All GRE Math Resources
Example Questions
Example Question #62 : Triangles
Quantity A: The perimeter of a right triangle with two short sides of 10 and 24.
Quantity B: The area of a right triangle with two short sides of 10 and 12.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
In order to find the perimeter of the right triangle in Quantity A, we must find the length of the hypotenuse. We know that by the Pythagorean theorem, the hypotenuse is equal to the square root of (102 + 242) = 100 + 576 = 676. The square root of 676 is 26, so the perimeter of the right triangle is 10 + 24 + 26 = 60.
We could also have noticed that the right triangle is similar to a 5-12-13 right triangle with a dilution ratio of 2, since the 10-24 sides are twice the length of the 5-12 sides.
The area of the right triangle is calculated with b * h / 2, with the base and height equal to the two short sides of the right triangle. 10 * 12 / 2 = 120 / 2 = 60.
Thus, the two quantities are equal.
Example Question #2 : How To Find The Perimeter Of A Right Triangle
Quantity A:
The perimeter of a right triangle with a hypotenuse of .
Quantity B:
.
The two quantities are equal.
Quantity B is greater.
The relationship cannot be determined from the information given.
Quantity A is greater.
The relationship cannot be determined from the information given.
The first step in quantitative comparison problems is to make sure they can actually be solved. Quantity B is just a number. Quantity A is a right triangle, where we're given the hypotenuse, the triangle's classification/an angle measure, and asked to find a perimeter. And we cannot.
How do we know that?
Draw a right triangle with a hypotenuse of 13. Odds are, you drew the 5/12/13, a right triangle pattern seeen in many books as being very helpful on the GRE (which, well, it is). In such a case, you probably think that the perimeter will be 30 after adding the sides together, and leave it at that.
But, hold on a second. Draw another triangle, also with a right angle and a hypotenus of 13, but this time, make the triangle isosceles. It's possible, right? You have met all the conditions Quantity A gives you in this triangle, as well, but it will have a different perimeter.
Therefore, the information in quantity A is not enough information to determine what the answer is, and that's the answer you need to put.
Example Question #4 : How To Find The Perimeter Of A Right Triangle
Quantity A:
The perimeter of an right triangle with a hypotenuse of and two equal angles.
Quantity B:
The relationship cannot be determined from the relationship given.
Quantity B is greater.
Quantity A is greater.
Both quantities are equal.
Quantity B is greater.
The first step of a quantitative comparison question is to see if the quantities can even be determined in the first place. The Quantity B is just a number, so it is already determined. In Quantity A, you must find the perimeter of a right triangle with a given side-length and two equal angles. This is determinable, since you have all three angles and a side length.
To solve Quantity A, first consider that two of the angles in the right triangle must be equal. As you cannot have multiple 90 degree angles in a triangle, then the two equal angles must be the other angles. This means they're both 45 degrees, and you have a 45-45-90 triangle. This is a special triangle, where the ratio of side:side:hypotenuse is . Since the hypotenuse is equal to , then the side lengths are both .
Quantity B is greater.
Example Question #1 : Quadrilaterals
A parallelogram has a base of and a height of . Find the area of the parallelogram.
By definition a parallelogram has two sets of opposite sides that are congruent/parallel. However to find the area of a paralleogram, you need to know the base and height lengths. Since this problem provides both the base and height measurements, apply the formula:
The solution is:
Example Question #122 : Geometry
A parallelogram has a base of and a height measurement that is the base length. Find the area of the parallelogram.
By definition a parallelogram has two sets of opposite sides that are congruent/parallel. However, to find the area of a paralleogram, you need to know the base and height lengths. Since this problem provides both the base and height measurements, apply the formula:
Before applying the formula you must find of .
The final solution is:
Example Question #123 : Geometry
A parallelogram has a base of and a height of . Find the area of the parallelogram.
By definition a parallelogram has two sets of opposite sides that are congruent/parallel. However, to find the area of a paralleogram, you need to know the base and height lengths. Since this problem provides both the base and height measurements, apply the formula:
The solution is:
Example Question #124 : Geometry
A parallelogram has a base of and a height measurement that is the base length. Find the area of the parallelogram.
A parallelogram must have two sets of opposite sides that are congruent/parallel. However, to find the area of a paralleogram, you need to know the base and height lengths. Since this problem provides both the base and height measurements, apply the formula:
Before applying the formula you must find of .
The solution is:
Example Question #125 : Geometry
Using the parallelogram shown above, find the area.
By definition a parallelogram has two sets of opposite sides that are congruent/parallel. However to find the area of a paralleogram, you need to know the base and height lengths. Since this problem provides both the base and height measurements, apply the formula:
The solution is:
Example Question #2 : Quadrilaterals
A parallelogram has a base of meters and a height measurement that is the base length. Find the area of the parallelogram.
By definition a parallelogram has two sets of opposite sides that are congruent/parallel. However, to find the area of a paralleogram, you need to know the base and height lengths. Since this problem provides both the base and height measurements, apply the formula:
Before applying the formula you must find of .
The solution is:
Example Question #3 : Quadrilaterals
A parallelogram has a base of and a height of . Find the area of the parallelogram.
A parallelogram must have two sets of opposite sides that are congruent/parallel. However, to find the area of a paralleogram, you need to know the base and height lengths. Since this problem provides both the base and height measurements, apply the formula:
The solution is:
Note: prior to applying the formula, the answer choices require you to be able to convert to , as well as to . Or, you could have converted the mixed numbers to improper fractions and then multiplied the two terms: