All GMAT Math Resources
Example Questions
Example Question #2 : Calculating The Endpoints Of A Line Segment
Consider segment with endpoint at . If the midpoint of can be found at , what are the coordinates of point ?
Recall midpoint formula:
In this case we have (x'y') and one of our other (x,y) points.
Plug and chug:
If you make this into two equations and solve you get the following.
Example Question #611 : Geometry
A line segement on the coordinate plane has endpoints and . Which of the following expressions is equal to the length of the segment?
Apply the distance formula, setting
:
Example Question #612 : Geometry
What is distance between and ?
Example Question #851 : Gmat Quantitative Reasoning
What is the distance between the points and ?
Let's plug our coordinates into the distance formula.
Example Question #852 : Gmat Quantitative Reasoning
What is the distance between the points and ?
We need to use the distance formula to calculate the distance between these two points.
Example Question #15 : Lines
Consider segment which passes through the points and .
Find the length of segment .
This question requires careful application of distance formula, which is really a modified form of Pythagorean theorem.
Plug in everthing and solve:
So our answer is 156.6
Example Question #16 : Lines
What is the length of a line segment that starts at the point and ends at the point ?
Using the distance formula for the length of a line between two points, we can plug in the given values and determine the length of the line segment by calculating the distance between the two points:
Example Question #853 : Gmat Quantitative Reasoning
Determine the equation of the line tangent to the curve at the point ?
To find the equation of a line tangent to a curve at a certain point, we first need to find the slope of the curve at that point. To find the slope of a function at any point, we need its derivative:
Now we can plug in the x value of the given point to find the slope of the function, and therefore the slope of tangent line, at that point:
Now that we have our slope, we can simply plug this value in with the given point to solve for the y intercept of the tangent line:
We have calculated the slope of the tangent line and its y intercept, so the equation for the line tangent to the curve at the point in standard form is:
Example Question #1 : Calculating The Equation Of A Tangent Line
Determine the equation of the line tangent to the following curve at the point .
First we find the slope of the tangent line by taking the derivative of the function and plugging in the -value of the point where we want to know the slope:
Now that we know the slope of the tangent line, we can plug it into the equation for a line along with the coordinates of the given point in order to calculate the -intercept:
We now have and , so we can write the equation of the tangent line:
Example Question #2 : Tangent Lines
Find the equation of a line tangent to the curve at the point .
None of the above equations
To find the equation of a line tangent to the curve at the point , we must first find the slope of the curve at the point by solving the derivative at that point:
Given the slope, we can now plug the given point and the slope at that point into the slope-intercept form of the tangent line and solve for the -intercept :
Given our slope, the chosen point, and the -intercept, we have the equation of our tangent line: