Call Now to Set Up Tutoring:

(888) 888-0446

AP Physics 1 : Impulse and Momentum

Study concepts, example questions & explanations for AP Physics 1

Create An Account

All AP Physics 1 Resources

7 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

← Previous 1 2 3 4 5 6 7 8 9 Next →

Example Question #21 : Impulse And Momentum

A train of mass $1.8\times10^7 kg$ traveling at $15 \frac{m}{s}$ strikes a car stuck on the tracks of mass 1300 kg . The car becomes stuck on the train.

Determine the final velocity of the train.

Possible Answers:

$15 \frac{m}{s}$

$30 \frac{m}{s}$

$10 \frac{m}{s}$

$20 \frac{m}{s}$

None of these

Correct answer:

$15 \frac{m}{s}$

Explanation:

We will need to use conservation of momentum to solve this problem.

$M_1V_1+M_2V_2=M_{final}V_{final}$

Where M_1 and V_1 refer to the train, and M_2 and V_2 refer to the car. $M_{final}$ and $V_{final}$ refer to the final state of both the train and the car.

Rearranging using algebra......

$\frac{M_1V_1+M_2V_2}{M_{final}}=V_{final}$

$\frac{1.8\times10^7\cdot15+1300\cdot0}{1.8\times10^7}=V_{final}$

Plugging in our values, we get $15 \frac{m}{s}$ .

Report an Error

Example Question #21 : Impulse And Momentum

A train of mass $1.8\times10^7 kg$ traveling at $15 \frac{m}{s}$ strikes a car stuck on the tracks of mass 1300 kg . The car becomes stuck on the train.

Determine the final velocity of the car.

Possible Answers:

$10 \frac{m}{s}$

$5 \frac{m}{s}$

$20 \frac{m}{s}$

$15 \frac{m}{s}$

None of these

Correct answer:

$15 \frac{m}{s}$

Explanation:

We will need to use conservation of momentum to solve this problem.

$M_1V_1+M_2V_2=M_{final}V_{final}$

Where M_1 and V_1 refer to the train, and M_2 and V_2 refer to the car. $M_{final}$ and $V_{final}$ refer to the final state of both the train and the car.

Rearranging using algebra......

$\frac{M_1V_1+M_2V_2}{M_{final}}=V_{final}$

$\frac{1.8\times10^7\cdot15+1300\cdot0}{1.8\times10^7}=V_{final}$

Plugging in our values, we get $15 \frac{m}{s}$ .

Report an Error

Example Question #23 : Impulse And Momentum

A train of mass $1.8\times10^7 kg$ traveling at $15 \frac{m}{s}$ strikes a car stuck on the tracks of mass 1300 kg .

Let's assume this collison took .01 seconds to happen. That is, it took the car to accelerate to it's new velocity. Determine the force experienced by the car.

Possible Answers:

$3.38\times10^6 N$

$1.11\times10^6 N$

None of these

$1.95\times10^6 N$

$2.25\times10^6 N$

Correct answer:

$1.95\times10^6 N$

Explanation:

We will need to use conservation of momentum to solve this problem.

$M_1V_1+M_2V_2=M_{final}V_{final}$

Where M_1 and V_1 refer to the train, and M_2 and V_2 refer to the car. $M_{final}$ and $V_{final}$ refer to the final state of both the train and the car.

Rearranging using algebra......

$\frac{M_1V_1+M_2V_2}{M_{final}}=V_{final}$

$\frac{1.8\times10^7\cdot15+1300\cdot0}{1.8\times10^7}=V_{final}$

Plugging in our values, we get $15 \frac{m}{s}$ .

Then, we will need to find out final momentum of the car.

$M_{car}V_{final}=P_{final}$

$1300kg\cdot15\frac{m}{s}=P_{final}$

$M_{car}V_{final}=P_{final}$

$\Delta P=P_{final}-P_{initial}$

Since our intial momentum of the car was , our change in momentum will be equal to the $P_{final}$ .

$\Delta P=P_{final}$

We will use the definition of impulse, which is the change in momentum:

$F\cdot \Delta t= \Delta P$

We will use substitution:

$F\cdot \Delta t= P_{final}$

Plugging in our values, we get $1.95\times10^6 N$

Report an Error

Example Question #24 : Impulse And Momentum

A car of mass 1110kg is accelerated from $10 \frac{m}{s}$ to $35 \frac{m}{s}$ in 2s.

Determine the average total forces on this car during this time frame.

Possible Answers:

F=4.4*10^4N

F=1.1*10^4N

F=2.4*10^4N

F=3.9*10^4N

F=1.4*10^4N

Correct answer:

F=1.4*10^4N

Explanation:

Determine the change in the velocity of the car:

$35\frac{m}{s}-10\frac{m}{s}=25\frac{m}{s}$

Calculate the average acceleration:

$\frac{25\frac{m}{s}}{2 s}=\frac{\Delta v}{\Delta s}=a$

$12.5\frac{m}{s^2}=a$

Use the definition of force:

F=ma

$F=1110kg*12.5\frac{m}{s^2}$

F=1.4*10^4N

Report an Error

Example Question #25 : Impulse And Momentum

A cart is traveling at $3 \frac{m}{s}$ when it launches a ball straight into the air with initial velocity $15 \frac{m}{s}$ .

You may ignore air resistance.

How much time will the ball take from the moment it is launched to return to it's initial height?

Possible Answers:

$\Delta t_{airtime}=30s$

None of these

$\Delta t_{airtime}=3.0s$

$\Delta t_{airtime}=1.5s$

$\Delta t_{airtime}=4.5s$

Correct answer:

$\Delta t_{airtime}=3.0s$

Explanation:

First, break the airborne time into two pieces, the ascent and descent.

Ascent:

The ball will need to decelerate from $15\frac{m}{s}$ to $0 \frac{m}{s}$ .

Use acceleration due to gravity.

$15\frac{m}{s}-9.8\frac{m}{s^2}*\Delta t=0\frac{m}{s}$

Solve for $\Delta t$

$\Delta t=1.5s$

Descent:

Due to parabolic motion, the ball will have the same magnitude of velocity when it returns to it's height as when it launched, albeit in the opposite direction.

$0\frac{m}{s}-9.8\frac{m}{s^2}*\Delta t=-15\frac{m}{s}$

Solving for $\Delta t$

$\Delta t=1.5s$

Add the times together to get the total airtime.

$\Delta t_{airtime}=3.0s$

Report an Error

Example Question #481 : Ap Physics 1

A cart is traveling at $3 \frac{m}{s}$ when it launches a ball straight into the air with initial velocity $15 \frac{m}{s}$ . Ignore air resistance.

How far will the cart have traveled by the time the ball returns to it's initial height?

Possible Answers:

3.5m=d

25m=d

9m=d

None of these

15m=d

Correct answer:

9m=d

Explanation:

First, break the airborne time into two pieces, the ascent and descent.

Ascent:

The ball will need to decelerate from $15\frac{m}{s}$ to $0 \frac{m}{s}$ .

Use acceleration due to gravity.

$15\frac{m}{s}-9.8\frac{m}{s^2}*\Delta t=0\frac{m}{s}$

Solve for $\Delta t$

$\Delta t=1.5s$

Descent:

Due to parabolic motion, the ball will have the same magnitude of velocity when it returns to it's height as when it launched, albeit in the opposite direction.

$0\frac{m}{s}-9.8\frac{m}{s^2}*\Delta t=-15\frac{m}{s}$

Solve for $\Delta t$

$\Delta t=1.5s$

Add the times together.

$\Delta t_{airtime}=3.0s$

Multiply the airtime by the velocity of the cart.

$3.0s*\frac{3m}{s}=d$

9m=d

Report an Error

Example Question #22 : Impulse And Momentum

An astronaut of mass 100kg throws a 8kg shot put in space. If the shot put has a magnitude of velocity of $3\frac{m}{s}$ in relation to the center of the galaxy, determine the magnitude of velocity of the astronaut in relation to the center of the galaxy.

Possible Answers:

None of these

$v_a=.32\frac{m}{s}$

$v_a=4\frac{m}{s}$

$v_a=32\frac{m}{s}$

$v_a=15\frac{m}{s}$

Correct answer:

$v_a=.32\frac{m}{s}$

Explanation:

Using conservation of momentum:

P_i=P_f

The initial momentum can be taken as zero from our reference frame.

$0\frac{kg*m}{s}=P_{astro}+P_{shotput}$

Plug in values:

$0\frac{kg*m}{s}=100kg*v_a+8kg*-4\frac{m}{s}$

Note: The sign of the velocity for the shot put is negative because it will be in the opposite direction as the astronaut. The question is asking for magnitude though, so we know it will be positive regardless of the direction since magnitude does not take into account the direction of motion.

$v_a=.32\frac{m}{s}$

Report an Error

Example Question #28 : Impulse And Momentum

A batter makes contact with a baseball for 0.1 seconds, exerting a constant force of 100 Newtons during the contact.

What is the ball's change in momentum as a result of the contact?

Possible Answers:

100Ns

50Ns

5Ns

10 Ns

1Ns

Correct answer:

10 Ns

Explanation:

We use the equation:

$\Delta p = F \Delta t$

Where the change in momentum is $\Delta p$ .

The force, , is 100N and t is the time during which the force is exerted ( $\Delta t=0.1s$ ) as given by the problem statement, we plug in to the formula:

$\Delta p=(100N)*(0.1s)=10Ns$

Report an Error

Example Question #29 : Impulse And Momentum

A locomotive of mass 167*10^3kg traveling at $4\frac{km}{hr}$ couples to a motionless coach without applying the brakes. Calculate the momentum change (the impulse experienced) of the coach.

