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High School Math : Variable Relationships

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Example Questions

Example Question #2 : Graphing Data

In a standard deck of cards, with replacement, what is the probability of drawing two Ace of Hearts?

Possible Answers:

$\frac{1}{2704}$

$\frac{2}{2704}$

$\frac{2}{52}$

$\frac{1}{52}$

Correct answer:

$\frac{1}{2704}$

Explanation:

Probability of drawing first ace of hearts: $\frac{1}{52}$

Probability of drawing second ace of hearts: $\frac{1}{52}$

Multiply both probabilities by each other:

$\frac{1}{52}*\frac{1}{52}=\frac{1}{2704}$

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Example Question #3 : Basic Statistics

In a standard deck of cards, without replacement, what is the probability of drawing three kings?

Possible Answers:

$\frac{3}{13}$

$\frac{3}{52}$

$\frac{1}{5525}$

$\frac{64}{140608}$

Correct answer:

$\frac{1}{5525}$

Explanation:

Start with 52 cards, probability of drawing first king: $\frac{4}{52}$

Now you have 51 cards. Probability of drawing second king: $\frac{3}{51}$

Now you have 50 cards. Probability of drawing third king: $\frac{2}{50}$

Multiply all probabilities:

$\frac{4}{52}*\frac{3}{51}*\frac{2}{50}=\frac{24}{132,600}=\frac{1}{5525}$

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Example Question #1 : Variable Relationships

With a standard deck of cards, what is the probability of picking a spade then a red card if there is no replacement?

Possible Answers:

$\frac{17}{104}$

$\frac{19}{51}$

$\frac{23}{53}$

$\frac{13}{102}$

$\frac{11}{95}$

Correct answer:

$\frac{13}{102}$

Explanation:

In a standard deck of cards:

$52\; cards=26\; black + 26\; red$

$26\; black = 13\; spades + 13\; clubs$

$26\; red = 13\; hearts + 13\; diamonds$

$P(spade)\cdot P(red)=\frac{13}{52}\cdot \frac{26}{51}=\frac{13}{102}$

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Example Question #1 : Probability

Using a standard deck of cards, what is the probability of choosing a single face card?

Possible Answers:

$\frac{7}{13}$

$\frac{9}{13}$

$\frac{19}{26}$

$\frac{3}{13}$

$\frac{7}{26}$

Correct answer:

$\frac{3}{13}$

Explanation:

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards.

Thus the probability of choosing a single face card is $\frac{12}{52}$ or $\frac{3}{13}$ .

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High School Math : Variable Relationships

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #2 : Graphing Data

Example Question #3 : Basic Statistics

Example Question #1 : Variable Relationships

Example Question #1 : Probability

All High School Math Resources

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