Common Core: 7th Grade Math : Use Measure of Center and Measure of Variability to Compare Populations: CCSS.Math.Content.7.SP.B.4

Study concepts, example questions & explanations for Common Core: 7th Grade Math

varsity tutors app store varsity tutors android store

Example Questions

Example Question #731 : Grade 7

Two businesses monitored their profits for a week. Which business made the most profit, and what was the average profit per day of that business? 

Screen shot 2016 03 01 at 3.18.47 pm

Possible Answers:

Business A- \(\displaystyle \$1\textup,050\)

Business B- \(\displaystyle \$1\textup,050\)

Business A- \(\displaystyle \$1\textup,060\)

Business B- \(\displaystyle \$1\textup,060\)

Correct answer:

Business B- \(\displaystyle \$1\textup,060\)

Explanation:

This is a two part problem. First, we need to find out which business made the most profit during the week. To do this, we simply add up the profits from each day:

Business A:

\(\displaystyle 1\textup,000+1\textup,200+900+1\textup,100+1\textup,050=5\textup,250\)

Business B:

\(\displaystyle 1\textup,200+800+1\textup,000+1\textup,300+1\textup,000=5\textup,300\)

Business B made the most profit, so the answer choices that said Business A made the most profit can be eliminated. 

To solve for the mean, we can take our added profits and divide them by the number of addends, which is \(\displaystyle 5\):

Business A:

\(\displaystyle \frac{5\textup,250}{5}=1\textup,050\)

Business B:

\(\displaystyle \frac{5\textup,300}{5}=1\textup,060\)

Example Question #1 : Use Measure Of Center And Measure Of Variability To Compare Populations: Ccss.Math.Content.7.Sp.B.4

Two businesses monitored their profits for a week. Which business made the most profit, and what was the average profit per day of that business? 


Screen shot 2016 03 01 at 3.42.01 pm

Possible Answers:

Business B- \(\displaystyle \$1\textup,140\)

Business A- \(\displaystyle \$924\)

Business A-\(\displaystyle \$1\textup,140\)

Business B- \(\displaystyle \$924\)

Correct answer:

Business B- \(\displaystyle \$1\textup,140\)

Explanation:

This is a two part problem. First, we need to find out which business made the most profit during the week. To do this, we simply add up the profits from each day:

Business A:

\(\displaystyle 1\textup,300+100+1\textup,900+1\textup,170+150=4\textup,620\)

Business B:

\(\displaystyle 1\textup,100+700+1\textup,500+1\textup,000+1\textup,400=5\textup,700\)

Business B made the most profit, so the answer choices that said Business A made the most profit can be eliminated. 

To solve for the mean, we can take our added profits and divide them by the number of addends, which is \(\displaystyle 5\):

Business A:

\(\displaystyle \frac{4\textup,620}{5}=924\)

Business B:

\(\displaystyle \frac{5\textup,700}{5}=1\textup,140\)

Example Question #1 : Use Measure Of Center And Measure Of Variability To Compare Populations: Ccss.Math.Content.7.Sp.B.4

Two businesses monitored their profits for a week. Which business made the most profit, and what was the average profit per day of that business? 


Screen shot 2016 03 01 at 3.49.08 pm

Possible Answers:

Business B- \(\displaystyle \$1\textup,012\)

Business A- \(\displaystyle \$1\textup,012\)

Business B- \(\displaystyle \$944\)

Business A- \(\displaystyle \$944\)

Correct answer:

Business A- \(\displaystyle \$1\textup,012\)

Explanation:

This is a two part problem. First, we need to find out which business made the most profit during the week. To do this, we simply add up the profits from each day:

Business A:

\(\displaystyle 1\textup,100+800+1\textup,600+1\textup,2700+290=5\textup,060\)

Business B:

\(\displaystyle 1\textup,000+700+1\textup,400+1\textup,340+280=4\textup,720\)

Business A made the most profit, so the answer choices that said Business B made the most profit can be eliminated. 

