We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Basic Geometry : How to find the area of a rectangle

Study concepts, example questions & explanations for Basic Geometry

Create An Account

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #165 : Rectangles

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

Correct answer:

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{36}{2}-12$

Simplify.

$\text{Width}=6$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=12 \times 6$

Solve.

$\text{Area}=72$

Report an Error

Example Question #166 : Rectangles

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

168

156

144

132

Correct answer:

156

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{50}{2}-13$

Simplify.

$\text{Width}=12$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=13 \times 12$

Solve.

$\text{Area}=156$

Report an Error

Example Question #167 : Rectangles

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

Correct answer:

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{28}{2}-13$

Simplify.

$\text{Width}=1$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=13 \times 1$

Solve.

$\text{Area}=13$

Report an Error

Example Question #168 : Rectangles

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

130

280

140

160

Correct answer:

140

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{48}{2}-10$

Simplify.

$\text{Width}=14$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=10 \times 14$

Solve.

$\text{Area}=140$

Report an Error

Example Question #21 : How To Find The Area Of A Rectangle

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

300

350

175

250

Correct answer:

250

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{70}{2}-25$

Simplify.

$\text{Width}=10$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=25 \times 10$

Solve.

$\text{Area}=250$

Report an Error

Example Question #22 : How To Find The Area Of A Rectangle

If the perimeter of a rectangle is , and the length fo the rectangle is , what is the area of the rectangle?

Possible Answers:

Correct answer:

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{40}{2}-5$

Simplify.

$\text{Width}=15$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=5 \times 15$

Solve.

$\text{Area}=75$

Report an Error

Example Question #23 : How To Find The Area Of A Rectangle

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

155

145

135

125

Correct answer:

135

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{48}{2}-15$

Simplify.

$\text{Width}=9$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=15 \times 9$

Solve.

$\text{Area}=135$

Report an Error

Example Question #24 : How To Find The Area Of A Rectangle

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

Correct answer:

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{16}{2}-2$

Simplify.

$\text{Width}=6$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=2 \times 6$

Solve.

$\text{Area}=12$

Report an Error

Example Question #25 : How To Find The Area Of A Rectangle

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

Correct answer:

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{20}{2}-5$

Simplify.

$\text{Width}=5$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=5 \times 5$

Solve.

$\text{Area}=25$

Report an Error

Example Question #26 : How To Find The Area Of A Rectangle

If the perimeter of a rectangle is , and the length of the rectangle is , what is the area of the rectangle?

Possible Answers:

150

250

300

200

Correct answer:

200

Explanation:

First, use the information given about the perimeter to find the width of the rectangle.

Recall how to find the perimeter of a rectangle:

$\text{Perimeter}=2(\text{length}+\text{width})$

From this equation, we can solve for the width.

$\text{length}+\text{width}=\frac{\text{Perimeter}}{2}$

$\text{width}=\frac{\text{Perimeter}}{2}-\text{length}$

Substitute in the information from the question to find the width of the rectangle.

$\text{Width}=\frac{60}{2}-20$

Simplify.

$\text{Width}=10$

Now, recall how to find the area of a rectangle:

$\text{Area}=\text{length}\times\text{width}$

Substitute in the information about the length and width to find the area for the rectangle in question.

$\text{Area}=20 \times 10$

Solve.

$\text{Area}=200$

Report an Error

View Tutors

Paarth
Certified Tutor

New Jersey Institute of Technology, Bachelor of Science, Computer Science.

View Tutors

Joshua
Certified Tutor

Murray State University, Bachelor in Arts, Spanish. Lipscomb University, Bachelor of Science, Teacher Assistant.

View Tutors

Kaylee
Certified Tutor

Brigham Young University, Bachelor, MFA - Animation.

All Basic Geometry Resources

9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Biology Tutors in Philadelphia, Statistics Tutors in Boston, ISEE Tutors in Dallas Fort Worth, Computer Science Tutors in Atlanta, LSAT Tutors in Denver, Chemistry Tutors in Denver, SSAT Tutors in Seattle, Computer Science Tutors in Washington DC, MCAT Tutors in Phoenix, Reading Tutors in Seattle

Popular Courses & Classes

ACT Courses & Classes in San Diego, Spanish Courses & Classes in Denver, SAT Courses & Classes in San Diego, LSAT Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in Phoenix, ISEE Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in New York City, LSAT Courses & Classes in Seattle, GRE Courses & Classes in Atlanta, GMAT Courses & Classes in Dallas Fort Worth

Popular Test Prep

SSAT Test Prep in Miami, MCAT Test Prep in Boston, ACT Test Prep in Seattle, ACT Test Prep in Denver, GRE Test Prep in Seattle, LSAT Test Prep in Washington DC, SSAT Test Prep in Boston, ISEE Test Prep in Phoenix, ACT Test Prep in Phoenix, ACT Test Prep in San Diego

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Basic Geometry : How to find the area of a rectangle

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #165 : Rectangles

Example Question #166 : Rectangles

Example Question #167 : Rectangles

Example Question #168 : Rectangles

Example Question #21 : How To Find The Area Of A Rectangle

Example Question #22 : How To Find The Area Of A Rectangle

Example Question #23 : How To Find The Area Of A Rectangle

Example Question #24 : How To Find The Area Of A Rectangle

Example Question #25 : How To Find The Area Of A Rectangle

Example Question #26 : How To Find The Area Of A Rectangle

All Basic Geometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: