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Algebra II : Imaginary Numbers

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Example Questions

Example Question #71 : Basic Operations With Complex Numbers

Evaluate: $2i^{878}$

Possible Answers:

-2i

$\textup{The answer is not given.}$

Correct answer:

Explanation:

Write the first few powers of the imaginary term.

$i=\sqrt{-1}$

$i^2 = i\cdot i= -1$

Change the higher ordered power by using the power rule of exponents.

$2i^{878} = 2(i^2)^{439}=2(-1)^{439}=2(-1)$

A negative one to an odd power will be negative one.

The answer is:

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Example Question #72 : Basic Operations With Complex Numbers

Add $8 +2 i \sqrt{5}$ to its complex conjugate. What is the result?

Possible Answers:

$-4i \sqrt{5}$

$4i \sqrt{5}$

Correct answer:

Explanation:

The complex conjugate of a complex number a+bi is a-bi .

Therefore, the complex conjugate of $8 +2 i \sqrt{5}$ is $8 -2 i \sqrt{5}$ . Add the two:

$\left (8 +2 i \sqrt{5} \right )+\left ( 8 -2 i \sqrt{5} \right )$

Collect real parts and imaginary parts:

$=8+ 8 +2 i \sqrt{5} -2 i \sqrt{5}$

The imaginary parts cancel out:

=8+ 8

=16

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Example Question #2091 : Mathematical Relationships And Basic Graphs

Select the complex conjugate of $9 - i \sqrt{5}$ .

Possible Answers:

$\sqrt{5} - 9i$

$-9 - i \sqrt{5}$

$\sqrt{5} + 9i$

$9 + i \sqrt{5}$

$-9 +i \sqrt{5}$

Correct answer:

$9 + i \sqrt{5}$

Explanation:

The complex conjugate of a complex number a-bi is a+bi , so the complex conjugate of $9 - i \sqrt{5}$ is $9 + i \sqrt{5}$ .

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Example Question #2092 : Mathematical Relationships And Basic Graphs

Evaluate $i ^{-34}$ .

Possible Answers:

Correct answer:

Explanation:

To raise to the power of a negative integer, first raise to the absolute value of that integer. Therefore, to find $i ^{-34}$ , we need to look at $i^{34}$ .

To raise to the power of any positive integer, divide the integer by 4 and note the remainder. The correct power is given according to the table below.

Powers of i

$34 \div 2 = 16 \textrm{ R }2$ , so $i^{34}$ can be determined by selecting the power of corresponding to remainder 2. This is .

Since $i^{34} = -1$ , and by definition, $a^{-N} = \frac{1}{a^{N}}$ , it follows that

$i^{-34} = \frac{1}{i^{34} }= \frac{1}{-1} = -1$ .

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Example Question #2101 : Mathematical Relationships And Basic Graphs

Select the complex conjugate of .

Possible Answers:

-6i

has no complex conjugate.

Correct answer:

-6i

Explanation:

can be restated in standard complex number form as

0+6i .

The complex conjugate of a complex number a+bi is a-bi , so the complex conjugate of 0+6i is 0-6i , which is equal to -6i . Therefore, -6i is the complex conjugate of .

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Example Question #2102 : Mathematical Relationships And Basic Graphs

Select the complex conjugate of .

Possible Answers:

-9i

9 has no complex conjugate.

Correct answer:

Explanation:

can be restated in standard complex number form as

-9 + 0i .

The complex conjugate of a complex number a+bi is a-bi , so the complex conjugate of -9 + 0i is -9 - 0i , which is also equal to . Therefore, itself is the complex conjugate of .

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Example Question #2103 : Mathematical Relationships And Basic Graphs

Select the complex conjugate of $2 + \frac{1}{3} i$ .

Possible Answers:

$\frac{1}{3} - 2i$

$-2 + \frac{1}{3} i$

$-2 - \frac{1}{3} i$

$2 - \frac{1}{3} i$

$\frac{1}{3} + 2i$

Correct answer:

$2 - \frac{1}{3} i$

Explanation:

The complex conjugate of a complex number a+bi is a-bi , so the complex conjugate of $2 + \frac{1}{3} i$ is $2 - \frac{1}{3} i$ .

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Example Question #2104 : Mathematical Relationships And Basic Graphs

Subtract $7 + i \sqrt{17}$ from its complex conjugate. What is the result?

Possible Answers:

$-2 i\sqrt{17}$

$2 i\sqrt{17}$

Correct answer:

$-2 i\sqrt{17}$

Explanation:

The complex conjugate of a complex number a+bi is a-bi .

Therefore, the complex conjugate of $7 + i \sqrt{17}$ is $7 - i \sqrt{17}$ . Subtract the former from the latter:

$\left (7 - i \sqrt{17} \right )-\left ( 7 + i \sqrt{17} \right )$

Collect real parts and imaginary parts:

$= 7 - 7 - i \sqrt{17} - i \sqrt{17}$

The real parts cancel out:

$= - i \sqrt{17} - i \sqrt{17}$

$= -2 i \sqrt{17}$

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Example Question #141 : Imaginary Numbers

Evaluate:

$i^{-47}$

Possible Answers:

Correct answer:

Explanation:

In order to raise to the power of a negative integer, first raise to the absolute value of that integer. Therefore, to find $i^{-47}$ , we need to look at $i^{47}$ .

To raise to the power of any positive integer, divide the integer by 4 and note the remainder. The correct power is given according to the following table:

Powers of i

$47 \div 4 = 11 \textrm{ R }3$ , so $i^{47}$ can be determined by selecting the power of corresponding to remainder 3. This is .

Since $i^{47} = -i$ , and by definition, $a^{-N} = \frac{1}{a^{N}}$ , it follows that

$i^{-47} = \frac{1}{i^{47}} = \frac{1}{-i}$

Rationalize the denominator by multiplying by , the complex conjugate:

$i^{-47} = \frac{1}{-i} = \frac{1 \cdot i}{-i \cdot i} = \frac{i}{-i^{1}} = \frac{i}{-(-1)} = \frac{i}{1} = i$

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Example Question #2105 : Mathematical Relationships And Basic Graphs

Evaluate:

$i^{64}$

Possible Answers:

Correct answer:

Explanation:

To raise to the power of any positive integer, divide the integer by 4 and note the remainder. The correct power is given according to the table below.

Powers of i

$64 \div 4 = 16\textrm{ R }0$ , so $i^{64}$ can be determined by selecting the power of corresponding to remainder 0. The corresponding power is 1, so $i^{64} = 1$ .

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Algebra II : Imaginary Numbers

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #71 : Basic Operations With Complex Numbers

Example Question #72 : Basic Operations With Complex Numbers

Example Question #2091 : Mathematical Relationships And Basic Graphs

Example Question #2092 : Mathematical Relationships And Basic Graphs

Example Question #2101 : Mathematical Relationships And Basic Graphs

Example Question #2102 : Mathematical Relationships And Basic Graphs

Example Question #2103 : Mathematical Relationships And Basic Graphs

Example Question #2104 : Mathematical Relationships And Basic Graphs

Example Question #141 : Imaginary Numbers

Example Question #2105 : Mathematical Relationships And Basic Graphs

All Algebra II Resources

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