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Common Core: 4th Grade Math : Solve problems involving measurement and conversion of measurements

Study concepts, example questions & explanations for Common Core: 4th Grade Math

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All Common Core: 4th Grade Math Resources

7 Diagnostic Tests 189 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1351 : Common Core Math: Grade 4

What is the length of a rectangular room with an area of 20ft^2 $\displaystyle 20ft^2$ and a width of 4ft? $\displaystyle 4ft?$

Possible Answers:

4ft $\displaystyle 4ft$

3ft $\displaystyle 3ft$

5ft $\displaystyle 5ft$

2ft $\displaystyle 2ft$

6ft $\displaystyle 6ft$

Correct answer:

5ft $\displaystyle 5ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$20=l\times 4$ $\displaystyle 20=l\times 4$

$\frac{20}{4}=\frac{l\times 4}{4}$ $\displaystyle \frac{20}{4}=\frac{l\times 4}{4}$

5=l $\displaystyle 5=l$

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Example Question #132 : Solve Problems Involving Measurement And Conversion Of Measurements

What is the length of a rectangular room with an area of 48ft^2 $\displaystyle 48ft^2$ and a width of 4ft? $\displaystyle 4ft?$

Possible Answers:

8ft $\displaystyle 8ft$

11ft $\displaystyle 11ft$

9ft $\displaystyle 9ft$

10ft $\displaystyle 10ft$

12ft $\displaystyle 12ft$

Correct answer:

12ft $\displaystyle 12ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$48=l\times 4$ $\displaystyle 48=l\times 4$

$\frac{48}{4}=\frac{l\times 4}{4}$ $\displaystyle \frac{48}{4}=\frac{l\times 4}{4}$

12=l $\displaystyle 12=l$

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Example Question #171 : Quadrilaterals

What is the length of a rectangular room with an area of 50ft^2 $\displaystyle 50ft^2$ and a width of 5ft? $\displaystyle 5ft?$

Possible Answers:

9ft $\displaystyle 9ft$

11ft $\displaystyle 11ft$

8ft $\displaystyle 8ft$

12ft $\displaystyle 12ft$

10ft $\displaystyle 10ft$

Correct answer:

10ft $\displaystyle 10ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$50=l\times 5$ $\displaystyle 50=l\times 5$

$\frac{50}{5}=\frac{l\times 5}{5}$ $\displaystyle \frac{50}{5}=\frac{l\times 5}{5}$

10=l $\displaystyle 10=l$

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Example Question #73 : How To Find The Area Of A Rectangle

What is the length of a rectangular room with an area of 80ft^2 $\displaystyle 80ft^2$ and a width of 10ft? $\displaystyle 10ft?$

Possible Answers:

10ft $\displaystyle 10ft$

7ft $\displaystyle 7ft$

8ft $\displaystyle 8ft$

9ft $\displaystyle 9ft$

11ft $\displaystyle 11ft$

Correct answer:

8ft $\displaystyle 8ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$80=l\times 10$ $\displaystyle 80=l\times 10$

$\frac{80}{10}=\frac{l\times 10}{10}$ $\displaystyle \frac{80}{10}=\frac{l\times 10}{10}$

8=l $\displaystyle 8=l$

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Example Question #131 : Solve Problems Involving Measurement And Conversion Of Measurements

What is the length of a rectangular yard with an area of 8m^2 $\displaystyle 8m^2$ and a width of 4m? $\displaystyle 4m?$

Possible Answers:

$\displaystyle 4m$

$\displaystyle 3m$

$\displaystyle 2m$

$\displaystyle 6m$

$\displaystyle 5m$

Correct answer:

$\displaystyle 2m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$8=l\times 4$ $\displaystyle 8=l\times 4$

$\frac{8}{4}=\frac{l\times 4}{4}$ $\displaystyle \frac{8}{4}=\frac{l\times 4}{4}$

2=l $\displaystyle 2=l$

Report an Error

Example Question #132 : Solve Problems Involving Measurement And Conversion Of Measurements

What is the length of a rectangular yard with an area of 12m^2 $\displaystyle 12m^2$ and a width of 4m? $\displaystyle 4m?$

Possible Answers:

$\displaystyle 5m$

$\displaystyle 6m$

$\displaystyle 3m$

$\displaystyle 4m$

$\displaystyle 2m$

Correct answer:

$\displaystyle 3m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$12=l\times 4$ $\displaystyle 12=l\times 4$

$\frac{12}{4}=\frac{l\times 4}{4}$ $\displaystyle \frac{12}{4}=\frac{l\times 4}{4}$

3=l $\displaystyle 3=l$

Report an Error

Example Question #133 : Solve Problems Involving Measurement And Conversion Of Measurements

What is the length of a rectangular yard with an area of 15m^2 $\displaystyle 15m^2$ and a width of 3m? $\displaystyle 3m?$

Possible Answers:

$\displaystyle 4m$

$\displaystyle 5m$

$\displaystyle 3m$

$\displaystyle 5m$

$\displaystyle 6m$

Correct answer:

$\displaystyle 5m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$15=l\times 3$ $\displaystyle 15=l\times 3$

$\frac{15}{3}=\frac{l\times 3}{3}$ $\displaystyle \frac{15}{3}=\frac{l\times 3}{3}$

5=l $\displaystyle 5=l$

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Example Question #51 : Solving For Length

What is the length of a rectangular yard with an area of 16m^2 $\displaystyle 16m^2$ and a width of 2m? $\displaystyle 2m?$

Possible Answers:

$\displaystyle 8m$

$\displaystyle 7m$

$\displaystyle 9m$

$\displaystyle 6m$

$\displaystyle 5m$

Correct answer:

$\displaystyle 8m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$16=l\times 2$ $\displaystyle 16=l\times 2$

$\frac{16}{2}=\frac{l\times 2}{2}$ $\displaystyle \frac{16}{2}=\frac{l\times 2}{2}$

8=l $\displaystyle 8=l$

Report an Error

Example Question #52 : Solving For Length

What is the length of a rectangular yard with an area of 20m^2 $\displaystyle 20m^2$ and a width of 5m? $\displaystyle 5m?$

Possible Answers:

$\displaystyle 3m$

$\displaystyle 1m$

$\displaystyle 5m$

$\displaystyle 4m$

$\displaystyle 2m$

Correct answer:

$\displaystyle 4m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$20=l\times 5$ $\displaystyle 20=l\times 5$

$\frac{20}{5}=\frac{l\times 5}{5}$ $\displaystyle \frac{20}{5}=\frac{l\times 5}{5}$

4=l $\displaystyle 4=l$

Report an Error

Example Question #53 : Solving For Length

What is the length of a rectangular yard with an area of 24m^2 $\displaystyle 24m^2$ and a width of 4m? $\displaystyle 4m?$

Possible Answers:

$\displaystyle 9m$

$\displaystyle 6m$

$\displaystyle 7m$

10m $\displaystyle 10m$

$\displaystyle 8m$

Correct answer:

$\displaystyle 6m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$24=l\times 4$ $\displaystyle 24=l\times 4$

$\frac{24}{4}=\frac{l\times 4}{4}$ $\displaystyle \frac{24}{4}=\frac{l\times 4}{4}$

6=l $\displaystyle 6=l$

Report an Error

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Common Core: 4th Grade Math : Solve problems involving measurement and conversion of measurements

Study concepts, example questions & explanations for Common Core: 4th Grade Math

All Common Core: 4th Grade Math Resources

Example Questions

Example Question #1351 : Common Core Math: Grade 4

Example Question #132 : Solve Problems Involving Measurement And Conversion Of Measurements

Example Question #171 : Quadrilaterals

Example Question #73 : How To Find The Area Of A Rectangle

Example Question #131 : Solve Problems Involving Measurement And Conversion Of Measurements

Example Question #132 : Solve Problems Involving Measurement And Conversion Of Measurements

Example Question #133 : Solve Problems Involving Measurement And Conversion Of Measurements

Example Question #51 : Solving For Length

Example Question #52 : Solving For Length

Example Question #53 : Solving For Length

All Common Core: 4th Grade Math Resources

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