To solve for the mean, we can take our added profits and divide them by the number of addends, which is \(\displaystyle 5\):

Business A:

\(\displaystyle \frac{5\textup,060}{5}=1\textup,012\)

Business B:

\(\displaystyle \frac{4\textup,720}{5}=944\)

Example Question #2 : Use Measure Of Center And Measure Of Variability To Compare Populations: Ccss.Math.Content.7.Sp.B.4

Two businesses monitored their profits for a week. Which business made the most profit, and what was the average profit per day of that business? 


Screen shot 2016 03 01 at 3.55.35 pm

Possible Answers:

Business B- \(\displaystyle \$980\)

Business A- \(\displaystyle \$1\textup,068\)

Business A- \(\displaystyle \$980\)

Business B- \(\displaystyle \$1\textup,068\)

Correct answer:

Business A- \(\displaystyle \$1\textup,068\)

Explanation:

This is a two part problem. First, we need to find out which business made the most profit during the week. To do this, we simply add up the profits from each day:

Business A:

\(\displaystyle 1\textup,300+700+1\textup,800+1\textup,200+340=5\textup,340\)

Business B:

\(\displaystyle 1\textup,100+500+1\textup,600+1\textup,300+400=4\textup,900\)

Business A made the most profit, so the answer choices that said Business B made the most profit can be eliminated. 

To solve for the mean, we can take our added profits and divide them by the number of addends, which is \(\displaystyle 5\):

Business A:

\(\displaystyle \frac{5\textup,340}{5}=1\textup,068\)

Business B:

\(\displaystyle \frac{4\textup,900}{5}=980\)

Example Question #744 : Grade 7

Two businesses monitored their profits for a week. Which business made the most profit, and what was the average profit per day of that business? 


Screen shot 2016 03 01 at 4.02.21 pm

Possible Answers:

Business B- \(\displaystyle \$1\textup,282\)

Business A- \(\displaystyle \$1\textup,282\)

Business B- \(\displaystyle \$1\textup,120\)

Business A- \(\displaystyle \$1\textup,120\)

Correct answer:

Business B- \(\displaystyle \$1\textup,282\)

Explanation:

This is a two part problem. First, we need to find out which business made the most profit during the week. To do this, we simply add up the profits from each day:

Business A:

\(\displaystyle 1\textup,000+900+1\textup,800+1\textup,100+800=5\textup,600\)

Business B:

\(\displaystyle 1\textup,600+900+1\textup,700+1\textup,300+910=6\textup,410\)

Business B made the most profit, so the answer choices that said Business A made the most profit can be eliminated. 

To solve for the mean, we can take our added profits and divide them by the number of addends, which is \(\displaystyle 5\):

Business A:

\(\displaystyle \frac{5\textup,600}{5}=1\textup,120\)

Business B:

\(\displaystyle \frac{6\textup,410}{5}=1\textup,282\)

Example Question #745 : Grade 7

Two businesses monitored their profits for a week. Which business made the most profit, and what was the average profit per day of that business? 


Screen shot 2016 03 01 at 4.07.13 pm

Possible Answers:

Business B-\(\displaystyle \$1\textup,155\)

Business A- \(\displaystyle \$1\textup,155\)

Business A- \(\displaystyle \$1\textup,152\)

Business B- \(\displaystyle \$1\textup,152\)

Correct answer:

Business B-\(\displaystyle \$1\textup,155\)

Explanation:

This is a two part problem. First, we need to find out which business made the most profit during the week. To do this, we simply add up the profits from each day:

Business A:

\(\displaystyle 1\textup,500+750+1\textup,260+1\textup,700+550=5\textup,760\)

Business B:

\(\displaystyle 1\textup,300+800+1\textup,330+1\textup,670+675=5\textup,775\)

Business B made the most profit, so the answer choices that said Business A made the most profit can be eliminated. 

