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Common Core: 6th Grade Math : Fluently Divide Multi-Digit Numbers: CCSS.Math.Content.6.NS.B.2

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Example Questions

Example Question #1 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 93\\ 3{\overline{\smash{)}279}}\\ -\ 27 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ 93\\ 3{\overline{\smash{)}279}}\\ -\ 27 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

Possible Answers:

$3\times 279$ $\displaystyle 3\times 279$

$3\times 90$ $\displaystyle 3\times 90$

$3\times 93$ $\displaystyle 3\times 93$

$3\times 99$ $\displaystyle 3\times 99$

$3\times 3$ $\displaystyle 3\times 3$

Correct answer:

$3\times 93$ $\displaystyle 3\times 93$

Explanation:

The computation shows that $279\div3=93$ $\displaystyle 279\div3=93$ with a remainder of $\displaystyle 0$.

$\frac{\begin{array}[b]{r} \ {\color{Green} 93}\\ {\color{Green} 3}{\overline{\smash{)}279}}\\ -\ 27 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 93}\\ {\color{Green} 3}{\overline{\smash{)}279}}\\ -\ 27 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

So it must be that:

$3\times93=279+0$ $\displaystyle 3\times93=279+0$

Simplify.

$3\times93=279$ $\displaystyle 3\times93=279$

The correct answer is $3\times 93$ $\displaystyle 3\times 93$

Report an Error

Example Question #2 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 72\\ 2{\overline{\smash{)}144}}\\ -\ 14 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ 72\\ 2{\overline{\smash{)}144}}\\ -\ 14 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

Possible Answers:

$2\times 72$ $\displaystyle 2\times 72$

$2\times 73$ $\displaystyle 2\times 73$

$2\times 70$ $\displaystyle 2\times 70$

$2\times 12$ $\displaystyle 2\times 12$

$2\times 92$ $\displaystyle 2\times 92$

Correct answer:

$2\times 72$ $\displaystyle 2\times 72$

Explanation:

The computation shows that $144\div2=72$ $\displaystyle 144\div2=72$ with a remainder of $\displaystyle 0$.

$\frac{\begin{array}[b]{r} \ {\color{Green} 72}\\ {\color{Green} 2}{\overline{\smash{)}144}}\\ -\ 14 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 72}\\ {\color{Green} 2}{\overline{\smash{)}144}}\\ -\ 14 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

So it must be that:

$2\times72=144+0$ $\displaystyle 2\times72=144+0$

Simplify.

$2\times72=144$ $\displaystyle 2\times72=144$

The correct answer is $2\times 72$ $\displaystyle 2\times 72$

Report an Error

Example Question #1 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 61\\ 4{\overline{\smash{)}244}}\\ -\ 24 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ 61\\ 4{\overline{\smash{)}244}}\\ -\ 24 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

Possible Answers:

$4\times 46$ $\displaystyle 4\times 46$

$4\times 61$ $\displaystyle 4\times 61$

$4\times 60$ $\displaystyle 4\times 60$

$4\times 18$ $\displaystyle 4\times 18$

$4\times 64$ $\displaystyle 4\times 64$

Correct answer:

$4\times 61$ $\displaystyle 4\times 61$

Explanation:

The computation shows that $244\div4=61$ $\displaystyle 244\div4=61$ with a remainder of $\displaystyle 0$.

$\frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 4}{\overline{\smash{)}244}}\\ -\ 24 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 4}{\overline{\smash{)}244}}\\ -\ 24 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

So it must be that:

$4\times61=244+0$ $\displaystyle 4\times61=244+0$

Simplify.

$4\times61=244$ $\displaystyle 4\times61=244$

The correct answer is $4\times 61$ $\displaystyle 4\times 61$

Report an Error

Example Question #2 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 11\\ 11{\overline{\smash{)}121}}\\ -\ 11 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}01{1\ \ }\\ -\ \ \ 11\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ 11\\ 11{\overline{\smash{)}121}}\\ -\ 11 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}01{1\ \ }\\ -\ \ \ 11\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

Possible Answers:

$12\times 12$ $\displaystyle 12\times 12$

$11\times 11$ $\displaystyle 11\times 11$

$11\times 21$ $\displaystyle 11\times 21$

$11\times 10$ $\displaystyle 11\times 10$

$11\times 13$ $\displaystyle 11\times 13$

Correct answer:

$11\times 11$ $\displaystyle 11\times 11$

Explanation:

The computation shows that $121\div11=11$ $\displaystyle 121\div11=11$ with a remainder of $\displaystyle 0$.

