GED Math : Basic Operations

Study concepts, example questions & explanations for GED Math

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Example Questions

Example Question #6 : Division

Solve for 

Possible Answers:

Correct answer:

Explanation:

In order to solve for , we'll need to move all of the variables on its side to the other side of the equation.

We can see that  is currently the denominator to , so we need to move the  in order to solve for .

To move the , we'll have to divide it on the other side. Keep in mind though that the  is in the numerator, so it will stay in the numerator when it divides over.

We cannot proceed with the question as there is nothing left to do. Our variables are different and the  can stay where it is.

Our answer is 

Example Question #7 : Division

Solve for 

Possible Answers:

Correct answer:

Explanation:

In order to solve for , we need to move all the numbers and variables to the other side of the equation.

We can see that  is currently being multiplied by . In order to move the , we need to divide it on the other side of the equation.

Both  and  can be divided by , which in turn gets rid of the  in the denominator. 

We cannot proceed any farther since there is nothing left to do in the equation.

Our answer is 

Example Question #7 : Division

Solve for 

Possible Answers:

Correct answer:

Explanation:

In order to solve for , we'll need to move all the other variables to the other side of the equation. Currently  is stuck to , so we need to move the  to the other side.

In order to move , we'll have to divide it to the other side of the equation.

Since all the variables are different, we cannot do anything else to simplify this equation.

Our answer is 

Example Question #272 : Numbers And Operations

Solve the equation: 

Possible Answers:

Correct answer:

Explanation:

Division is another way of seeing how many of the number we are dividing with is in the number we are dividing. 

Let's take a look at . This is the number we are dividing, and  is the number we are dividing with as told by their placement. We want to see how many 's there are in .

To figure this out, we'll add a  each time until we get to .

We have now reached , so how many 's did it take us to get there? It took us  's to get to , and if you check with a calculator you will see that this is the answer as well.

Our answer is .

Example Question #1 : Operations With Negative Numbers

Solve:

Possible Answers:

Correct answer:

Explanation:

When a negative number is multipied by a positive number, the result is negative.

Therefore,

.

Example Question #2 : Operations With Negative Numbers

Evaluate:

Do not use a calculator.

Possible Answers:

Correct answer:

Explanation:

To subtract a larger positive number from a smaller positive number, do the reverse, then affix a negative symbol, as demonstrated here:

So subtract 3.7 from 9.17:

Since the answer must be negative, it is .

Example Question #2 : Operations With Negative Numbers

Evaluate:

Do not use a calculator.

Possible Answers:

Correct answer:

Explanation:

To obtain the product of two numbers of unlike sign, multiply their absolute values:

The product will remain positive.

Example Question #1 : Operations With Negative Numbers

Evaluate  for . Do NOT use a calculator.

Possible Answers:

Correct answer:

Explanation:

Substitute  for  in the expression.

Example Question #2 : Operations With Negative Numbers

Evaluate: 

Do not use a calculator.

Possible Answers:

Correct answer:

Explanation:

To subtract with negative numbers, change to an addition and make the second number its opposite:

To add two numbers of unlike sign, if the positive has the greater absolute value, simply subtract the absolute values.

The answer is 45.

Example Question #5 : Operations With Negative Numbers

Evaluate:

Do NOT use a calculator.

Possible Answers:

Correct answer:

Explanation:

To obtain the product of two numbers of unlike sign, multiply their absolute values and affix a negative symbol.

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