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AP Calculus AB : Derivatives

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Example Questions

Example Question #31 : Derivatives

Differentiate the following function.

$f(x)=x^{7}$

Possible Answers:

$f'(x)=7x^{6}$

$f'(x)=6x^{6}$

$f'(x)=7x^{7}$

$f'(x)=6x^{7}+7x^{6}$

$f'(x)=6x^{7}$

Correct answer:

$f'(x)=7x^{6}$

Explanation:

If a function is in the form of $f(x)=x^{a}$ , then the derivative is $f'(x)= a\times x^{a-1}$ .

To solve $f(x)=x^{7}$ you solve bring the 7 down in front of the x and lower the exponent by 1.

This will bring you to the answer $f'(x)=7x^{6}$ .

The apostrophe (') denotes that this is the first derivative of the function.

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Example Question #32 : Derivatives

Calculate the derivative of the following:

$x^{2}+12x-36$

Possible Answers:

x^2-12

2x-24

2x+12

Correct answer:

2x+12

Explanation:

Using the power rule which states,

$\frac{d}{dx}x^n=nx^{n-1}$

you can move the from $x^{2}$ to the front and decrease the exponent by which makes it .

For 12x , any term that has an exponent of , the coefficient is its derivative.

Thus, the derivative of 12x is .

Since does not have a variable attached, the derivative will be .

Add your derivatives to get 2x+12 .

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Example Question #32 : Derivatives

Calculate the derivative of the following:

$x^{3}+8x^{2}-16x+9$

Possible Answers:

$3x^{2}+8x+16$

$3x^3+8x^{2}-16$

$3x^{2}+16x-25$

$3x+16x^{2}-16$

$3x^{2}+16x-16$

Correct answer:

$3x^{2}+16x-16$

Explanation:

Use the power rule to move the exponent of each term to the front, and multiply it with the existing coefficient to create the new coefficient for the derivative.

In mathematical terms, the power rule states,

$\frac{d}{dx}x^n=nx^{n-1}$

Applying the power rule to the first term creates $3x^{2}$ .

Next, move the from $8x^{2}$ to the front and multiply it by , and decrease the exponent by 1 to get 16x .

Next, since 16x does not have an exponent, the derivative of that will be .

Lastly, has a derivative of because there is not variable attached to it.

Therefore the derivative becomes,

$3x^{2}+16x-16$ .

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Example Question #33 : Derivatives

Calculate the derivative of the following:

$\sqrt{x}$

Possible Answers:

$x^{2}$

$x^{\frac{1}{2}}$

$\frac{1}{2\sqrt{x}}$

$\frac{1}{2}x$

$\frac{1}{2}x^2$

Correct answer:

$\frac{1}{2\sqrt{x}}$

Explanation:

To find the derivative, use the power rule.

In mathematical terms, the power rule states,

$\frac{d}{dx}x^n=nx^{n-1}$

$\sqrt{x}$ is the same as $x^{\frac{1}{2}}$ .

Therefore, move the exponent to the front, and then decrease it by one to get

$\frac{1}{2}x^{-\frac{1}{2}}$ .

After simplifying, you get

$\frac{1}{2\sqrt{x}}$ .

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Example Question #34 : Derivatives

Calculate the derivative of the following:

$\left ( x^2-4\right )$

Possible Answers:

2x-4

$2x^{2}$

Correct answer:

Explanation:

Having a binomial does not change the rules for the power rule. You still move the exponent to the front, and decrease the exponent by .

In mathematical terms, the power rule states,

$\frac{d}{dx}x^n=nx^{n-1}$

Constants still have a derivative of

Thus, giving you a final answer of

$\\f(x)=x^2-4 \\f'(x)=2x^{2-1}-0 \\f'(x)=2x$

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Example Question #35 : Derivatives

Calculate the derivative of the following:

$\left ( x^2-2\right )^2$

Possible Answers:

$4x\left ( x^2-2\right )^2$

$4x\left ( x^2-2\right )$

$2\left ( x^2-2\right )^2$

$2x\left ( x^2-2\right )$

$2\left ( x^2-2\right )$

Correct answer:

$4x\left ( x^2-2\right )$

Explanation:

Use the chain rule to move the exponent of the binomial to the front, and decrease the exponent by 1. Next, take the derivative of what is on the inside and multiply it with what is one the outside.