Possible Answers:

$52.3*10^3\frac{kg*m}{s}$

$91.1*10^3\frac{kg*m}{s}$

$85.1*10^3\frac{kg*m}{s}$

$47.8*10^3\frac{kg*m}{s}$

$66.7*10^3\frac{kg*m}{s}$

Correct answer:

$52.3*10^3\frac{kg*m}{s}$

Explanation:

Use conservation of momentum

P_i=P_f

$m_{1i}v_{1i}+m_{2i}v_{2i}=m_{1,2f}v_{1,2f}$

Plug in values:

$(167*10^3)*4+(67*10^3)*0=(234*10^3)v_{1,2f}$

Solve for $v_{1,2f}$ :

$v_{1,2f}=\frac{167*10^3*4}{234*10^3}$

$v_{1,2f}=2.85\frac{km}{hr}$

Definition of impulse:

$J=\Delta P=m(v_f-v_i)$

Convert $\frac{km}{hr}$ to $\frac{m}{s}$

$2.85\frac{km}{hr}*\frac{1hr}{3600s}*\frac{1000m}{1km}=.79\frac{m}{s}$

Plug in values:

$J=\Delta P=67*10^3(.79-0)$

$J=52.3*10^3\frac{kg*m}{s}$

Report an Error

Example Question #21 : Impulse And Momentum

A locomotive of mass 167*10^3kg traveling at $4\frac{km}{hr}$ couples to a motionless coach without applying the brakes. This took .5s . Determine the average force experienced by the coach.

Possible Answers:

382kN

507kN

105kN

302kN

207kN

Correct answer:

105kN

Explanation:

Use conservation of momentum

P_i=P_f

$m_{1i}v_{1i}+m_{2i}v_{2i}=m_{1,2f}v_{1,2f}$

Plug in values:

$(167*10^3)*4+(67*10^3)*0=(234*10^3)v_{1,2f}$

Solve for $v_{1,2f}$ :

$v_{1,2f}=\frac{167*10^3*4}{234*10^3}$

$v_{1,2f}=2.85\frac{km}{hr}$

Definition of impulse:

$J=\Delta P=m(v_f-v_i)$

Convert $\frac{km}{hr}$ to $\frac{m}{s}$

$2.85\frac{km}{hr}*\frac{1hr}{3600s}*\frac{1000m}{1km}=.79\frac{m}{s}$

Plug in values:

$J=\Delta P=67*10^3(.79-0)$

$J=52.3*10^3\frac{kg*m}{s}$

$J=F*\Delta t$

Plug in values

$52.3*10^3\frac{kg*m}{s}=F*.5seconds$

Solve for :

F=105kN

Report an Error

← Previous 1 2 3 4 5 6 7 8 9 Next →

View AP Physics 1 Tutors

Magdy
Certified Tutor

Cairo University, Egypt, Bachelor of Science, Electrical Engineering. New Mexico State University-Main Campus, Doctor of Phil...

View AP Physics 1 Tutors

Jeremy
Certified Tutor

University of Illinois at Chicago, Bachelor of Science, Physics.

View AP Physics 1 Tutors

Ali
Certified Tutor

McGill University, Master of Mechnaical Engineering, Mechanical Engineering.

All AP Physics 1 Resources

7 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Computer Science Tutors in Houston, Physics Tutors in Boston, Physics Tutors in Seattle, Computer Science Tutors in Denver, Reading Tutors in San Francisco-Bay Area, Math Tutors in Dallas Fort Worth, Reading Tutors in Seattle, GMAT Tutors in San Diego, French Tutors in New York City, MCAT Tutors in Chicago

Popular Courses & Classes

Spanish Courses & Classes in Atlanta, GMAT Courses & Classes in Phoenix, ACT Courses & Classes in Boston, SAT Courses & Classes in Dallas Fort Worth, ACT Courses & Classes in Miami, SAT Courses & Classes in Houston, ACT Courses & Classes in San Francisco-Bay Area, LSAT Courses & Classes in Los Angeles, MCAT Courses & Classes in Denver, Spanish Courses & Classes in New York City

Popular Test Prep

ACT Test Prep in San Francisco-Bay Area, MCAT Test Prep in Phoenix, LSAT Test Prep in San Diego, LSAT Test Prep in Washington DC, GMAT Test Prep in Phoenix, SAT Test Prep in Boston, ACT Test Prep in Boston, SAT Test Prep in Atlanta, ISEE Test Prep in New York City, ACT Test Prep in Seattle

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

AP Physics 1 : Impulse and Momentum

Study concepts, example questions & explanations for AP Physics 1

All AP Physics 1 Resources

Example Questions

Example Question #21 : Impulse And Momentum

Example Question #21 : Impulse And Momentum

Example Question #23 : Impulse And Momentum

Example Question #24 : Impulse And Momentum

Example Question #25 : Impulse And Momentum

Example Question #481 : Ap Physics 1

Example Question #22 : Impulse And Momentum

Example Question #28 : Impulse And Momentum

Example Question #29 : Impulse And Momentum

Example Question #21 : Impulse And Momentum

All AP Physics 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: