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Algebra 1 : Binomials

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Example Questions

Example Question #3 : How To Find The Solution To A Binomial Problem

Solve in terms of :

$\frac{2}{3}x+5y=7$

Possible Answers:

$x=7+\frac{10}{3}y$

$x=7-\frac{10}{3}y$

$x=\frac{21}{2}-\frac{15}{2}y$

$x=\frac{21}{2}+\frac{15}{2}y$

Correct answer:

$x=\frac{21}{2}-\frac{15}{2}y$

Explanation:

First, isolate X by itself:

$\frac{2}{3}x+5y=7$

-5y -5y

$\frac{2}{3}x=7-5y$

Next, divide both sides by 2/3 to get X by itself:

$\frac{2}{3}\div\frac{2}{3}x=\frac{2}{3}\div\frac{7}{1}-\frac{2}{3}\div\frac{5}{1}y$

$\frac{3}{2}\cdot\frac{2}{3}x=\frac{3}{2}\cdot\frac{7}{1}-\frac{3}{2}\cdot\frac{5}{1}y$

Your answer should come out as:

$x=\frac{21}{2}-\frac{15}{2}y$

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Example Question #1 : How To Find The Solution To A Binomial Problem

Solve for in terms of :

$\frac{4}{3}x-3=\frac{2}{9}y$

Possible Answers:

$x=\frac{8}{27}y-3$

$x=\frac{-8}{27}y+3$

$x=\frac{1}{6}y-\frac{9}{4}$

$x=\frac{1}{6}y+\frac{9}{4}$

$x=\frac{8}{27}y+3$

Correct answer:

$x=\frac{1}{6}y+\frac{9}{4}$

Explanation:

First, isolate X onto one side of the equation:

$\frac{4}{3}X-3=\frac{2}{9}Y$

$\frac{4}{3}X=\frac{2}{9}Y+3$

Next, divide both sides of the equation by 4/3:

$\frac{4}{3}\div \frac{4}{3}X=\frac{4}{3}\div \frac{2}{9}Y+\frac{4}{3}\div \frac{3}{1}$

$\frac{3}{4}\cdot \frac{4}{3}X=\frac{3}{4}\cdot \frac{2}{9}Y+\frac{3}{4}\cdot \frac{3}{1}$

$X=\frac{6}{36}Y+\frac{9}{4}$

When simplified, your answer should be:

$X=\frac{1}{6}Y+\frac{9}{4}$

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Example Question #1 : How To Find The Solution To A Binomial Problem

Solve for

-1 = 6 + x

Possible Answers:

Correct answer:

Explanation:

-1 = 6 + x

-1-6 = 6+x-6

-7 = x

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Example Question #3 : How To Find The Solution To A Binomial Problem

Solve for

3 = -6 + x

Possible Answers:

Correct answer:

Explanation:

$\\3 = -6 + x \\3 + 6 = -6 + x + 6 \\9 = x$

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Example Question #3 : How To Find The Solution To A Binomial Problem

Solve for

3 = 2 - x

Possible Answers:

None of the other answers.

Correct answer:

Explanation:

$\\3 = 2 - x \\3 - 2 = 2 - x - 2\\ 1 = -x(-1) = x$

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Example Question #1 : How To Find The Solution To A Binomial Problem

Solve for

19 = 7 + x

Possible Answers:

Correct answer:

Explanation:

$\\19 = 7 + x \\ 19 - 7 = 7 + x -7 \\ 12 = x$

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Example Question #31 : Binomials

Solve for

-9 = 82 + x

Possible Answers:

None of the other answers.

Correct answer:

Explanation:

$\\-9 = 82 + x \\ -9 - 82 = 82 + x - 82 \\-91 = x$

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Example Question #32 : Binomials

Solve for

1 = -3 + x

Possible Answers:

None of the other answers.

Correct answer:

Explanation:

$\\1 = -3 + x \\1 + 3 = -3 + x + 3\\ 4 = x$

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Example Question #4 : Solving Rational Expressions

Simplify:

$\frac{2x-3}{3-2x}$

Possible Answers:

$\frac{3}{2}$

$\frac{2}{3}$

Correct answer:

Explanation:

Factor out from the numerator which gives us

$\left -(3-2x \right )$

Hence we get the following

$\frac{\left -(3-2x \right )}{3-2x}$

which is equal to

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Example Question #1 : Factoring Rational Expressions

Simplify:

$\frac{x+3}{x^{2}+6x+9}$

Possible Answers:

$\frac{1}{\left ( x+3 \right )^{2}}$

$\frac{1}{x+3}$

$\left ( x-3 \right )$

$\left ( x+3 \right )^{2}$

$\left ( x+3 \right )$

Correct answer:

$\frac{1}{x+3}$

Explanation:

If we factors the denominator we get

$\left ( x+3 \right )^{2}$

Hence the rational expression becomes equal to

$\frac{\left ( x+3 \right )}{\left ( x+3 \right )^{2}}$

which is equal to $\frac{1}{\left ( x+3 \right )}$

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Algebra 1 : Binomials

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #3 : How To Find The Solution To A Binomial Problem

Example Question #1 : How To Find The Solution To A Binomial Problem

Example Question #1 : How To Find The Solution To A Binomial Problem

Example Question #3 : How To Find The Solution To A Binomial Problem

Example Question #3 : How To Find The Solution To A Binomial Problem

Example Question #1 : How To Find The Solution To A Binomial Problem

Example Question #31 : Binomials

Example Question #32 : Binomials

Example Question #4 : Solving Rational Expressions

Example Question #1 : Factoring Rational Expressions

All Algebra 1 Resources

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