In mathematical terms the chain rule is,

$\frac{d}{dx}(f(x))^n\rightarrow n(f(x))\cdot f'(x)$

Identify f(x) and its derivative first.

$\\f(x)=x^2-2 \\f'(x)=2x^{2-1}=2x$

Substituting the function and its derivative into the chain rule formula, the final derivative becomes

$\\f(x)=(x^2-2)^2 \\f'(x)=2(x^2-2)(2x) \\f'(x)=4x(x^2-2)$

Thus, giving you an answer of $4x\left ( x^2-2\right )$ .

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Example Question #37 : Ap Calculus Ab

Calculate the derivative of the following:

$\frac{x^2}{2}$

Possible Answers:

$\frac{x}{2}$

$\frac{1}{2}x^2$

2x^2

Correct answer:

Explanation:

To find the derivative, use the quotient rule.

The quotient rule requires you to do the following:

$\frac{(Denominator)(Deriv. Numerator)-(Numerator)(Deriv. Denominator)}{(Denominator^2)}$

When you apply it to this problem, you get a final answer of,

$\\\text{Numerator}=x^2 \\\text{Deriv. of Numerator}=2x \\\text{Denominator}=2 \\\text{Deriv. of Denominator}=0$

$\\f'(x)=\frac{2(2x)-x^2(0)}{2^2} \\\\f'(x)=\frac{4x}{4} \\\\f'(x)=x$

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Example Question #38 : Ap Calculus Ab

Calculate the derivative of the following:

$12x^{5}-4x^4+10x^3$

Possible Answers:

60x^4+16x^3+30x^2

60x^4+16x^3-30x^2

60x^5-16x^4+30x^3

60x^4-16x^3+30x^2

12x^5-4x^3+10x^2

Correct answer:

60x^4-16x^3+30x^2

Explanation:

Use the power rule to multiply the exponent of each term with its coefficient, to get the derivative of each separate term.

Then, decrease the exponent of each term by

Keep all the signs the same, and your final answer will be

$\\f(x)=12x^{5}-4x^4+10x^3 \\f'(x)=5\cdot 12x^{5-1}-4\cdot 4x^{4-1}+3\cdot 10x^{3-1}$

f'(x)=60x^4-16x^3+30x^2

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Example Question #21 : Derivatives Of Functions

Calculate the derivative of the following:

$\sin(x)$

Possible Answers:

$-\csc(x)$

$\csc(x)$

$\cos(x)$

$-\sin(x)$

$-\cos(x)$

Correct answer:

$\cos(x)$

Explanation:

This is a trigonometry identity.

$\frac{d}{dx}\sin(x)=\cos(x)$

The derivative of $\sin(x)$ will always be $\cos(x)$ .

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Example Question #36 : Derivatives

Calculate the derivative of the following:

$\cos(x)$

Possible Answers:

$-\sin(x)$

$-\cos(x)$

$\sin(x)$

$-\sec(x)$

$\sec(x)$

Correct answer:

$-\sin(x)$

Explanation:

This is a trigonometry identity.

$\frac{d}{dx}\cos(x)=-\sin(x)$

The derivative of $\cos(x)$ will always be $-\sin(x)$ .

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AP Calculus AB : Derivatives

Study concepts, example questions & explanations for AP Calculus AB

All AP Calculus AB Resources

Example Questions

Example Question #31 : Derivatives

Example Question #32 : Derivatives

Example Question #32 : Derivatives

Example Question #33 : Derivatives

Example Question #34 : Derivatives

Example Question #35 : Derivatives

Example Question #37 : Ap Calculus Ab

Example Question #38 : Ap Calculus Ab

Example Question #21 : Derivatives Of Functions

Example Question #36 : Derivatives

All AP Calculus AB Resources

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