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SAT II Math II : Faces, Face Area, and Vertices

Study concepts, example questions & explanations for SAT II Math II

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Example Questions

Example Question #1 : Faces, Face Area, And Vertices

A regular tetrahedron has four congruent faces, each of which is an equilateral triangle.

The total surface area of a given regular tetrahedron is 600 square centimeters. To the nearest tenth of a centimeter, what is the length of each edge?

Possible Answers:

$24.5 \textrm{ cm}$

$18.6 \textrm{ cm}$

$11.9 \textrm{ cm}$

$37.2\textrm{ cm}$

$12.2 \textrm{ cm}$

Correct answer:

$18.6 \textrm{ cm}$

Explanation:

The total surface area of the tetrahedron is 600 square centimeters; since the tetrahedron comprises four congruent faces, each has area $600 \div 4 = 150$ square centimeters.

The area of an equilateral triangle is given by the formula

$A = \frac{s^{2}\sqrt{3}}{4}$

Set A = 150 and solve for :

$\frac{s^{2}\sqrt{3}}{4} = 150$

$\frac{s^{2}\sqrt{3}}{4} \cdot \frac{4}{\sqrt{3}}=1 50 \cdot \frac{4}{\sqrt{3}}$

$s^{2} = \frac{600}{ \sqrt{3}} \approx \frac{600}{1.732} \approx 346.41$

$s \approx \sqrt{346.41} \approx 18.6$ centimeters.

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Example Question #2 : Faces, Face Area, And Vertices

A regular octahedron has eight congruent faces, each of which is an equilateral triangle.

The total surface area of a given regular octahedron is 400 square centimeters. To the nearest tenth of a centimeter, what is the length of each edge?

Possible Answers:

$11.9 \textrm{ cm}$

$14.1 \textrm{ cm}$

$10.7 \textrm{ cm}$

$21.5 \textrm{ cm}$

$23.8 \textrm{ cm}$

Correct answer:

$10.7 \textrm{ cm}$

Explanation:

The total surface area of the octahedron is 400 square centimeters; since the octahedron comprises eight congruent faces, each has area $400 \div 8 = 50$ square centimeters.

The area of an equilateral triangle is given by the formula

$A = \frac{s^{2}\sqrt{3}}{4}$

Set A = 50 and solve for :

$\frac{s^{2}\sqrt{3}}{4} = 50$

$\frac{s^{2}\sqrt{3}}{4} \cdot \frac{4}{\sqrt{3}}= 50 \cdot \frac{4}{\sqrt{3}}$

$s^{2} = \frac{200}{ \sqrt{3}} \approx \frac{200}{1.732} \approx 115.47$

$s \approx \sqrt{115.47} \approx 10.7$ centimeters.

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Example Question #1 : Faces, Face Area, And Vertices

A regular icosahedron has twenty congruent faces, each of which is an equilateral triangle.

A given regular icosahedron has edges of length four inches. Give the total surface area of the icosahedron.

Possible Answers:

$80 \sqrt{3} \textrm{ in}^{2}$

$80 \sqrt{2} \textrm{ in}^{2}$

$80 \textrm{ in}^{2}$

$40 \sqrt{3} \textrm{ in}^{2}$

$40 \sqrt{2} \textrm{ in}^{2}$

Correct answer:

$80 \sqrt{3} \textrm{ in}^{2}$

Explanation:

The area of an equilateral triangle is given by the formula

$A = \frac{s^{2}\sqrt{3}}{4}$

Since there are twenty equilateral triangles that comprise the surface of the icosahedron, the total surface area is

$SA = 20 A = 20 \cdot \frac{s^{2}\sqrt{3}}{4} = 5 s^{2}\sqrt{3}$

Substitute s = 4 :

$SA = 5 \cdot 4^{2}\sqrt{3} = 5 \cdot 16 \sqrt{3} = 80 \sqrt{3}$ square inches.

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Example Question #4 : Faces, Face Area, And Vertices

How many faces does a polyhedron with nine vertices and sixteen edges have?

Possible Answers:

Correct answer:

Explanation:

By Euler's Formula, the relationship between the number of vertices , the number of faces , and the number of edges of a polyhedron is

V + F - E = 2

Set V = 9 and E = 16 and solve for :

9 + F - 16 = 2

F - 7= 2

F = 9

The polyhedron has nine faces.

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Example Question #1 : Faces, Face Area, And Vertices

How many edges does a polyhedron with eight vertices and twelve faces have?

Possible Answers:

Insufficient information is given to answer the question.

Correct answer:

Explanation:

By Euler's Formula, the relationship between the number of vertices , the number of faces , and the number of edges of a polyhedron is

V + F - E = 2

Set V= 8 and F = 12 and solve for :

8 + 12 - E = 2

20 - E = 2

E = 18

The polyhedron has eighteen edges.

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Example Question #6 : Faces, Face Area, And Vertices

How many faces does a polyhedron with ten vertices and fifteen edges have?

Possible Answers:

Insufficient information is given to answer the question.

Correct answer:

Explanation:

By Euler's Formula, the relationship between the number of vertices , the number of faces , and the number of edges of a polyhedron is

V + F - E = 2

Set V = 10 and E = 15 and solve for :

10+ F - 15= 2

F - 5 = 2

F = 7

The polyhedron has seven faces.

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Example Question #7 : Faces, Face Area, And Vertices

How many faces does a polyhedron with ten vertices and sixteen edges have?

Possible Answers:

Correct answer:

Explanation:

By Euler's Formula, the relationship between the number of vertices , the number of faces , and the number of edges of a polyhedron is

V + F - E = 2

Set V = 10 and E = 16 and solve for :

10+ F - 16= 2

F - 6 = 2

F = 8

The polyhedron has eight faces.

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Example Question #1 : Faces, Face Area, And Vertices

A convex polyhedron with eighteen faces and forty edges has how many vertices?

Possible Answers:

Correct answer:

Explanation:

The number of vertices, edges, and faces of a convex polygon— V, E, F —are related by the Euler's formula:

V-E + F = 2

Therefore, set F = 18, E = 40 and solve for :

V-40 + 18 = 2

V-22= 2

V= 24

The polyhedron has twenty-four faces.

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Example Question #9 : Faces, Face Area, And Vertices

How many edges does a polyhedron with fourteen vertices and five faces have?

Possible Answers:

Correct answer:

Explanation:

By Euler's Formula, the relationship between the number of vertices , the number of faces , and the number of edges of a polyhedron is

V + F - E = 2 .

Set V = 14 and F = 5 and solve for :

14+5 - E = 2

19 - E = 2

E = 17

The polyhedron has seventeen edges.

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SAT II Math II : Faces, Face Area, and Vertices

Study concepts, example questions & explanations for SAT II Math II

All SAT II Math II Resources

Example Questions

Example Question #1 : Faces, Face Area, And Vertices

Example Question #2 : Faces, Face Area, And Vertices

Example Question #1 : Faces, Face Area, And Vertices

Example Question #4 : Faces, Face Area, And Vertices

Example Question #1 : Faces, Face Area, And Vertices

Example Question #6 : Faces, Face Area, And Vertices

Example Question #7 : Faces, Face Area, And Vertices

Example Question #1 : Faces, Face Area, And Vertices

Example Question #9 : Faces, Face Area, And Vertices

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