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ISEE Middle Level Math : Rectangles

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Example Question #200 : Geometry

Use the following image to answer the question:

Rectangle3

Find the area of the rectangle.

Possible Answers:

$30\text{in}^2$

$63\text{in}^2$

$54\text{in}^2$

$15\text{in}^2$

$36\text{in}^2$

Correct answer:

$54\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, let's look at the rectangle.

Rectangle3

We can see the length is 9 inches, and the width is 6 inches.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 9\text{in} \cdot 6\text{in}$

$\text{area of rectangle} = 54\text{in}^2$

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Example Question #41 : Rectangles

Find the area of a rectangle with a width of 4in and a length that is three times the width.

Possible Answers:

$14\text{in}^2$

$36\text{in}^2$

$12\text{in}^2$

$32\text{in}^2$

$48\text{in}^2$

Correct answer:

$48\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 4in. We also know the length of the rectangle is three times the width. Therefore, the length is 12in.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 12\text{in} \cdot 4\text{in}$

$\text{area of rectangle} = 48\text{in}^2$

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Example Question #42 : Rectangles

Find the area of a rectangle with a width of 9cm and a length that is two times the width.

Possible Answers:

$24\text{cm}^2$

$18\text{cm}^2$

$162\text{cm}^2$

$128\text{cm}^2$

$32\text{cm}^2$

Correct answer:

$162\text{cm}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 9cm. We also know the length of the rectangle is two times the width. Therefore, the length is 18cm.

Knowing this, we will substitute into the formula. We get

$\text{area of rectangle} = 18\text{cm} \cdot 9\text{cm}$

$\text{area of rectangle} = 162\text{cm}^2$

Report an Error

Example Question #43 : Rectangles

Find the area of a rectangle with a width of 4in and a length that is three times the width.

Possible Answers:

$17\text{in}^2$

$12\text{in}^2$

$48\text{in}^2$

$32\text{in}^2$

$24\text{in}^2$

Correct answer:

$48\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 4in. We also know the length is three times the width. Therefore, the length is 12in.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 12\text{in} \cdot 4\text{in}$

$\text{area of rectangle} = 48\text{in}^2$

Report an Error

Example Question #44 : Rectangles

Find the area of a rectangle with a width of 3cm and a length that is three times the width.

Possible Answers:

$24\text{cm}^2$

$12\text{cm}^2$

$16\text{cm}^2$

$27\text{cm}^2$

$9\text{cm}^2$

Correct answer:

$27\text{cm}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

So, we know the width of the rectangle is 3cm. We also know the length is three times the width. Therefore, the length is 9cm.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 9\text{cm} \cdot 3\text{cm}$

$\text{area of rectangle} = 27\text{cm}^2$

Report an Error

Example Question #45 : Rectangles

Find the area of a rectangle with a length of 12cm and a width that is a quarter of the length.

Possible Answers:

$16\text{cm}^2$

$36\text{cm}^2$

$48\text{cm}^2$

$25\text{cm}^2$

$30\text{cm}^2$

Correct answer:

$36\text{cm}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 12cm. We also know the width of the rectangle is a quarter of the length. To find the width, we will divide 12 by 4. Therefore, the width the 3cm.

Knowing this, we will substitute into the formula. We get

$\text{area of rectangle} = 12\text{cm} \cdot 3\text{cm}$

$\text{area of rectangle} = 36\text{cm}^2$

Report an Error

Example Question #46 : Rectangles

Find the area of a rectangle with a width of 8in and a length that is two times the width.

Possible Answers:

$128\text{in}^2$

$48\text{in}^2$

$16\text{in}^2$

$114\text{in}^2$

$20\text{in}^2$

Correct answer:

$128\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 8in. We also know the length is two times the width. Therefore, the length is 16in.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 16\text{in} \cdot 8\text{in}$

$\text{area of rectangle} = 128\text{in}^2$

Report an Error

Example Question #47 : Rectangles

Find the area of a rectangle with a length of 24in and a width that is a third of the length.

Possible Answers:

$192\text{in}^2$

$212\text{in}^2$

$72\text{in}^2$

$156\text{in}^2$

$96\text{in}^2$

Correct answer:

$192\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 24in. We also know the width is a third of the length. Therefore, the width is 8in.

Knowing this, we can substitute into the formula. We get

$A = 24\text{in} \cdot 8\text{in}$

$A = 196\text{in}^2$

Report an Error

Example Question #48 : Rectangles

Find the area of a rectangle with a width of 6in and a length that is four times the width.

Possible Answers:

$96\text{in}^2$

$121\text{in}^2$

$48\text{in}^2$

$136\text{in}^2$

$144\text{in}^2$

Correct answer:

$144\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 6in. We also know the length is four times the width. Therefore, the length is 24in.

Knowing this, we can substitute into the formula. We get

$A = 24\text{in} \cdot 6\text{in}$

$A = 144\text{in}^2$

Report an Error

Example Question #49 : Rectangles

Find the area of a rectangle with a length of 21in and a width that is a third of the length.

Possible Answers:

$126\text{in}^2$

$84\text{in}^2$

$147\text{in}^2$

$49\text{in}^2$

$63\text{in}^2$

Correct answer:

$147\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

We know the length of the rectangle is 21in. We also know the width of the rectangle is a third of the length. Therefore, the width is 7in.

Knowing this, we can substitute into the formula. We get

$A = 21\text{in} \cdot 7\text{in}$

$A = 147\text{in}^2$

Report an Error

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ISEE Middle Level Math : Rectangles

Study concepts, example questions & explanations for ISEE Middle Level Math

All ISEE Middle Level Math Resources

Example Questions

Example Question #200 : Geometry

Example Question #41 : Rectangles

Example Question #42 : Rectangles

Example Question #43 : Rectangles

Example Question #44 : Rectangles

Example Question #45 : Rectangles

Example Question #46 : Rectangles

Example Question #47 : Rectangles

Example Question #48 : Rectangles

Example Question #49 : Rectangles

All ISEE Middle Level Math Resources

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