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Common Core: 2nd Grade Math : Solve Word Problems Involving Money: CCSS.Math.Content.2.MD.C.8

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

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All Common Core: 2nd Grade Math Resources

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Example Questions

Example Question #441 : Operations

If I have $\displaystyle 1$ dollar bill, $\displaystyle 5$ pennies, and $\displaystyle 3$ quarters, how much money do I have?

Possible Answers:

$\$1.80$ $\displaystyle \$1.80$

$\$1.90$ $\displaystyle \$1.90$

$\$1.85$ $\displaystyle \$1.85$

$\$1.08$ $\displaystyle \$1.08$

$\$1.40$ $\displaystyle \$1.40$

Correct answer:

$\$1.80$ $\displaystyle \$1.80$

Explanation:

Each dollar bill is worth $\$1$ $\displaystyle \$1$ , each penny is worth $1\cent$ $\displaystyle 1\cent$ and each quarter is worth $25\cent$ $\displaystyle 25\cent$ .

We have $\displaystyle 1$ dollar bill, $\displaystyle 5$ pennies, and $\displaystyle 3$ quarters.

$\$1$ $\displaystyle \$1$ $\frac{\begin{array}[b]{r}1\cent\\ 1\cent\\1\cent\\1\cent\\+\ 1\cent\end{array}}{ \ \ \ \space 5\cent}$ $\displaystyle \frac{\begin{array}[b]{r}1\cent\\ 1\cent\\1\cent\\1\cent\\+\ 1\cent\end{array}}{ \ \ \ \space 5\cent}$ $\frac{\begin{array}[b]{r}25\cent\\25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 75\cent}$ $\displaystyle \frac{\begin{array}[b]{r}25\cent\\25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 75\cent}$

When we add dollars and cents, we add dollars to dollars and cents to cents.

$\frac{\begin{array}[b]{r}5\cent\\ +\ 75\cent\end{array}}{ \ \ \ \space 80\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\ +\ 75\cent\end{array}}{ \ \ \ \space 80\cent}$

We have $\$1$ $\displaystyle \$1$ and $80\cent$ $\displaystyle 80\cent$ which is written as $\$1.80$ $\displaystyle \$1.80$

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Example Question #22 : Solve Word Problems Involving Money: Ccss.Math.Content.2.Md.C.8

If I have $\displaystyle 3$ dollar bills, $\displaystyle 2$ nickels, and $\displaystyle 3$ dimes, how much money do I have?

Possible Answers:

$\$3.25$ $\displaystyle \$3.25$

$\$3.45$ $\displaystyle \$3.45$

$\$3.35$ $\displaystyle \$3.35$

$\$3.30$ $\displaystyle \$3.30$

$\$3.40$ $\displaystyle \$3.40$

Correct answer:

$\$3.40$ $\displaystyle \$3.40$

Explanation:

Each dollar bill is worth $\$1$ $\displaystyle \$1$ , each nickel is worth $5\cent$ $\displaystyle 5\cent$ and each dime is worth $10\cent$ $\displaystyle 10\cent$ .

We have $\displaystyle 3$ dollar bills, $\displaystyle 2$ nickels, and $\displaystyle 3$ dimes.

$\frac{\begin{array}[b]{r}\$1\\ \ \$1\\ +\$1\end{array}}{ \ \ \space\$3}$ $\displaystyle \frac{\begin{array}[b]{r}\$1\\ \ \$1\\ +\$1\end{array}}{ \ \ \space\$3}$ $\frac{\begin{array}[b]{r}5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 10\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 10\cent}$ $\frac{\begin{array}[b]{r}10\cent\\10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 30\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 30\cent}$

When we add dollars and cents, we add dollars to dollars and cents to cents.

$\frac{\begin{array}[b]{r}10\cent\\ +\ 30\cent\end{array}}{ \ \ \ \space 40\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\ +\ 30\cent\end{array}}{ \ \ \ \space 40\cent}$

We have $\$3$ $\displaystyle \$3$ and $40\cent$ $\displaystyle 40\cent$ which is written as $\$3.40$ $\displaystyle \$3.40$

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Example Question #311 : Measurement & Data

If I have $\displaystyle 1$ dollar bill, $\displaystyle 4$ nickels, and $\displaystyle 5$ dimes, how much money do I have?

