We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Basic Geometry : Circles

Study concepts, example questions & explanations for Basic Geometry

Create An Account

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #3 : How To Find The Length Of The Diameter

A circle has an area of $60\pi$ cm^2 . What is the circle's diameter?

Possible Answers:

$2\sqrt{15}$

$2\sqrt{15}\pi$

$4\sqrt{15}$

Correct answer:

$4\sqrt{15}$

Explanation:

The area of a circle is given by the equation $A = \pi r^2$ , where is the area and is the radius. Use the given area in this equation and solve for to find the circle's radius.

$60\pi = \pi r^2$

$\frac{(60\pi)}{\pi} = \frac{(\pi r^2)}{\pi}$

60 = r^2

$\sqrt{60} = \sqrt{r^2}$

$r = \sqrt{60} = 2\sqrt{15}$

To find the circle's diameter, multiply its radius by .

$2\sqrt{15} * 2 = 4\sqrt{15}$

Report an Error

Example Question #4 : How To Find The Length Of The Diameter

A circle has a radius of 7 inches. What is the diameter of the circle?

Possible Answers:

inches

Correct answer:

inches

Explanation:

The diameter of a circle can be written as d=2r , where is the radius and is the diameter.

(7) 2 = 14

Therefore the diameter of the circle is 14 inches.

Report an Error

Example Question #2 : How To Find The Length Of The Diameter

Two legs of a right triangle measure 3 and 4, respectively. What is the area of the circle that circumscribes the triangle?

Possible Answers:

$6.25\pi$

$5\pi$

$6\pi$

$12.5\pi$

$25\pi$

Correct answer:

$6.25\pi$

Explanation:

For the circle to contain all 3 vertices, the hypotenuse must be the diameter of the circle. The hypotenuse, and therefore the diameter, is 5, since this must be a 3-4-5 right triangle.

The equation for the area of a circle is A = πr².

$A=\pi (5/2)^2=6.25\pi$

Report an Error

Example Question #7 : Diameter

If the area of a circle is $9\pi$ , what is its diameter?

Possible Answers:

Correct answer:

Explanation:

Before we can find the diameter of this circle, we need to find its radius. We need to use the formula for the area of a cirlce:

$A=\pi r^2$

Given that the area is $9\pi$ , we can find the radius

$9\pi=\pi r^2$

cancel the pi and then square root it to find 'r'.

9=r^2

3=r

Now that the radius is found, we can find the diamater by multiplying it by 2.

D=2r=2(3)=6

Report an Error

Example Question #8 : Diameter

Find the diameter of a circle that has an area of $144\pi$ .

Possible Answers:

144

$24\pi$

Correct answer:

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$144\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=144$

$\text{radius}=\sqrt{144}=12$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times 12 = 24$

Report an Error

Example Question #311 : Circles

Find the diameter of a circle that has an area of $169\pi$ .

Possible Answers:

$26\pi$

Correct answer:

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$169\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=169$

$\text{radius}=\sqrt{169}=13$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times 13 = 26$

Report an Error

Example Question #11 : How To Find The Length Of The Diameter

Find the diameter of a circle whose area is $49\pi$ .

Possible Answers:

$14\pi$

$7\pi$

Correct answer:

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$49\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=49$

$\text{radius}=\sqrt{49}=7$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times 7 = 14$

Report an Error

Example Question #312 : Circles

Find the diameter of a circle whose area is $676\pi$ .

Possible Answers:

104

Correct answer:

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$676\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=676$

$\text{radius}=\sqrt{676}=26$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times 26 = 52$

Report an Error

Example Question #14 : How To Find The Length Of The Diameter

Find the diameter of a circle whose area is $324\pi$ .

Possible Answers:

Correct answer:

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$324\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=324$

$\text{radius}=\sqrt{324}=18$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times 18 = 36$

Report an Error

Example Question #13 : How To Find The Length Of The Diameter

Find the diameter of a circle whose area is $289\pi$ .

Possible Answers:

8.5

Correct answer:

Explanation:

Recall how to find the area of a circle:

$\text{Area}=\pi\times\text{radius}^2$

Next, plug in the information given by the question.

$289\pi=\pi\times\text{radius}^2$

From this, we can see that we can solve for the radius.

$\text{radius}^2=289$

$\text{radius}=\sqrt{289}=17$

Now recall the relationship between the radius and the diameter.

$\text{diameter}=2\times\text{radius}$

Plug in the value of the radius to find the diameter.

$\text{diameter}=2\times 17 = 34$

Report an Error

View Tutors

Diane
Certified Tutor

Ashford University, Bachelor in Arts, Education. Ashford University, Master of Arts, Education.

View Tutors

Ben
Certified Tutor

Brown University, Bachelor in Arts, International Relations. Bridge Education Group, Certificate, Teaching French as a Second...

View Tutors

Mohammad
Certified Tutor

Rutgers University-New Brunswick, Bachelor of Science, Mathematics. Rutgers University-New Brunswick, Master of Science, Stat...

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

GRE Tutors in Chicago, Computer Science Tutors in Atlanta, Statistics Tutors in Chicago, Calculus Tutors in Washington DC, Math Tutors in Chicago, Math Tutors in Los Angeles, LSAT Tutors in Washington DC, Math Tutors in Houston, Physics Tutors in New York City, Biology Tutors in Denver

Popular Courses & Classes

GRE Courses & Classes in Dallas Fort Worth, GRE Courses & Classes in New York City, MCAT Courses & Classes in Atlanta, MCAT Courses & Classes in San Francisco-Bay Area, MCAT Courses & Classes in Denver, MCAT Courses & Classes in San Diego, ISEE Courses & Classes in Seattle, ISEE Courses & Classes in Chicago, SAT Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in Seattle

Popular Test Prep

SSAT Test Prep in San Diego, SAT Test Prep in Washington DC, SSAT Test Prep in Denver, LSAT Test Prep in Philadelphia, MCAT Test Prep in Philadelphia, ISEE Test Prep in Boston, GRE Test Prep in Washington DC, MCAT Test Prep in Washington DC, GRE Test Prep in Denver, ISEE Test Prep in San Francisco-Bay Area

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Basic Geometry : Circles

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #3 : How To Find The Length Of The Diameter

Example Question #4 : How To Find The Length Of The Diameter

Example Question #2 : How To Find The Length Of The Diameter

Example Question #7 : Diameter

Example Question #8 : Diameter

Example Question #311 : Circles

Example Question #11 : How To Find The Length Of The Diameter

Example Question #312 : Circles

Example Question #14 : How To Find The Length Of The Diameter

Example Question #13 : How To Find The Length Of The Diameter

All Basic Geometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: