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Calculus 2 : Calculus II

Study concepts, example questions & explanations for Calculus 2

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9 Diagnostic Tests 308 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #152 : Derivative Review

Find f'(0) for

$f(t)=t^3+2^{26t^2}$

Possible Answers:

$\log(2)$

Correct answer:

Explanation:

In order to take the derivative, we need to remember how to take derivatives of exponential functions not in base e.

Derivatives of exponential functions not in base e:

$f(x)=a^{g(x)}$

$f'(x)=g'(x)a^{g(x)}\ln(a)$

Now lets apply this to our problem.

$f(t)=t^3+2^{26t^2}$

$f'(t)=3t^2+52t\ 2^{26t^2}\ln(2)$

Now we plug in 0 to get.

$f'(0)=3(0)^2+52(0) \2^{26(0)^2}\ln(2)$

$f'(0)=0+0*1*\log(2)=0$

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Example Question #157 : Derivative Review

What is the slope of $f(x)=-x^{2}+10x-5$ at (-5,3) ?

Possible Answers:

Correct answer:

Explanation:

We define slope as the first derivative of a given function.

Since we have $f(x)=-x^{2}+10x-5$ , we can use the Power Rule

$\frac{d}{dx}x^{n}=nx^{n-1}$ for all $n\neq0$ to determine that

$f'(x)=(2)(-1)x^{2-1}+(1)10x^{1-1}-(0)5=-2x+10$ .

We also have a point (-5,3) with a -coordinate , so the slope

f'(-5)=-2(-5)+10=10+10=20 .

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Example Question #153 : Derivative Review

What is the slope of $f(x)=7x^{2}-2x+9$ at (2,0) ?

Possible Answers:

Correct answer:

Explanation:

We define slope as the first derivative of a given function.

Since we have

$f(x)=7x^{2}-2x+9$ , we can use the Power Rule

$\frac{d}{dx}x^{n}=nx^{n-1}$ for all $n\neq0$

to determine that

$f'(x)=(2)7x^{2-1}-(1)2x^{1-1}+(0)9=14x-2$ .

We also have a point (2,0) with a -coordinate , so the slope

f'(2)=14(2)-2=28-2=26 .

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Example Question #159 : Derivative Review

What is the slope of $f(x)=6x^{2}+7x+1$ at (-1,4) ?

Possible Answers:

Correct answer:

Explanation:

We define slope as the first derivative of a given function.

Since we have

$f(x)=6x^{2}+7x+1$ , we can use the Power Rule

$\frac{d}{dx}x^{n}=nx^{n-1}$ for all $n\neq0$

to determine that

$f'(x)=(2)6x^{2-1}+(1)7x^{1-1}+(0)1=12x+7$ .

We also have a point (-1,4) with a -coordinate , so the slope

f'(-1)=12(-1)+7=-12+7=-5 .

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Example Question #154 : Derivative Review

Find the derivative of the following function at x=0 :

$f(x)=2xe^{\cos(x)}$

Possible Answers:

2e^1

-2e^1

4e^1

Correct answer:

2e^1

Explanation:

The derivative of the function is

$f'(x)=2e^{\cos(x)}-2x\sin(x)e^{\cos(x)}$

and was found using the following rules:

$\frac{\mathrm{d} }{\mathrm{d} x} \cos(x)=-\sin(x)$ , $\frac{\mathrm{d} }{\mathrm{d} x} e^u=e^u\frac{\mathrm{du} }{\mathrm{d} x}$ , $\frac{\mathrm{d} }{\mathrm{d} x} f(x)g(x)=f'(x)g(x)+f(x)g'(x)$ , $\frac{\mathrm{d} }{\mathrm{d} x} x^n=nx^{n-1}$

Now, just plug zero into the first derivative function to get our answer:

f'(0)=2e^1

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Example Question #161 : Derivative Review

Evaluate the derivative of the following function at x=0 :

$f(x)=5x^4e^{\sin(x)}$

Possible Answers:

Correct answer:

Explanation:

The derivative of the function is

$f'(x)=20x^3e^{\sin(x)}+5x^4\cos(x)e^{\sin(x)}$

and was found using the following rules:

$\frac{\mathrm{d} }{\mathrm{d} x}f(x)g(x)=f'(x)g(x)+f(x)g'(x)$ , $\frac{\mathrm{d} }{\mathrm{d} x}e^u=\frac{\mathrm{du} }{\mathrm{d} x}e^u$ , $\frac{\mathrm{d} }{\mathrm{d} x}\sin(x)=\cos(x)$ , $\frac{\mathrm{d} }{\mathrm{d} x}x^n=nx^{n-1}$

To finish, plug in the point given into the first derivative function:

f'(0)=0+0=0

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Example Question #162 : Derivative Review

Find the derivative of the following function at x=2 :

$f(x)=x^2+\csc(2x)+e^\ln(x)$

Possible Answers:

$6+\csc(2x)$

$2x+\csc(2x)+\cot(2x)$

$5+2\csc(x)\cot(x)$

$5-2\csc(4)\cot(4)$

Correct answer:

$5-2\csc(4)\cot(4)$

Explanation:

The derivative of the function is:

$f'(x)=2x-2\csc(2x)\cot(2x)+1$

and was found using the following rules:

$\frac{\mathrm{d} }{\mathrm{d} x} x^n=nx^{n-1}$ , $\frac{\mathrm{d} }{\mathrm{d} x}\csc(x)=-\csc(x)\cot(x)$ , $e^{\ln(x)}=x$ , $\frac{\mathrm{d} }{\mathrm{d} x} f(g(x))=f'(g(x))\cdot g'(x)$

Now, just plug in the point x=2 into the first derivative function:

$f'(2)=5-2\csc(4)\cot(4)$

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Example Question #161 : Derivatives

What is the slope of $f(x)=2x^{2}-7x+11$ at (5,6) ?

Possible Answers:

Correct answer:

Explanation:

We define slope as the first derivative of a given function.

Since we have

$f(x)=2x^{2}-7x+11$ , we can use the Power Rule

$\frac{d}{dx}x^{n}=nx^{n-1}$ for all $n\neq0$

to determine that

$f'(x)=(2)2x^{2-1}-(1)7x^{1-1}+(0)11=4x-7$ .

We also have a point (5,6) with a -coordinate , so the slope

f'(5)=4(5)-7=20-7=13 .

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Example Question #164 : Derivative Review

What is the slope of $f(x)=-5x^{2}+\frac{1}{2}x+4$ at (2,5) ?

Possible Answers:

$\frac{39}{2}$

$\frac{2}{39}$

$-\frac{2}{39}$

$-\frac{39}{2}$

None of the above

Correct answer:

$-\frac{39}{2}$

Explanation:

We define slope as the first derivative of a given function.

Since we have

$f(x)=-5x^{2}+\frac{1}{2}x+4$ , we can use the Power Rule

$\frac{d}{dx}x^{n}=nx^{n-1}$ for all $n\neq0$

to determine that

$f'(x)=(2)(-5)x^{2-1}+(1)\frac{1}{2}x^{1-1}+(0)4=-10x+\frac{1}{2}$ .

We also have a point (2,5) with a -coordinate , so the slope

$f'(2)=-10(2)+\frac{1}{2}=-20+\frac{1}{2}=-\frac{40}{2}+\frac{1}{2}=-\frac{39}{2}$ .

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Example Question #165 : Derivative Review

What is the slope of $f(x)=\frac{1}{2}x^{2}-x+7$ at (-1,1) ?

Possible Answers:

Correct answer:

Explanation:

We define slope as the first derivative of a given function.

Since we have

$f(x)=\frac{1}{2}x^{2}-x+7$ , we can use the Power Rule

$\frac{d}{dx}x^{n}=nx^{n-1}$ for all $n\neq0$ to determine that

$f'(x)=2(\frac{1}{2}x^{2-1})-(1)x^{1-1}+(0)7=x-1$ .

We also have a point (-1,1) with a -coordinate , so the slope

f'(-1)=(-1)-1=-2 .

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Calculus 2 : Calculus II

Study concepts, example questions & explanations for Calculus 2

All Calculus 2 Resources

Example Questions

Example Question #152 : Derivative Review

Example Question #157 : Derivative Review

Example Question #153 : Derivative Review

Example Question #159 : Derivative Review

Example Question #154 : Derivative Review

Example Question #161 : Derivative Review

Example Question #162 : Derivative Review

Example Question #161 : Derivatives

Example Question #164 : Derivative Review

Example Question #165 : Derivative Review

All Calculus 2 Resources

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