Possible Answers:

$\$1.72$ $\displaystyle \$1.72$

$\$1.43$ $\displaystyle \$1.43$

$\$1.45$ $\displaystyle \$1.45$

$\$1.70$ $\displaystyle \$1.70$

$\$1.77$ $\displaystyle \$1.77$

Correct answer:

$\$1.70$ $\displaystyle \$1.70$

Explanation:

Each dollar bill is worth $\$1$ $\displaystyle \$1$ , each nickel is worth $5\cent$ $\displaystyle 5\cent$ and each dime is worth $10\cent$ $\displaystyle 10\cent$ .

We have $\displaystyle 1$ dollar bill, $\displaystyle 4$ nickels, and $\displaystyle 5$ dimes.

$\$1$ $\displaystyle \$1$ $\frac{\begin{array}[b]{r}5\cent\\5\cent\\5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 20\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\5\cent\\5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 20\cent}$ $\frac{\begin{array}[b]{r}10\cent\\10\cent\\10\cent\\10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \ \space 50\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\10\cent\\10\cent\\10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \ \space 50\cent}$

When we add dollars and cents, we add dollars to dollars and cents to cents.

$\frac{\begin{array}[b]{r}20\cent\\ +\ 50\cent\end{array}}{ \ \ \space 70\cent}$ $\displaystyle \frac{\begin{array}[b]{r}20\cent\\ +\ 50\cent\end{array}}{ \ \ \space 70\cent}$

We have $\$1$ $\displaystyle \$1$ and $70\cent$ $\displaystyle 70\cent$ which is written as $\$1.70$ $\displaystyle \$1.70$

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Example Question #2542 : Numbers And Operations

If I have $\displaystyle 3$ quarters and $\displaystyle 5$ pennies, how many cents do I have?

Possible Answers:

$75\cent$ $\displaystyle 75\cent$

$85\cent$ $\displaystyle 85\cent$

$70\cent$ $\displaystyle 70\cent$

$80\cent$ $\displaystyle 80\cent$

$65\cent$ $\displaystyle 65\cent$

Correct answer:

$80\cent$ $\displaystyle 80\cent$

Explanation:

Each quarter is worth $25\cent$ $\displaystyle 25\cent$ and each penny is worth $1\cent$ $\displaystyle 1\cent$ .

We have three quarters and five pennies.

$\frac{\begin{array}[b]{r}25\cent\\ 25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 75\cent}$ $\displaystyle \frac{\begin{array}[b]{r}25\cent\\ 25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 75\cent}$ $\frac{\begin{array}[b]{r}1\cent\\ \ 1\cent\\ 1\cent\\ \ 1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 5\cent}$ $\displaystyle \frac{\begin{array}[b]{r}1\cent\\ \ 1\cent\\ 1\cent\\ \ 1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 5\cent}$

$\frac{\begin{array}[b]{r}75\cent\\ +\ 5\cent\end{array}}{ \ \ \space 80\cent}$ $\displaystyle \frac{\begin{array}[b]{r}75\cent\\ +\ 5\cent\end{array}}{ \ \ \space 80\cent}$

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Example Question #451 : Isee Lower Level (Grades 5 6) Quantitative Reasoning

If I have $\displaystyle 5$ dimes and $\displaystyle 1$ nickel, how much money do I have?

Possible Answers:

$65\cent$ $\displaystyle 65\cent$

$60\cent$ $\displaystyle 60\cent$

$78\cent$ $\displaystyle 78\cent$

$55\cent$ $\displaystyle 55\cent$

$62\cent$ $\displaystyle 62\cent$

Correct answer:

$55\cent$ $\displaystyle 55\cent$

Explanation:

Each dime is worth $10\cent$ $\displaystyle 10\cent$ and each nickel is worth $5\cent$ $\displaystyle 5\cent$ .

We have five dimes and one nickel.

