc is one fourth of a circle, the length of arc \(\displaystyle \widehat{AB}\) is

\(\displaystyle \frac{1}{4}( x \pi \sqrt{2} + 2 \pi \sqrt{2})\)

\(\displaystyle = \frac{ \pi }{4} x\sqrt{2} + \frac{ \pi }{2} \sqrt{2}\)

\(\displaystyle = \frac{ \pi \sqrt{2}}{4} x + \frac{ \pi \sqrt{2}}{2}\)

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