When we have a set of something that we are splitting up into groups, we divide. In this case, we are splitting up cookies into containers. We have $\displaystyle 50$ cookies that we are dividing into containers. Each container holds $\displaystyle 4$ cookies, so we divide $\displaystyle 50$ by $\displaystyle 4$ to find out how many containers we can fill. We will let $\displaystyle c$ represent the number of containers that we can fill. 

$\displaystyle 50\div4=c$

 $\displaystyle \frac{\begin{array}[b]{r} \ 12\\ 4{\overline{\smash{)}50}}\\ -\ 4\smash{\color{Red}\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}1{\color{Red} 0\ \ }\\ -\ \ \ 8\ \ \end{array}}{ \ \ \space} }$

                     $\displaystyle 2$

We drop the remainder of $\displaystyle 2$ because the question asks how many containers we can fill completely. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are splitting up cookies into containers. We have $\displaystyle 62$ cookies that we are dividing into containers. Each container holds $\displaystyle 5$ cookies, so we divide $\displaystyle 62$ by $\displaystyle 5$ to find out how many containers we can fill. We will let $\displaystyle c$ represent the number of containers that we can fill. 

$\displaystyle 62\div5=c$

$\displaystyle \frac{\begin{array}[b]{r} \ 12\\ 5{\overline{\smash{)}62}}\\ -\ 5\smash{\color{Red}\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}1{\color{Red} 2\ \ }\\ -\ \ \ 10\ \ \end{array}}{ \ \ \space} }$

                     $\displaystyle 2$

We drop the remainder of $\displaystyle 2$ because the question asks how many containers we can fill completely. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are splitting up cookies into containers. We have $\displaystyle 76$ cookies that we are dividing into containers. Each container holds $\displaystyle 6$ cookies, so we divide $\displaystyle 76$ by $\displaystyle 6$ to find out how many containers we can fill. We will let $\displaystyle c$ represent the number of containers that we can fill. 

$\displaystyle 76\div6=c$

$\displaystyle \frac{\begin{array}[b]{r} \ 12\\ 6{\overline{\smash{)}76}}\\ -\ 6\smash{\color{Red}\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}1{\color{Red} 6\ \ }\\ -\ \ \ 12\ \ \end{array}}{ \ \ \space} }$

                     $\displaystyle 4$

We drop the remainder of $\displaystyle 4$ because the question asks how many containers we can fill completely. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are splitting up cookies into containers. We have $\displaystyle 96$ cookies that we are dividing into containers. Each container holds $\displaystyle 9$ cookies, so we divide $\displaystyle 96$ by $\displaystyle 9$ to find out how many containers we can fill. We will let $\displaystyle c$ represent the number of containers that we can fill. 

$\displaystyle 96\div9=c$

$\displaystyle \frac{\begin{array}[b]{r} \ 10\\ 9{\overline{\smash{)}96}}\\ -\ 9\smash{\color{Red}\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}0{\color{Red} 6\ \ }\\ -\ \ \ 0\ \ \end{array}}{ \ \ \ \space} }$

                   $\displaystyle 6$

We drop the remainder of $\displaystyle 6$ because the question asks how many containers we can fill completely. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let $\displaystyle c$ represent the number of cars they will need.

$\displaystyle 31\div5=c$

$\displaystyle \frac{\begin{array}[b]{r} \ 6\\ 5{\overline{\smash{)}31}}\\ -\ 30\end{array}}{ \ \ \ \space}$

           $\displaystyle 1$

Our answer is $\displaystyle 6$ with a remainder of $\displaystyle 1$. This means that they will have $\displaystyle 6$ full cars of $\displaystyle 5$ people, but there is $\displaystyle 1$ person left over. So they need $\displaystyle 7$ cars in order for every student to be in a car. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let $\displaystyle c$ represent the number of cars they will need.

$\displaystyle 63\div5=c$

$\displaystyle \frac{\begin{array}[b]{r} \ 12\\ 5{\overline{\smash{)}63}}\\ -\ 60\end{array}}{ \ \ \ \ \ 3}$

Our answer is $\displaystyle 12$ with a remainder of $\displaystyle 3$. This means that they will have $\displaystyle 12$ full cars of $\displaystyle 5$ people, but there are $\displaystyle 3$ people left over. So they need $\displaystyle 13$ cars in order for every student to be in a car. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let $\displaystyle c$ represent the number of cars they will need.

$\displaystyle 26\div5=c$

$\displaystyle \frac{\begin{array}[b]{r} \ 5\\ 5{\overline{\smash{)}26}}\\ -\ 25\end{array}}{ \ \ \ \ \ 1}$

Our answer is $\displaystyle 5$ with a remainder of $\displaystyle 1$. This means that they will have $\displaystyle 5$ full cars of $\displaystyle 5$ people, but there is $\displaystyle 1$ person left over. So they need $\displaystyle 6$ cars in order for every student to be in a car. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let $\displaystyle c$ represent the number of cars they will need.

$\displaystyle 36\div5=c$

$\displaystyle \frac{\begin{array}[b]{r} \ 7\\ 5{\overline{\smash{)}36}}\\ -\ 35\end{array}}{ \ \ \ \ \ 1}$

Our answer is $\displaystyle 7$ with a remainder of $\displaystyle 1$. This means that they will have $\displaystyle 7$ full cars of $\displaystyle 5$ people, but there is $\displaystyle 1$ person left over. So they need $\displaystyle 8$ cars in order for every student to be in a car. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let $\displaystyle c$ represent the number of cars they will need.

$\displaystyle 46\div4=c$

$\displaystyle \frac{\begin{array}[b]{r} \ 11\\ 4{\overline{\smash{)}46}}\\ -\ 44\end{array}}{ \ \ \ \ \ 2}$     

Our answer is $\displaystyle 11$ with a remainder of $\displaystyle 2$. This means that they will have $\displaystyle 11$ full cars of $\displaystyle 4$ people, but there are $\displaystyle 2$ people left over. So they need $\displaystyle 12$ cars in order for every student to be in a car. 

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let $\displaystyle c$ represent the number of cars they will need.

$\displaystyle 18\div4=c$

$\displaystyle \frac{\begin{array}[b]{r} \ 4\\ 4{\overline{\smash{)}18}}\\ -\ 16\end{array}}{ \ \ \ \ \ 2}$     

Our answer is $\displaystyle 4$ with a remainder of $\displaystyle 2$. This means that they will have $\displaystyle 4$ full cars of $\displaystyle 4$ people, but there are $\displaystyle 2$ people left over. So they need $\displaystyle 5$ cars in order for every student to be in a car.