$\frac{\begin{array}[b]{r}10\cent\\ \ 10\cent\\ 10\cent\\ 10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 50\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\ \ 10\cent\\ 10\cent\\ 10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 50\cent}$ $5\cent$ $\displaystyle 5\cent$

$\frac{\begin{array}[b]{r}50\cent\\ +\ 5\cent\end{array}}{ \ \ \space 55\cent}$ $\displaystyle \frac{\begin{array}[b]{r}50\cent\\ +\ 5\cent\end{array}}{ \ \ \space 55\cent}$

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Example Question #452 : Isee Lower Level (Grades 5 6) Quantitative Reasoning

If I have $\displaystyle 3$ quarters and $\displaystyle 2$ pennies, how many cents do I have?

Possible Answers:

$74\cent$ $\displaystyle 74\cent$

$68\cent$ $\displaystyle 68\cent$

$77\cent$ $\displaystyle 77\cent$

$65\cent$ $\displaystyle 65\cent$

$79\cent$ $\displaystyle 79\cent$

Correct answer:

$77\cent$ $\displaystyle 77\cent$

Explanation:

Each quarter is worth $25\cent$ $\displaystyle 25\cent$ and each penny is worth $1\cent$ $\displaystyle 1\cent$ .

We have three quarters and two pennies.

$\frac{\begin{array}[b]{r}25\cent\\ 25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 75\cent}$ $\displaystyle \frac{\begin{array}[b]{r}25\cent\\ 25\cent\\ +\ 25\cent\end{array}}{ \ \ \ \space 75\cent}$ $\frac{\begin{array}[b]{r}1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 2\cent}$ $\displaystyle \frac{\begin{array}[b]{r}1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 2\cent}$

$\frac{\begin{array}[b]{r}75\cent\\ +\ 2\cent\end{array}}{ \ \ \space 77\cent}$ $\displaystyle \frac{\begin{array}[b]{r}75\cent\\ +\ 2\cent\end{array}}{ \ \ \space 77\cent}$

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Example Question #2543 : Numbers And Operations

If I have $\displaystyle 5$ nickels and $\displaystyle 3$ dimes, how many cents do I have?

Possible Answers:

$53\cent$ $\displaystyle 53\cent$

$55\cent$ $\displaystyle 55\cent$

$80\cent$ $\displaystyle 80\cent$

$63\cent$ $\displaystyle 63\cent$

$74\cent$ $\displaystyle 74\cent$

Correct answer:

$55\cent$ $\displaystyle 55\cent$

Explanation:

Each nickel is worth $5\cent$ $\displaystyle 5\cent$ and each dime is worth $10\cent$ $\displaystyle 10\cent$ .

We have five nickels and three dimes.

$\frac{\begin{array}[b]{r}5\cent\\ 5\cent\\ \ 5\cent\\5\cent\\ +\ 5\cent\end{array}}{ \ \ \ \space 25\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\ 5\cent\\ \ 5\cent\\5\cent\\ +\ 5\cent\end{array}}{ \ \ \ \space 25\cent}$ $\frac{\begin{array}[b]{r}10\cent\\ \ 10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 30\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\ \ 10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 30\cent}$

$\frac{\begin{array}[b]{r}25\cent\\ +\ 30\cent\end{array}}{ \ \ \ \space 55\cent}$ $\displaystyle \frac{\begin{array}[b]{r}25\cent\\ +\ 30\cent\end{array}}{ \ \ \ \space 55\cent}$

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Example Question #454 : Isee Lower Level (Grades 5 6) Quantitative Reasoning

If I have $\displaystyle 1$ quarter and $\displaystyle 3$ pennies, how many cents do I have?

Possible Answers:

$22\cent$ $\displaystyle 22\cent$

$38\cent$ $\displaystyle 38\cent$

$30\cent$ $\displaystyle 30\cent$

$25\cent$ $\displaystyle 25\cent$

$28\cent$ $\displaystyle 28\cent$

Correct answer:

$28\cent$ $\displaystyle 28\cent$

Explanation:

Each quarter is worth $25\cent$ $\displaystyle 25\cent$ and each penny is worth $1\cent$ $\displaystyle 1\cent$ .

We have one quarters and three pennies.