$\frac{\begin{array}[b]{r} \ {\color{Green} 11}\\ {\color{Green} 11}{\overline{\smash{)}121}}\\ -\ 11 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}01{ 1\ \ }\\ -\ \ \ 11\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 11}\\ {\color{Green} 11}{\overline{\smash{)}121}}\\ -\ 11 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}01{ 1\ \ }\\ -\ \ \ 11\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

So it must be that:

$11\times11=121+0$ $\displaystyle 11\times11=121+0$

Simplify.

$11\times11=121$ $\displaystyle 11\times11=121$

The correct answer is $11\times 11$ $\displaystyle 11\times 11$

Report an Error

Example Question #392 : How To Divide

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 54\\ 2{\overline{\smash{)}108}}\\ -\ 10 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{8\ \ }\\ -\ \ \ 8\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ 54\\ 2{\overline{\smash{)}108}}\\ -\ 10 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{8\ \ }\\ -\ \ \ 8\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

Possible Answers:

$2\times 46$ $\displaystyle 2\times 46$

$2\times 64$ $\displaystyle 2\times 64$

$2\times 56$ $\displaystyle 2\times 56$

$4\times 44$ $\displaystyle 4\times 44$

$2\times 54$ $\displaystyle 2\times 54$

Correct answer:

$2\times 54$ $\displaystyle 2\times 54$

Explanation:

The computation shows that $108\div2=54$ $\displaystyle 108\div2=54$ with a remainder of $\displaystyle 0$.

$\frac{\begin{array}[b]{r} \ {\color{Green} 54}\\ {\color{Green} 2}{\overline{\smash{)}108}}\\ -\ 10 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 8\ \ }\\ -\ \ \ 8\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 54}\\ {\color{Green} 2}{\overline{\smash{)}108}}\\ -\ 10 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 8\ \ }\\ -\ \ \ 8\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

So it must be that:

$2\times54=108+0$ $\displaystyle 2\times54=108+0$

Simplify.

$2\times54=108$ $\displaystyle 2\times54=108$

The correct answer is $2\times 54$ $\displaystyle 2\times 54$

Report an Error

Example Question #101 : Grade 6

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 61\\ 2{\overline{\smash{)}122}}\\ -\ 12 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{2\ \ }\\ -\ \ \ 2\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ 61\\ 2{\overline{\smash{)}122}}\\ -\ 12 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{2\ \ }\\ -\ \ \ 2\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

Possible Answers:

$2\times 61$ $\displaystyle 2\times 61$

$2\times 76$ $\displaystyle 2\times 76$

$2\times 68$ $\displaystyle 2\times 68$

$3\times 36$ $\displaystyle 3\times 36$

$2\times 63$ $\displaystyle 2\times 63$

Correct answer:

$2\times 61$ $\displaystyle 2\times 61$

Explanation:

The computation shows that $122\div2=61$ $\displaystyle 122\div2=61$ with a remainder of $\displaystyle 0$.

$\frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 2}{\overline{\smash{)}122}}\\ -\ 12 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 2\ \ }\\ -\ \ \ 2\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 2}{\overline{\smash{)}122}}\\ -\ 12 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 2\ \ }\\ -\ \ \ 2\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

So it must be that:

$2\times61=122+0$ $\displaystyle 2\times61=122+0$

Simplify.

$2\times61=122$ $\displaystyle 2\times61=122$

The correct answer is $2\times 61$ $\displaystyle 2\times 61$

Report an Error

Example Question #102 : Grade 6

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 51\\ 3{\overline{\smash{)}153}}\\ -\ 15 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ 51\\ 3{\overline{\smash{)}153}}\\ -\ 15 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

Possible Answers:

$3\times 53$ $\displaystyle 3\times 53$

$3\times 61$ $\displaystyle 3\times 61$

$3\times 36$ $\displaystyle 3\times 36$

$3\times 51$ $\displaystyle 3\times 51$

$3\times 35$ $\displaystyle 3\times 35$

Correct answer:

$3\times 51$ $\displaystyle 3\times 51$

Explanation:

The computation shows that $153\div3=61$ $\displaystyle 153\div3=61$ with a remainder of $\displaystyle 0$.

$\frac{\begin{array}[b]{r} \ {\color{Green} 51}\\ {\color{Green} 3}{\overline{\smash{)}153}}\\ -\ 15 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 51}\\ {\color{Green} 3}{\overline{\smash{)}153}}\\ -\ 15 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

So it must be that:

$3\times51=153+0$ $\displaystyle 3\times51=153+0$

Simplify.

