Calculus AB : Limits and Continuity

Study concepts, example questions & explanations for Calculus AB

varsity tutors app store varsity tutors android store

Example Questions

1 2 5 6 7 8 9 10 11 13 Next →

Example Question #7 : Apply Intermediate Value Theorem

Can Intermediate Value Theorem be applied to the function  within the interval ?

Possible Answers:

No, because 

Yes, because the function  has a root at 

No, because the function is not continuous

Yes, because the function crosses the  axis within the interval 

Correct answer:

No, because 

Explanation:

The required conditions for Intermediate Value Theorem include the function must be continuous and cannot equal . While there is a root at  for this particular continuous function, this cannot be shown using Intermediate Value Theorem. The function does not cross the  axis, thus eliminating that particular answer choice. The correct answer is “No, because .” Since one of the conditions for Intermediate Value Theorem is that cannot equal , by graphing  we can see that this requirement is not met.

Example Question #8 : Apply Intermediate Value Theorem

What can be concluded by using Intermediate Value Theorem for the function  on the interval ?

Possible Answers:

There is a root for this polynomial located between  and 

The requirements for Intermediate Value Theorem are not met

There are two roots on this polynomial located between  and 

There is a root for this polynomial at 

Correct answer:

There is a root for this polynomial located between  and 

Explanation:

his function is continuous (as it is a polynomial) and ; therefore, the required conditions for Intermediate Value Theorem are met. While there is a root at  for this function (as can be seen by graphing the polynomial), Intermediate Value Theorem does not state where this root will be exactly, nor does it state how many roots there might be. Thus, the conclusion that can be made by IVT is that there is a root for this polynomial located somewhere between  and .

Example Question #9 : Apply Intermediate Value Theorem

Let . Is there a number  between  and  such that ?

Possible Answers:

Yes, as shown by the Fundamental Theorem of Calculus

No, Intermediate Value Theorem cannot determine the exact value of 

No, no number c such that  exists

Yes, as shown by Intermediate Value Theorem

Correct answer:

Yes, as shown by Intermediate Value Theorem

Explanation:

First, determine the values of the function at the bounds. This will allow the correct implementation of the Intermediate Value Theorem.

Because the problem asks to analyze the interval  and , there must be a value , with . Because , by Intermediate Value Theorem there should be a number  between  and  that satisfies the required conditions. Therefore, “Yes, as shown by Intermediate Value Theorem” is the correct  answer.

Example Question #10 : Apply Intermediate Value Theorem

Assume  is continuous on the interval  and has the values listed in the table below. Which of the following values of  guarantees that  has at least two roots?

Q10 table

Possible Answers:

Correct answer:

Explanation:

If , only one root can be guaranteed (at ). 

If , then Intermediate Value Theorem can be applied twice, for  and .

 

This is true because for continuous functions, Intermediate Value Theorem states that a change in sign (ex: from positive to negative) of the function within an interval suggests a root (where the function crosses the  axis) at some point within that interval.

 

 

1 2 5 6 7 8 9 10 11 13 Next →
Learning Tools by Varsity Tutors