Biochemistry : Carbohydrate Metabolism

Study concepts, example questions & explanations for Biochemistry

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Example Questions

Example Question #11 : Glycolysis Enzymes

Which one of these applies to the enzyme glucokinase?

Possible Answers:

It removes a phosphate group from glucose.

It specifically phosphorylates glucose, rather than other sugars.

It has a higher affinity for glucose than does hexokinase.

It phosphorylates many different sugars, including fructose and mannose.

It is the only kinase involved in glycolysis.

Correct answer:

It specifically phosphorylates glucose, rather than other sugars.

Explanation:

Glucokinase specifically phosphorylates the six-carbon sugar glucose. It is involved in glycolysis, but only in hepatocytes; hexokinase is the main enzyme that phosphorylates glucose during the first reaction of glycolysis. Rather, glucokinase's main role is to phosphorylate glucose to glucose-1-phosphate during the process of glycogen synthesis. The other kinases involved in glycolysis is phosphofructokinase. Fructose and mannose are not phosphorylated by glucokinase. Also, note that hexokinase has a higher affinity for glucose than does glucokinase.

Example Question #21 : Carbohydrate Metabolism

Which of the following is true of phosphofructokinase (PFK)?

Possible Answers:

PFK catalyzes a reversible step in glycolysis

PFK acts to remove a phosphate group from fructose-6-phosphate

Low levels of ATP inhibit PFK

High levels of ATP inhibit PFK

PFK is the first enzyme used glycolysis

Correct answer:

High levels of ATP inhibit PFK

Explanation:

Phosphofructokinase catalyzes the third step in glycolysis transforming fructose 6-phosphate to fructose-1,6-bisphosphate.  It is an irreversible step, and it is one of the major regulatory points of glycolysis.  One way in which it controls the flow of glycolysis is that when there is a high level of ATP, PFK is inhibited.  This is because the ultimate goal of glycolysis is to make ATP.  Thus, if there is already a high level of ATP, glycolysis should slow down.

Example Question #11 : Glycolysis Enzymes

Which of the following enzymes catalyzes an unfavorable step in glycolysis?

Possible Answers:

Phosphoglycerate kinase

Enolase

Aldolase

Phosphoglycerate mutase

Hexokinase

Correct answer:

Hexokinase

Explanation:

Hexokinase catalyzes the first step of glycolysis, and this step requires the input of an ATP molecule. This step is unfavorable, but the steps catalyzed by the rest of the enzymes listed as answer choices are favorable.

Example Question #21 : Carbohydrate Metabolism

Which enzyme in glycolysis is responsible for the cleavage of a six-carbon molecule into two separate three-carbon molecules?

Possible Answers:

Enolase

Hexokinase

Phosphofructokinase

Phosphoglycerate kinase

Aldolase

Correct answer:

Aldolase

Explanation:

In the fourth step of glycolysis, the six-carbon molecule fructose-1,6-bisphosphate is cleaved into two separate three-carbon molecules: dihydroxyacetone phosphate and glyceraldehyde-3-phosphate. This is catalyzed by the enzyme, aldolase.

Example Question #11 : Glycolysis

If a cell is completely lacking in the enzyme triose phosphate isomerase, which of the following is a possible result?

Possible Answers:

Glycolysis will produce a net yield of four ATP molecules per molecule of glucose

Only one pyruvate molecule will be formed per molecule of glucose

Glycolysis will double its production of NADH

The energy investment phase of glycolysis will only require one ATP rather than two, per molecule of glucose

Glycolysis will no longer be able to function to completion

Correct answer:

Only one pyruvate molecule will be formed per molecule of glucose

Explanation:

Triose phosphate isomerase is responsible for converting dihydroxyacetone phosphate into glyceraldehyde-3-phosphate. It is glyceraldehyde-3-phosphate that continues on through glycolysis to ultimately form a pyruvate molecule. Therefore, if there is no triose phosphate isomerase, the dihydroxyacetone will be unable to continue through glycolysis. The normal net yield of 2 ATP will be halved, the production of NADH will be halved, and only 1 pyruvate molecule will be created. Glycolysis will still be able to function, and the energy investment phase will be unaffected.

Example Question #21 : Carbohydrate Metabolism

What is the role of phosphofructokinase-2 in glycolysis?

Possible Answers:

Phosphofructokinase-2 converts fructose to fructose-6-phosphate.

Phosphofructokinase-2 converts fructose-2,6-bisphosphate  to fructose-6-phosphate.

Phosphofructokinase-2 converts fructose-6-phosphate to fructose-1,6-bisphosphate.

Phosphofructokinase-2 converts fructose to fructose-2,6-bisphosphate.

Phosphofructokinase-2 converts fructose-6-phosphate to fructose-2,6-bisphosphate.

Correct answer:

Phosphofructokinase-2 converts fructose-6-phosphate to fructose-2,6-bisphosphate.

Explanation:

Phosphofructokinase-2 converts fructose-6-phosphate to fructose-2,6-bisphosphate. The product, fructose-2,6-bisphosphate activates phosphofructokinase-1, the rate limiting step in glycolysis. Phosphofructokinase-2 is regulated by insulin (activated) and glucagon (inhibited).

Example Question #21 : Carbohydrate Metabolism

In muscle, glucose-6-phosphate is a common intermediate among __________.

Possible Answers:

pentose phosphate pathway, glycogenesis, and gluconeogenesis

pentose phosphate pathways, glycogenin synthesis, and glycolysis

pentose phosphate pathway, glycogenesis, and glycolysis

glycogenesis, Krebs cycle, and glycolysis 

glycolysis and glycogenesis

Correct answer:

pentose phosphate pathway, glycogenesis, and glycolysis

Explanation:

Glucose-6-phosphate (G6P) is the first molecule of the pentose phosphate pathway where it is acted upon by glucose-6-phosphate dehydrogenase. G6P is the result of the hexokinase (first) reaction in glycolysis. What is key here is that the tissue in question is muscle. Because muscle cells lack the glucose-6-phosphatase necessary to produce free glucose from G6P, they cannot be said to perform gluconeogenesis. They do, however, perform glycogenesis through conversion of G6P to glucose-1-phosphate followed by conversion to uridine diphosphateglucose for addition to a growing molecule of glycogen. 

Example Question #21 : Glycolysis

The following are the common substrates, enzymes, and their associated products.  

In patients with a hypoglycemic crisis, the cells are not getting enough glucose for ATP production. Which of the following carbohydrates would be most beneficial during such crisis?

Possible Answers:

Lactose 

Galactose

Sucrose

Cellulose 

Maltose

Correct answer:

Sucrose

Explanation:

Sucrose is the linking of glucose and fructose. Recall from the glycolytic pathway that fructose is further downstream than glucose, and therefore would allow for faster production of ATP.  

Example Question #21 : Glycolysis

What is the major product of the first committed step of glycolysis?

Possible Answers:

Glucose

Pyruvate

Glucose-6-phosphate

Fructose-1,6-bisphosphate

Fructose-6-phosphate 

Correct answer:

Fructose-1,6-bisphosphate

Explanation:

First, we must realize that the first committed step is the first irreversible reaction of glycolysis that is unique to glycolysis (cannot lead to another process, such as the pentose phosphate pathway). This is the third step, in which fructose-6-phosphate is converted to fructose-1,6-bisphosphate (the correct answer).  

Glucose is the beginning reactant of glycolysis, and pyruvate is the final product. Glucose-6-phosphate is the product of the first step of glycolysis overall, but not of the committed step.

Example Question #1 : Glycolysis Carbohydrate Intermediates

In glycolysis, which of these reactions produce adenosine triphosphate (ATP)?

I. Conversion of 1,3-bisphosphoglycerate to 3-phosphoglycerate

II. Conversion of phosphoenolpyruvate to pyruvate

IV. Conversion of 2-phosphoglycerate to phosphoenolpyruvate.

Possible Answers:

I only

II only

I and II

I, II, and III

II and III

Correct answer:

I and II

Explanation:

Conversion of 1,3-bisphosphoglycerate to 3-phosphoglycerate is mediated by phosphoglycerate kinase. Conversion of phosphoenolpyruvate to pyruvate is mediated by pyruvate. In both these reactions adenosine diphosphate (ADP) is converted to ATP via substrate level phosphorylation. Conversion of 2-phosphoglycerate to phosphoenolpyruvate, mediated by enolase, does not produce ATP.

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