Call Now to Set Up Tutoring:

(888) 888-0446

Algebra 1 : Linear Equations

Study concepts, example questions & explanations for Algebra 1

Create An Account

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #231 : How To Solve One Step Equations

Solve for .

$\frac{x}{3}+7=9$

Possible Answers:

Correct answer:

Explanation:

In order to solve for , we need to isolate it on the left side of the equation. We will do this by performing the same operations to both sides of the given equation:

$\frac{x}{3}+7=9$

Subtract from both sides of the equation.

$\frac{x}{3}+7-7=9-7$

Simplify.

$\frac{x}{3}=2$

Multiply both sides of the equation by .

$(3)\frac{x}{3}=2(3)$

Solve

x=6

Report an Error

Example Question #231 : Algebra 1

Solve for :

$\frac{1}{2}x=6$ .

Possible Answers:

Correct answer:

Explanation:

In order to solve for in the above equation, we must isolate it on one side of the equation. We can do this by applying an operation to that is the inverse (opposite) of what's currently being applied to .

Given $\frac{1}{2}x=6$ , we see that is being multiplied by $\frac{1}{2}$ , so we need to divide both sides of the equation by $\frac{1}{2}$ (or, equivalently, multiply by ) to isolate :

$\frac{1}{2}x=6$

$(2)\frac{1}{2}x=(2)6$

x=12

Report an Error

Example Question #231 : How To Solve One Step Equations

Solve for :

5x=3 .

Possible Answers:

$\frac{3}{5}$

$-\frac{5}{3}$

None of the above

$\frac{5}{3}$

$-\frac{3}{5}$

Correct answer:

$\frac{3}{5}$

Explanation:

Given 5x=3 , we see that is being multiplied by , so we need to divide both sides of the equation by to isolate :

5x=3

$\frac{5x}{5}=\frac{3}{5}$

$x=\frac{3}{5}$

Report an Error

Example Question #234 : Linear Equations

Solve for :

x-4=10 .

Possible Answers:

Correct answer:

Explanation:

Given x-4=10 , we see that is being subtracted from , so we need to add to both sides of the equation to isolate :

x-4=10

x-4+4=10+4

x=14

Report an Error

Example Question #231 : Algebra 1

Solve for .

x+7=32

Possible Answers:

Correct answer:

Explanation:

In order to solve for , we need to isolate it on the left side of the equation. We will do this by performing the same operations to both sides of the given equation:

x+7=32

Subtract from both sides of the equation.

x+7-7=32-7

Solve.

x=25

Report an Error

Example Question #234 : How To Solve One Step Equations

Solve for .

x+14=1

Possible Answers:

Correct answer:

Explanation:

In order to solve for , we need to isolate it on the left side of the equation. We will do this by performing the same operations to both sides of the given equation:

x+14=1

Subtract from both sides of the equation.

x+14-14=1-14

Since is greater than and is negative, our answer is negative. We will treat this operation as a subtraction problem.

x=-(14-1)

Solve.

x=-13

Report an Error

Example Question #233 : Algebra 1

Solve for .

x+1.4=3.1

Possible Answers:

1.7

-1.7

4.5

-4.5

3.2

Correct answer:

1.7

Explanation:

In order to solve for , we need to isolate it on the left side of the equation. We will do this by performing the same operations to both sides of the given equation:

x+1.4=3.1

Subtract 1.4 from both sides of the equation. Remember to line-up the decimals.

x+1.4-1.4=3.1-1.4

Solve.

x=1.7

Report an Error

Example Question #234 : Algebra 1

Solve for .

x-3=21

Possible Answers:

Correct answer:

Explanation:

In order to solve for , we need to isolate it on the left side of the equation. We will do this by performing the same operations to both sides of the given equation:

x-3=21

Add to both sides of the equaton.

x-3+3=21+3

Solve.

x=24

Report an Error

Example Question #237 : How To Solve One Step Equations

Solve for .

x-15=-19

Possible Answers:

Correct answer:

Explanation:

In order to solve for , we need to isolate it on the left side of the equation. We will do this by performing the same operations to both sides of the given equation:

x-15=-19

Add to both sides of the equation.

x-15+15=-19+15

Since is greater than and is negative, our answer is negative. We will treat this operation as a subtraction problem.

x=-(19-15)

Solve.

x=-4

Report an Error

Example Question #235 : Algebra 1

Solve for .

x-9.5=1.4

Possible Answers:

10.9

-10.9

-8.1

5.7

8.1

Correct answer:

10.9

Explanation:

In order to solve for , we need to isolate it on the left side of the equation. We will do this by performing the same operations to both sides of the given equation:

x-9.5=1.4

Add 9.5 to both sides of the equation. Remember to line the decimals up.

x-9.5+9.5=1.4+9.5

Solve.

x=10.9

Report an Error

View Algebra Tutors

Vaansh
Certified Tutor

Rutgers University-New Brunswick, Bachelor of Science, Biological and Physical Sciences.

View Algebra Tutors

Jeanene
Certified Tutor

Troy University, Bachelor of Science, Science Teacher Education.

View Algebra Tutors

Mohammad
Certified Tutor

Jamia Millia Islamia, Master of Science, Physics.

All Algebra 1 Resources

10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Chemistry Tutors in Atlanta, Math Tutors in Washington DC, ISEE Tutors in Atlanta, Algebra Tutors in San Diego, Calculus Tutors in Denver, ISEE Tutors in Washington DC, LSAT Tutors in Denver, SAT Tutors in Los Angeles, MCAT Tutors in Chicago, ACT Tutors in Philadelphia

Popular Courses & Classes

LSAT Courses & Classes in Boston, GRE Courses & Classes in Denver, GRE Courses & Classes in Miami, SSAT Courses & Classes in Chicago, SAT Courses & Classes in San Diego, Spanish Courses & Classes in New York City, LSAT Courses & Classes in Chicago, Spanish Courses & Classes in Los Angeles, SSAT Courses & Classes in Denver, ACT Courses & Classes in Phoenix

Popular Test Prep

SAT Test Prep in Denver, MCAT Test Prep in San Francisco-Bay Area, MCAT Test Prep in New York City, LSAT Test Prep in Boston, ISEE Test Prep in Chicago, GRE Test Prep in Denver, MCAT Test Prep in Denver, ACT Test Prep in San Diego, ACT Test Prep in Phoenix, ISEE Test Prep in Phoenix

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra 1 : Linear Equations

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #231 : How To Solve One Step Equations

Example Question #231 : Algebra 1

Example Question #231 : How To Solve One Step Equations

Example Question #234 : Linear Equations

Example Question #231 : Algebra 1

Example Question #234 : How To Solve One Step Equations

Example Question #233 : Algebra 1

Example Question #234 : Algebra 1

Example Question #237 : How To Solve One Step Equations

Example Question #235 : Algebra 1

All Algebra 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: