All High School Physics Resources
Example Questions
Example Question #1 : Impulse And Momentum
A crate slides along the floor for before stopping. If it was initially moving with a velocity of , what is the force of friction?
The fastest way to solve a problem like this is with momentum.
Remember that momentum is equal to mass times velocity: . We can rewrite this equation in terms of force.
Using this transformation, we can see that momentum is also equal to force times time.
can also be thought of as .
Expand this equation to include our given values.
Since the object is not moving at the end, its final velocity is zero. Plug in the given values and solve for the force.
We would expect the answer to be negative because the force of friction acts in the direction opposite to the initial velocity.
Example Question #2 : Impulse And Momentum
A crate slides along a floor with a starting velocity of . If the force due to friction is , how long will it take for the box to come to rest?
The fastest way to solve a problem like this is with momentum.
Remember that momentum is equal to mass times velocity: . We can rewrite this equation in terms of force.
Using this transformation, we can see that momentum is also equal to force times time.
can also be thought of as .
Expand this equation to include our given values.
Since the box is not moving at the end, its final velocity is zero. Plug in the given values and solve for the time.
Example Question #3 : Impulse And Momentum
A man with a mass of m is painting a house. He stands on a tall ladder of height h. He leans over and falls straight down off the ladder. If he is in the air for s seconds, what will be his momentum right before he hits the ground?
The problem tells us he falls vertically off the ladder (straight down), so we don't need to worry about motion in the horizontal direction.
The equation for momentum is:
We can assume he falls from rest, which allows us to find the initial momentum.
.
From here, we can use the formula for impulse:
We know his initial momentum is zero, so we can remove this variable from the equation.
The problem tells us that his change in time is s seconds, so we can insert this in place of the time.
The only force acting upon man is the force due to gravity, which will always be given by the equation .
Example Question #4 : Impulse And Momentum
If an egg is dropped on concrete, it usually breaks. If an egg is dropped on grass, it may not break. What conclusion explains this result?
Grass is a softer texture
The egg is in contact with the grass for longer, so it absorbs less force
Grass has less mass than concrete
The density of grass is less than the density of concrete
The coefficient of friction of the grass on the egg is less than the coefficient of the concrete on the egg
The egg is in contact with the grass for longer, so it absorbs less force
In both cases the egg starts with the same velocity, so it has the same initial momentum. In both cases the egg stops moving at the end of its fall, so it has the same final velocity. The only thing that changes is the time and force of the impact. The force is produced by the deceleration resulting from the time that the egg is in contact with its point of impact.
As the time of contact increases, acceleration decreases and force decreases.
As the time of contact decreases, acceleration increases and force increases.
The grass will have less force on the egg, allowing for a lesser acceleration, due to a longer period of impact.
Example Question #5 : Impulse And Momentum
A tennis ball strikes a racket, moving at . After striking the racket, it bounces back at a speed of . What is the change in momentum?
The change in momentum is the final momentum minus the initial momentum, or .
Notice that the problem gives us the final SPEED of the ball but not the final VELOCITY. Since the ball "bounced back," it begins to move in the opposite direction, so its velocity at this point will be negative.
Plug in our values to solve:
Example Question #1 : Impulse And Momentum
The area under the curve on a Force versus time (F versus t) graph represents
Impulse
Kinetic energy
Momentum
Work
Impulse
If we were to examine the area under the curve of a constant force applied over a certain amount of time we would have a graph with a straight horizontal line. To find the area of that rectangle we would multiply the base times the height. The base would be the time (number of seconds the force was applied). The height would be the amount of force applied during this time. Force*time is equal to the impulse acting on the object which is equal to the change in momentum of the object.