To solve for the mean, we can take our added profits and divide them by the number of addends, which is \(\displaystyle 5\):

Business A:

\(\displaystyle \frac{5\textup,760}{5}=1\textup,152\)

Business B:

\(\displaystyle \frac{5\textup,775}{5}=1\textup,155\)

Example Question #746 : Grade 7

A teacher is comparing two students' median test scores, as show in the dot plots below. Which student had a higher median score, and what was this student's median score? 


1

2

Possible Answers:

Student B- \(\displaystyle 70\)

Student B- \(\displaystyle 80\)

Student A- \(\displaystyle 80\)

Student A- \(\displaystyle 70\)

Correct answer:

Student A- \(\displaystyle 80\)

Explanation:

The median is the middle number of a set of data points. 

To solve for the median, we list our data points in order from least to greatest, and then find the number in the middle. 

Student A:

\(\displaystyle 45,65,65,70,75,75,80,{\color{DarkOrange} 80},80,80,85,85,85,90,100\)

Student B:

\(\displaystyle 40,50,60,65,65,65,70,{\color{DarkOrange} 70},75,75,75,75,80,85,85\)

Student A has the higher median score, \(\displaystyle 80\)

Example Question #3 : Use Measure Of Center And Measure Of Variability To Compare Populations: Ccss.Math.Content.7.Sp.B.4

A teacher is comparing two students' median test scores, as show in the dot plots below. Which student had a higher median score, and what was this student's median score? 


1

2

Possible Answers:

Student A- \(\displaystyle 70\)

Student B- \(\displaystyle 65\)

Student B- \(\displaystyle 90\)

Student A- \(\displaystyle 80\)

Correct answer:

Student A- \(\displaystyle 80\)

Explanation:

The median is the middle number of a set of data points. 

To solve for the median, we list our data points in order from least to greatest, and then find the number in the middle. 

Student A:

\(\displaystyle 55,65,65,70,75,75,80,{\color{DarkOrange} 80},85,85,85,90,95,95,100\)

Student B:

\(\displaystyle 50,50,55,55,65,65,70,{\color{DarkOrange} 70},75,75,80,85,90,90,100\)

Student A has the higher median score, \(\displaystyle 80\)

Example Question #41 : Statistics & Probability

A teacher is comparing two students' median test scores, as show in the dot plots below. Which student had a higher median score, and what was this student's median score? 


1


2

Possible Answers:

Student A- \(\displaystyle 90\)

Student A- \(\displaystyle 85\)

Student B- \(\displaystyle 85\)

Student B- \(\displaystyle 90\)

Correct answer:

Student A- \(\displaystyle 90\)

Explanation:

The median is the middle number of a set of data points. 

To solve for the median, we list our data points in order from least to greatest, and then find the number in the middle. 

Student A:

\(\displaystyle 70,80,80,85,85,85,90,{\color{DarkOrange} 90},90,95,95,100,100,100,100\)

Student B:

\(\displaystyle 65,70,70,75,80,80,85,{\color{DarkOrange} 85},85,90,90,90,90,100,100\)

Student A has the higher median score, \(\displaystyle 90\)

Example Question #42 : Statistics & Probability

A teacher is comparing two students' median test scores, as show in the dot plots below. Which student had a higher median score, and what was this student's median score? 


1

2

Possible Answers:

Student A- \(\displaystyle 95\)

Student B- \(\displaystyle 80\)

Student A- \(\displaystyle 85\)

Student B- \(\displaystyle 90\)

Correct answer:

Student B- \(\displaystyle 90\)

Explanation:

The median is the middle number of a set of data points. 

To solve for the median, we list our data points in order from least to greatest, and then find the number in the middle. 

Student A:

\(\displaystyle 55,55,75,75,75,80,85,{\color{DarkOrange} 85},90,90,90,95,95,100,100\)

Student B:

\(\displaystyle 70,80,85,85,85,85,90,{\color{DarkOrange} 90},90,90,90,95,95,100,100\)

Student B has the higher median score, \(\displaystyle 90\)

Learning Tools by Varsity Tutors