$3\times51=153$ $\displaystyle 3\times51=153$

The correct answer is $3\times 51$ $\displaystyle 3\times 51$

Report an Error

Example Question #101 : Grade 6

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 61\\ 3{\overline{\smash{)}183}}\\ -\ 18 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ 61\\ 3{\overline{\smash{)}183}}\\ -\ 18 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

Possible Answers:

$3\times 61$ $\displaystyle 3\times 61$

$3\times 68$ $\displaystyle 3\times 68$

$3\times 42$ $\displaystyle 3\times 42$

$3\times 36$ $\displaystyle 3\times 36$

$3\times 63$ $\displaystyle 3\times 63$

Correct answer:

$3\times 61$ $\displaystyle 3\times 61$

Explanation:

The computation shows that $183\div3=61$ $\displaystyle 183\div3=61$ with a remainder of $\displaystyle 0$.

$\frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 3}{\overline{\smash{)}183}}\\ -\ 18 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 3}{\overline{\smash{)}183}}\\ -\ 18 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

So it must be that:

$3\times61=183+0$ $\displaystyle 3\times61=183+0$

Simplify.

$3\times61=183$ $\displaystyle 3\times61=183$

The correct answer is $3\times 61$ $\displaystyle 3\times 61$

Report an Error

Example Question #102 : Grade 6

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 63\\ 3{\overline{\smash{)}189}}\\ -\ 18 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ 63\\ 3{\overline{\smash{)}189}}\\ -\ 18 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

Possible Answers:

$3\times 69$ $\displaystyle 3\times 69$

$3\times 83$ $\displaystyle 3\times 83$

$3\times 72$ $\displaystyle 3\times 72$

$3\times 68$ $\displaystyle 3\times 68$

$3\times 63$ $\displaystyle 3\times 63$

Correct answer:

$3\times 63$ $\displaystyle 3\times 63$

Explanation:

The computation shows that $189\div3=63$ $\displaystyle 189\div3=63$ with a remainder of $\displaystyle 0$.

$\frac{\begin{array}[b]{r} \ {\color{Green} 63}\\ {\color{Green} 3}{\overline{\smash{)}189}}\\ -\ 18 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 63}\\ {\color{Green} 3}{\overline{\smash{)}189}}\\ -\ 18 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

So it must be that:

$3\times63=189+0$ $\displaystyle 3\times63=189+0$

Simplify.

$3\times63=189$ $\displaystyle 3\times63=189$

The correct answer is $3\times 63$ $\displaystyle 3\times 63$

Report an Error

Example Question #401 : How To Divide

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 91\\ 3{\overline{\smash{)}273}}\\ -\ 27 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ 91\\ 3{\overline{\smash{)}273}}\\ -\ 27 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

Possible Answers:

$3\times 79$ $\displaystyle 3\times 79$

$3\times 97$ $\displaystyle 3\times 97$

$3\times 89$ $\displaystyle 3\times 89$

$3\times 91$ $\displaystyle 3\times 91$

$3\times 93$ $\displaystyle 3\times 93$

Correct answer:

$3\times 91$ $\displaystyle 3\times 91$

Explanation:

The computation shows that $273\div3=91$ $\displaystyle 273\div3=91$ with a remainder of $\displaystyle 0$.

$\frac{\begin{array}[b]{r} \ {\color{Green} 91}\\ {\color{Green} 3}{\overline{\smash{)}273}}\\ -\ 27 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$ $\displaystyle \frac{\begin{array}[b]{r} \ {\color{Green} 91}\\ {\color{Green} 3}{\overline{\smash{)}273}}\\ -\ 27 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 3\ \ }\\ -\ \ \ 3\ \ \end{array}}{ \ \ \ \space} }$

$\displaystyle 0$

So it must be that:

$3\times91=273+0$ $\displaystyle 3\times91=273+0$

Simplify.

$3\times91=273$ $\displaystyle 3\times91=273$

The correct answer is $3\times 91$ $\displaystyle 3\times 91$

Report an Error

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Common Core: 6th Grade Math : Fluently Divide Multi-Digit Numbers: CCSS.Math.Content.6.NS.B.2

Study concepts, example questions & explanations for Common Core: 6th Grade Math

All Common Core: 6th Grade Math Resources

Example Questions

Example Question #1 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #2 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #1 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #2 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #392 : How To Divide

Example Question #101 : Grade 6

Example Question #102 : Grade 6

Example Question #101 : Grade 6

Example Question #102 : Grade 6

Example Question #401 : How To Divide

All Common Core: 6th Grade Math Resources

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