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GED Math : Area of a Quadrilateral

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Example Questions

Example Question #31 : Area Of A Quadrilateral

What is the area of a square with a perimeter of ?

Possible Answers:

$\frac{9}{16}$

$\frac{9}{8}$

$\frac{9}{2}$

$\frac{9}{4}$

Correct answer:

$\frac{9}{16}$

Explanation:

The perimeter includes the sum of the four sides of the square.

4s=3

Divide by 4 on each side.

$s=\frac{3}{4}$

Each side has a length of three fourths.

Write the formula for the area of a square.

A=s^2

Substitute the side.

$A= (\frac{3}{4})^2 = (\frac{3}{4}) (\frac{3}{4}) = \frac{9}{16}$

The area is: $\frac{9}{16}$

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Example Question #32 : Area Of A Quadrilateral

Find the area of a rectangle with a length of and a height of 4x^2 .

Possible Answers:

32 x^3

32 x^2

24x^3

16x^3

24x^2

Correct answer:

32 x^3

Explanation:

Write the formula to find the area of a rectangle.

A = LW

Substitute the dimensions.

A = (8x)(4x^2) = 32 x^3

The answer is: 32 x^3

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Example Question #33 : Area Of A Quadrilateral

What is the area of a square with a side of $3\sqrt5$ ?

Possible Answers:

Correct answer:

Explanation:

Write the area formula for a square.

A = s^2

Substitute the side length in the equation.

$A = (3\sqrt5)^2 = (3\sqrt5) (3\sqrt5) = 9(5) = 45$

The area is:

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Example Question #34 : Area Of A Quadrilateral

What is the area of a square that has a perimeter of 154.2 ?

Possible Answers:

5944.4

77.1

1486.1

1322.4

Correct answer:

1486.1

Explanation:

Start by finding the length of a side for the square by using the given perimeter.

$\text{Perimeter}=4(\text{side})$

$\text{side}=\frac{\text{Perimeter}}{4}$

For the given square,

$\text{side}=\frac{154.2}{4}=38.55$

Now, recall how to find the area of a square:

$\text{Area}=\text{side}^2$

Plug in the side length of the square to find its area.

$\text{Area}=(38.55)^2=1486.1$

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Example Question #35 : Area Of A Quadrilateral

Use the following rectangle to answer the question:

Rectangle4

Find the area.

Possible Answers:

$32\text{cm}^2$

$63\text{cm}^2$

$54\text{cm}^2$

$16\text{cm}^2$

$72\text{cm}^2$

Correct answer:

$63\text{cm}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, given the rectangle

Rectangle4

we can see the length is 9cm and the width is 7cm. So, we substitute. We get

$A = 9\text{cm} \cdot 7\text{cm}$

$A = 63\text{cm}^2$

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Example Question #36 : Area Of A Quadrilateral

Use the following square to answer the question:

Square3

Find the area.

Possible Answers:

$64\text{cm}^2$

$24\text{cm}^2$

$56\text{cm}^2$

$32\text{cm}^2$

$16\text{cm}^2$

Correct answer:

$64\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the square.

Now, given the square

Square3

we can see the width is 8cm. Because it is a square, all sides are equal. Therefore, the length is also 8cm. So, we can substitute. We get

$A = 8\text{cm} \cdot 8\text{cm}$

$A = 64\text{cm}^2$

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Example Question #371 : Geometry And Graphs

Find the area of a rectangle with a length of 15in and a width that is a third of the length.

Possible Answers:

$45\text{in}^2$

$20\text{in}^2$

$75\text{in}^2$

$30\text{in}^2$

$40\text{in}^2$

Correct answer:

$75\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 15in. We know the width is a third of the length. Therefore, the width is 5in. So, we can substitute. We get

$A = 15\text{in} \cdot 5\text{in}$

$A = 75\text{in}^2$

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Example Question #372 : Geometry And Graphs

Find the area of a square with a length of 7in.

Possible Answers:

$49\text{in}^2$

$56\text{in}^2$

$\text{There is not enough information to solve the problem.}$

$28\text{in}^2$

$64\text{in}^2$

Correct answer:

$49\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

A = x^2

where x is any side of the square. Because a square has 4 equal sides, we can use any side of the square in the formula.

Now, we know the length of the square is 7in. So, we can substitute. We get

$A = (7\text{in})^2$

$A = 49\text{in}^2$

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Example Question #373 : Geometry And Graphs

Find the area of a rectangle with a length of 3x^3 and a height of 3x-3 .

Possible Answers:

6x^3 - 6x^2

6x^4 - 6x^3

6x^3+6x-6

9x^4 - 9x^3

9x^3 - 9x^2

Correct answer:

9x^4 - 9x^3

Explanation:

Write the formula for the area of a rectangle.

$A =\textup{ Length} \times\textup{ Width}$

Substitute the dimensions.

A =3x^3(3x-3) = 9x^4 - 9x^3

The answer is: 9x^4 - 9x^3

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Example Question #374 : Geometry And Graphs

Find the area of a square with a length of $5\sqrt2$ .

Possible Answers:

150

100

Correct answer:

Explanation:

Write the formula for the area of a square.

A= s^2

Substitute the side length.

$A= (5\sqrt2)^2 = (5\sqrt2)(5\sqrt2) = 25 \cdot 2 = 50$

The answer is:

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GED Math : Area of a Quadrilateral

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #31 : Area Of A Quadrilateral

Example Question #32 : Area Of A Quadrilateral

Example Question #33 : Area Of A Quadrilateral

Example Question #34 : Area Of A Quadrilateral

Example Question #35 : Area Of A Quadrilateral

Example Question #36 : Area Of A Quadrilateral

Example Question #371 : Geometry And Graphs

Example Question #372 : Geometry And Graphs

Example Question #373 : Geometry And Graphs

Example Question #374 : Geometry And Graphs

All GED Math Resources

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