Calculus 1 : Differential Functions

Study concepts, example questions & explanations for Calculus 1

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Example Questions

Example Question #201 : Differential Functions

What is the first derivative of f(x) = sin4(x) – cos4(x)?

Possible Answers:

4sin(4x)

4sin3(x) + 4cos3(x)

1

2sin(2x)

4

Correct answer:

2sin(2x)

Explanation:

Applying the chain rule to each element, we get:

f'(x) = 4sin3(x)cos(x) + 4cos3(x)sin(x)

If we factor out the common factors, we get: 

f'(x) = 4sin(x)cos(x)(sin2(x) + cos2(x)) = 4sin(x)cos(x)(1) = 4sin(x)cos(x)

Also, since we know that 2sin(x)cos(x) = sin(2x), we know that 4sin(x)cos(x) = 2sin(2x)

Example Question #202 : Differential Functions

What is the first derivative of f(x) = x2sin(4x3)?

Possible Answers:

sin(4x3) + 12x2cos(4x3)

2x(sin(4x3) + 6x3cos(4x3))

2x * cos(4x3)

24x4 * cos(4x3)

2x * sin(4x3) + 12x5cos(4x3)

Correct answer:

2x(sin(4x3) + 6x3cos(4x3))

Explanation:

This is a product rule combined with a chain rule.  Let's do the chain rule for sin(4x3) first:

cos(4x3) * 12x2 = 12x2cos(4x3)

With this in mind, let's solve our whole problem:

2x * sin(4x3) + x2 * 12x2cos(4x3) = 2x * sin(4x3) + 12x4cos(4x3) = 2x(sin(4x3) + 6x3cos(4x3))

Example Question #203 : Differential Functions

What is the first derivative of f(x) = x4 – x * sin(x–5)?

Possible Answers:

4x3 – cos(x–5)

None of the other answers

4x3 + cos(x–5)

4x3 + sin(x–5) – (5 * cos(x–5)/x5)

4x3 – sin(x–5) + (5 * cos(x–5)/x5)

Correct answer:

4x3 – sin(x–5) + (5 * cos(x–5)/x5)

Explanation:

The first element is merely differentiated as 4x3

The second element is a relatively simple product rule:

sin(x–5) + x * cos(x–5) * –5 * x–6 = sin(x–5) + cos(x–5) * –5 * x–5 = sin(x–5) – (5 * cos(x–5)/x5)

Put everything back together:

4x3 – ( sin(x–5) – (5 * cos(x–5)/x5) ) = 4x3 – sin(x–5) + (5 * cos(x–5)/x5)

Example Question #204 : Differential Functions

What is the first derivative of f(x) = 5x * ln(2x)?

Possible Answers:

5ln(2)/2x

5/x

5(ln(2) + (1/2))

5/2x

5(ln(2) + 1)

Correct answer:

5(ln(2) + 1)

Explanation:

This is just a normal product rule problem:

5 * ln(2x) + 5x * 2 * (1/2x)

Simplify: 5ln(2) + 5 = 5(ln(2) + 1)

Example Question #204 : Differential Functions

What is the slope of the tangent line at x = 2 for f(x) = 6/x2?

Possible Answers:

–1.5

–3

–12

1.5

3

Correct answer:

–1.5

Explanation:

First rewrite your function to make this easier:

f(x) = 6/x= 6x–2

Now, we must find the first derivative:

f'(x) = –2 * 6 * x–3 = –12/x3

The slope of the tangent line of f(x) at x = 2 is: f'(2) = –12/23 = –12/8 = –3/2 = –1.5

Example Question #205 : Differential Functions

What is the first derivative of f(x) = 2ln(cos(x)sin(x))?

Possible Answers:

2cot(x)cos2(x)

cot(x)cos2(x)

2cos(2x)sec(x)csc(x)

2cos2(x)sec(x)csc(x)

None of the other answers

Correct answer:

2cos(2x)sec(x)csc(x)

Explanation:

This requires both the use of the chain rule and the product rule. Start with the natural logarithm: 2/(cos(x)sin(x))

Now, multiply by d/dx cos(x)sin(x), which is: –sin(x)sin(x) + cos(x)cos(x) = cos2(x) – sin2(x)

Therefore, f'(x) = (cos2(x) – sin2(x)) * 2/(cos(x)sin(x)) = 2(cos2(x) – sin2(x))sec(x)csc(x)

From our trigonometric identities, we know cos2(x) – sin2(x) = cos(2x)

Therefore, we can finilize our simplification to f'(x) = 2cos(2x)sec(x)csc(x)

Example Question #206 : Differential Functions

Take the derivative of

y=(7+x)^{(7+x)^2}

Possible Answers:

{y}'=(7+x)^{(7+x)^2}[2(7+x)\ln(7+x)+7+x]

Derivative does not exist

 

{y}'=(7+x)^{(7+x)^2}[21+\ln(7+x)+x]

{y}'=(7+x)^{(7+x)^2}(1+\ln(7+x)^{(7+x)^2)})

{y}'=(7+x)^2(7+x)^{(7+x)^2-1}

Correct answer:

{y}'=(7+x)^{(7+x)^2}[2(7+x)\ln(7+x)+7+x]

Explanation:

We need to use logarithm differentiation to do this problem.  Take the natural log of both sides.

\ln y=\ln(7+x)^{(7+x)^2}

Apply the power rule of natural log

\ln y=(7+x)^2\ln(7+x)

Perform implicit differentiation to both sides

\frac{{y}'}{y}=2(7+x)\ln(7+x)+7+x

Solve for

{y}'=y[2(7+x)\ln(7+x)+7+x]

{y}'=(7+x)^{(7+x)^2}[2(7+x)\ln(7+x)+7+x]

Example Question #21 : Other Differential Functions

Find   

Possible Answers:

Correct answer:

Explanation:






Example Question #1237 : Calculus

Differentiate:

 with respect to .

Possible Answers:

Correct answer:

Explanation:

Apply the chain rule: differentiate the "outside" function first. Let .

Differentiate the "inside" function next.

Multiply these two functions to find the derivative of the original function.

Example Question #1238 : Calculus

Evaluate 

Possible Answers:

Correct answer:

Explanation:

To integrate the function, integrate each term of the function. e.g., integrate  by increasing the exponent by 1 integer and dividing the term by this new integer: .

Do this for the rest to get .

But remember that every integration requires an arbitrary constant, . Thus, the integral of the function is 

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