$25\cent$ $\displaystyle 25\cent$ $\frac{\begin{array}[b]{r}1\cent\\ \ 1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 3\cent}$ $\displaystyle \frac{\begin{array}[b]{r}1\cent\\ \ 1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 3\cent}$

$\frac{\begin{array}[b]{r}25\cent\\ +\ 3\cent\end{array}}{ \ \ \space 28\cent}$ $\displaystyle \frac{\begin{array}[b]{r}25\cent\\ +\ 3\cent\end{array}}{ \ \ \space 28\cent}$

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Example Question #2541 : Numbers And Operations

If I have $\displaystyle 3$ dimes and $\displaystyle 2$ nickels, how many cents do I have?

Possible Answers:

$10\cent$ $\displaystyle 10\cent$

$20\cent$ $\displaystyle 20\cent$

$40\cent$ $\displaystyle 40\cent$

$5\cent$ $\displaystyle 5\cent$

$30\cent$ $\displaystyle 30\cent$

Correct answer:

$40\cent$ $\displaystyle 40\cent$

Explanation:

Each dime is worth $10\cent$ $\displaystyle 10\cent$ and each nickel is worth $5\cent$ $\displaystyle 5\cent$ .

We have three dimes and two nickels.

$\frac{\begin{array}[b]{r}10\cent\\10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 30\cent}$ $\displaystyle \frac{\begin{array}[b]{r}10\cent\\10\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 30\cent}$ $\frac{\begin{array}[b]{r}5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 10\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 10\cent}$

$\frac{\begin{array}[b]{r}30\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 40\cent}$ $\displaystyle \frac{\begin{array}[b]{r}30\cent\\ +\ 10\cent\end{array}}{ \ \ \ \space 40\cent}$

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Example Question #22 : Solve Word Problems Involving Money: Ccss.Math.Content.2.Md.C.8

If I have $\displaystyle 7$ pennies and $\displaystyle 4$ nickels, how many cents do I have?

Possible Answers:

$37\cent$ $\displaystyle 37\cent$

$32\cent$ $\displaystyle 32\cent$

$27\cent$ $\displaystyle 27\cent$

$35\cent$ $\displaystyle 35\cent$

$29\cent$ $\displaystyle 29\cent$

Correct answer:

$27\cent$ $\displaystyle 27\cent$

Explanation:

Each penny is worth $1\cent$ $\displaystyle 1\cent$ and each nickel is worth $5\cent.$ $\displaystyle 5\cent.$

We have seven pennies and four nickels.

$\frac{\begin{array}[b]{r}1\cent\\1\cent\\ 1\cent\\ 1\cent\\ \ 1\cent\\ 1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 7\cent}$ $\displaystyle \frac{\begin{array}[b]{r}1\cent\\1\cent\\ 1\cent\\ 1\cent\\ \ 1\cent\\ 1\cent\\ +\ 1\cent\end{array}}{ \ \ \ \space 7\cent}$ $\frac{\begin{array}[b]{r}5\cent\\ \ 5\cent\\ 5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 20\cent}$ $\displaystyle \frac{\begin{array}[b]{r}5\cent\\ \ 5\cent\\ 5\cent\\ +\ 5\cent\end{array}}{ \ \ \space 20\cent}$

$\frac{\begin{array}[b]{r}7\cent\\ +\ 20\cent\end{array}}{ \ \ \ \space 27\cent}$ $\displaystyle \frac{\begin{array}[b]{r}7\cent\\ +\ 20\cent\end{array}}{ \ \ \ \space 27\cent}$

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Common Core: 2nd Grade Math : Solve Word Problems Involving Money: CCSS.Math.Content.2.MD.C.8

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

All Common Core: 2nd Grade Math Resources

Example Questions

Example Question #441 : Operations

Example Question #22 : Solve Word Problems Involving Money: Ccss.Math.Content.2.Md.C.8

Example Question #311 : Measurement & Data

Example Question #2542 : Numbers And Operations

Example Question #451 : Isee Lower Level (Grades 5 6) Quantitative Reasoning

Example Question #452 : Isee Lower Level (Grades 5 6) Quantitative Reasoning

Example Question #2543 : Numbers And Operations

Example Question #454 : Isee Lower Level (Grades 5 6) Quantitative Reasoning

Example Question #2541 : Numbers And Operations

Example Question #22 : Solve Word Problems Involving Money: Ccss.Math.Content.2.Md.C.8

All Common Core: 2nd Grade Math Resources

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