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Common Core: High School - Number and Quantity : High School: Number and Quantity

Study concepts, example questions & explanations for Common Core: High School - Number and Quantity

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All Common Core: High School - Number and Quantity Resources

6 Diagnostic Tests 49 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #21 : High School: Number And Quantity

Rewrite $31^{\frac{5}{6}}$ , in radical form.

Possible Answers:

$\sqrt[6]{\frac{31}{5}}$

$\sqrt[5]{\frac{31}{6}}$

$(\sqrt[6]{31})^5$

$(\sqrt[5]{31})^6$

Correct answer:

$(\sqrt[6]{31})^5$

Explanation:

To determine what the root is, we look at the denominator of the exponent. In this case the root is , and the numerator tells us what power we are raising the entire expression to, which is .

$31^{\frac{5}{6}}=(\sqrt[6]{31})^5$

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Example Question #22 : High School: Number And Quantity

Rewrite $79^{\frac{2}{3}}$ , in radical form.

Possible Answers:

$\sqrt[]{\frac{79}{3}}$

$(\sqrt[2]{79})^3$

$\sqrt[3]{\frac{79}{2}}$

$(\sqrt[3]{79})^2$

Correct answer:

$(\sqrt[3]{79})^2$

Explanation:

To determine what the root is, we look at the denominator of the exponent. In this case the root is , and the numerator tells us what power we are raising the entire expression to, which is .

$79^{\frac{2}{3}}=(\sqrt[3]{79})^2$

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Example Question #23 : High School: Number And Quantity

Rewrite $134^{\frac{1}{2}}$ , in radical form.

Possible Answers:

$\sqrt{134}$

$134^{\frac{1}{2}}$

$\sqrt[134]{2}$

$\sqrt[]{\frac{134}{2}}$

Correct answer:

$\sqrt{134}$

Explanation:

To determine what the root is, we look at the denominator of the exponent. In this case the root is , so we will write it in the following way.

$134^{\frac{1}{2}}=\sqrt[]{134}$

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Example Question #1 : Quantities*

Evaluate: $169^{\frac{3}{2}}$

Possible Answers:

2197

235.5

169

Correct answer:

2197

Explanation:

To evaluate this, let's rewrite the problem.

$169^{\frac{3}{2}}=(\sqrt[]{64})^3$

Now lets break down the square root.

$(\sqrt[]{169})^3=(\sqrt[]{13\cdot13})^3=(\sqrt[]{13^2})^3=13^3=2197$

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Example Question #1 : Use, Understand, And Interpret Units: Ccss.Math.Content.Hsn Q.A.1

If the temperature is $33 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

92.4

59.4

91.4

Correct answer:

91.4

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

F = 1.8 C + 32

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ .

$F = 1.8 \cdot 33 +32$

F = 59.4 +32

F = 91.4

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Example Question #2 : Quantities*

If the temperature is $43 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

77.4

109.4

110.4

Correct answer:

109.4

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

F = 1.8 C + 32

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ .

$F = 1.8 \cdot 43 +32$

F = 77.4 +32

F = 109.4

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Example Question #26 : High School: Number And Quantity

If the temperature is $63 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

113.4

146.4

145.4

Correct answer:

145.4

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

F = 1.8 C + 32

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ .

$F = 1.8 \cdot 63 +32$

F = 113.4 +32

F = 145.4

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Example Question #27 : High School: Number And Quantity

If the temperature is $67 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

120.6

153.6

152.6

Correct answer:

152.6

Explanation:

F = 120.60 +32

F = 152.6

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Example Question #28 : High School: Number And Quantity

If the temperature is $30 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

86.0

87.0

54.0

Correct answer:

86.0

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

F = 1.8 C + 32

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ .

$F = 1.8 \cdot 30 +32$

F = 54.0 +32

F = 86.0

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Example Question #29 : High School: Number And Quantity

If the temperature is $58 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

137.4

104.4

136.4

Correct answer:

136.4

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

F = 1.8 C + 32

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ .

$F = 1.8 \cdot 58 +32$

F = 104.4 +32

F = 136.4

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All Common Core: High School - Number and Quantity Resources

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Common Core: High School - Number and Quantity : High School: Number and Quantity

Study concepts, example questions & explanations for Common Core: High School - Number and Quantity

All Common Core: High School - Number and Quantity Resources

Example Questions

Example Question #21 : High School: Number And Quantity

Example Question #22 : High School: Number And Quantity

Example Question #23 : High School: Number And Quantity

Example Question #1 : Quantities*

Example Question #1 : Use, Understand, And Interpret Units: Ccss.Math.Content.Hsn Q.A.1

Example Question #2 : Quantities*

Example Question #26 : High School: Number And Quantity

Example Question #27 : High School: Number And Quantity

Example Question #28 : High School: Number And Quantity

Example Question #29 : High School: Number And Quantity

All Common Core: High School - Number and Quantity Resources

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