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Example Questions
Example Question #81 : How To Find Solutions To Differential Equations
Which type of function solves the differential equation given.
Polynomial
Rational
Logarithmic
Exponential
Polynomial
Without doing very much, we can see that the solution to this differential equation will be such that the derivative is equal to the original function divided by .
One such type of function is a polynomial, where the derivative decreases the order of the function by , which is equivalent to dividing by .
We can also show this through integration.
First separate the variables.
Now take the integral remembering the rule for natural logs.
Thus we get,
From here recall the properties of natural logs such that .
Therefore we can rewrite our function and exponentiate it to solve for y.
.
From here, we can see that it is a polynomial.
Example Question #83 : How To Find Solutions To Differential Equations
Find the general solution to the differential equation:
To find the general solution to the seperable differential equation, we must seperate the x and dx, y and dy to seperate sides:
Now, integrate both sides (note that the two constants of integration combine to make one C):
The following rules were used for integration:
,
Finally, solve for y:
Example Question #83 : How To Find Solutions To Differential Equations
Where will have a local minimum or maximum between and ?
,
. , ,
,
,
We must find the maximums and minimumss by setting the derivative equal to zero.
The derivative of is found using the chain rule,
and the trigonometric rule of derivatives for cosine,
.
Applying the above rules we find the derivative to be,
. when , so in this case, we must divide each angle by two since we are dealing with , so .
Example Question #91 : Differential Equations
Which one of the following functions is continuous and has continuous derivative at 2?
In order for the graph to be continuous, both of the parts of the piecewise function must be equal.
For the derivative to be equal, one must take the derivatives at each part and see if this new piecwise function is equal at 2 as well.
Only
fufills both these requirements.
Remember to use the power rule to find the derivatives of the piecewise function, .
Example Question #91 : Solutions To Differential Equations
What is the derivative of at ?
Here you must use the chain rule,
and the rule for natural log,
.
First, you get
,
then using the chain on , you get
.
You must then remember the , which gives you
as the final derivative.
Plugging in gives .
Example Question #343 : Equations
Find for the equation:
Take the derivative of each term in the equation twice: with respect to and then with respect to . When taking the derivative with respect to one variable, treat the other variable as a constant.
For the function
The derivative is then
Now bring and terms to opposite sides of the equation:
Now rearraging variables gives :
Example Question #2421 : Calculus
Find for the following equation:
Given the function:
We'll be taking the derivative with respect to the variables and .
Beginning with the left side of the equation, only the variable appears and the derivative is:
Note that
Now for the right side of the equation, both and appear, so we'll utilize the chain rule giving the derivative:
Combining these gives the derivative of the original equation:
Since we're looking for , gather terms on one side of the equation and terms on the other side:
From there, separate terms once more to find :
Example Question #345 : Equations
Find for the equation:
For this problem, knowledge of the following derivatives is necessary:
To take the derivative of the equation
Let's begin with the left side. For each term, we'll take the derivative with respect to both variables and , treating the other variable as just a constant when we do so. The derivative of the left side is thus
Now moving to the right side, the derivative is:
Notice how since the term has no term, when we take the derivative with respect to we just get zero, since we're treating the as a constant.
Now we have the derived equation:
Bring and terms to opposite sides of the equation:
Now we can once more rearrange variables to find :
Example Question #346 : Equations
Find for the equation:
We'll be taking the derivative of each term in the equation
with respect to both and . When taking the derivative for one variable, treat the other variable as a constant:
Note that
Notice how is treated as a constant when taking the derivative with respect to and so goes to zero. The same happens when taking the derivative of with respect to
Now bring and terms to opposite sides of the equation:
Rearrange terms once more to find :
Example Question #347 : Equations
Find for the equation:
For this problem, note that:
To approach this problem, we'll take the derivative of each term twice: with respect to and then with respect to . When taking the derivative with respect to one variable, treat the other variable as a constant.
For the equation
The derivative is then
Now, bring and terms to opposite sides of the equation:
Finally, rearrange terms once more to get :
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