All AP Physics 1 Resources
Example Questions
Example Question #721 : Ap Physics 1
The force of friction, , points always points along which direction?
points perpendicular to the direction of motion.
can point in any direction relative to a surface.
points along the direction of motion.
always points opposite of the direction of motion, or intended direction of motion.
always points opposite of the direction of motion, or intended direction of motion.
By definition, , always points opposite of the objects direction of motion. If the object is not moving, but an applied force is attempted to move the object along a particular direction, points opposite of the intended direction.
Example Question #721 : Ap Physics 1
Assuming that the brakes are locked up and thus all friction is kinetic, what does the coefficient of friction need to be for a car traveling at in ?
None of these
Use the following experience:
All energy will be kinetic, and final energy will be zero as the car has stopped.
Using the definition of the force of friction. (Frictional force points in the direction opposite of travel, so will be a negative value)
Solving for
Plugging in values
Example Question #121 : Forces
How will changing the amount of surface area in contact between two surfaces affect friction?
It is unaffected
Increasing surface area will increase friction to a point, then decrease it
Increasing surface area will decrease friction
Increasing surface area will increase friction
It depends on the surfaces involved
It is unaffected
Frictional force is independent of surface area, it only depends on the normal force and the coefficient of friction.
Example Question #732 : Ap Physics 1
A box is in a moving bus. When the bus is moving at and goes around a corner with a radius of , the force is just enough to cause the box to “move to the outside” of the bus. Determine the coefficient of static friction between the floor and the box.
None of these
Right when the box starts to slide, the magnitude of the frictional force is equal to the magnitude of the centripetal force.
Using the definition of frictional force.
Solving for
Plugging in values:
Example Question #21 : Force Of Friction
What coefficient of friction would be needed to stop a box sliding across a level surface at in ?
None of these
Solving for :
Plugging in values:
Example Question #21 : Force Of Friction
A box starts sliding down an adjustable ramp when the angle has reached . Determine the coefficient of friction between the box and the ramp.
None of these
By constructing a force diagram, it can be seen that:
Right when the box starts to move, these will be equal
Solving for
Plugging in values:
Example Question #22 : Force Of Friction
2 masses are connected by a pulley as demonstrated by the image above. The weight of mass 1 is and and the weight of mass 2 is . The coefficient of static friction between mass 1 and the block it rests on is and the coefficient of kinetic friction between the 2 surfaces is . The system is not drawn to scale.
How fast will mass 1 be accelerating in this system?
Because the mass of object 1 is given, the force acting on it must be found in order to figure out how fast it is accelerating. These 3 variables are related by the equation:
There are 2 forces acting on mass 1. The first force is the tension in the rope. This tension is equal to the magnitude of the gravitational force created by object 2. This can be found using the equation:
where g is the gravity constant which is equal to .
The other force acting on the object is friction. The force of friction can be found by multiplying the normal force exerted by the object on the surface that it is resting on by the coefficient of friction. This is demonstrated by the equation:
Where is the coefficient of friction and N is the normal force. Static friction is the force of friction acting on an object that is not moving. because the magnitude of the force of static friction would not be as great as the magnitude of the force of tension in the rope the object would be moving. Because the object is moving, kinetic friction would be the other force that is acting on mass 1. Kinetic friction represents the friction exerted on an object that is moving on a surface.
Because there are 2 forces acting on this object, a free body diagram can be made to illustrate these forces.
T represents tension in the rope while F represents friction. The total net force can be found by subtracting the force of friction from the magnitude of tension in the rope.
Acceleration of mass 1 can now be figured out because the force acting on the object has been found and the mass is given.
Example Question #121 : Forces
Mass 1 weighs and mass 2 weighs .
What would be the minimum coefficient of static friction between mass 1 and the surface that would cause mass 1 to not slide in this system?
In order for mass 1 to remain stationary while mass 2 is experiencing free fall, the magnitude of the force of static friction acting on mass 1 must be greater than the magnitude of the force of tension in the rope that is created by mass 2. The force of tension in the rope is equal to the gravitational force that is created by mass 2. This force can be found using the equation:
The minimum coefficient of static friction would create a force in the opposite direction that has the same magnitude as the force found above. Force of static friction is equal to the coefficient static friction between an object and surface multiplied by the normal force exerted by the object being analyzed. This is represented by the following equation:
Where is the coefficient of static friction and N is normal force. Normal force in this problem would be equal to the mass of object 1 multiplied by the gravity constant. By setting the 2 equations above equal to each other, minimum coefficient of static friction can be found.
After plugging in given values,
Example Question #24 : Force Of Friction
How will doubling the coefficient of friction of rubber tires change the stopping distance of a car?
Impossible to determine
Cut the stopping distance in half
None of these
Quadruple the stopping distance
Double the stopping distance
Cut the stopping distance in half
Since the car is stopped at the end,
Combining equations:
Solving for
From this, it can be seen that doubling the coefficient of friction would cut the stopping distance in half.
Example Question #731 : Ap Physics 1
A box is shoved and is sliding on a concrete floor. It has a mass of and in slows from to . Determine the coefficient of friction.
None of these
Work is due to friction:
Solving for
Plugging in values: