Notice that the given triangle is a right isosceles triangle. The two legs with the tick marks are the same length.

The lengths of the legs in the given triangle are then $\displaystyle 12$.

Next, find the length of the hypotenuse by using the Pythagorean Theorem.

$\displaystyle a^2+a^2=b^2$

$\displaystyle b^2=2a^2$

$\displaystyle b=a\sqrt2$

Plug in the value of the length of a leg to find the length of the hypotenuse.

$\displaystyle b=13\sqrt2$

Finally, recall how to find the perimeter of a triangle:

$\displaystyle \text{Perimeter}=a+a+b$

Plug in the values for this triangle to find its perimeter.

$\displaystyle \text{Perimeter}=13+13+13\sqrt2=44.38$

Make sure to round to two places after the decimal.

Notice that the given triangle is a right isosceles triangle. The two legs with the tick marks are the same length.

The lengths of the legs in the given triangle are then $\displaystyle 12$.

Next, find the length of the hypotenuse by using the Pythagorean Theorem.

$\displaystyle a^2+a^2=b^2$

$\displaystyle b^2=2a^2$

$\displaystyle b=a\sqrt2$

Plug in the value of the length of a leg to find the length of the hypotenuse.

$\displaystyle b=21\sqrt2$

Finally, recall how to find the perimeter of a triangle:

$\displaystyle \text{Perimeter}=a+a+b$

Plug in the values for this triangle to find its perimeter.

$\displaystyle \text{Perimeter}=21+21+21\sqrt2=71.70$

Make sure to round to two places after the decimal.

Notice that the given triangle is a right isosceles triangle. The two legs with the tick marks are the same length.

The lengths of the legs in the given triangle are then $\displaystyle 12$.

Next, find the length of the hypotenuse by using the Pythagorean Theorem.

$\displaystyle a^2+a^2=b^2$

$\displaystyle b^2=2a^2$

$\displaystyle b=a\sqrt2$

Plug in the value of the length of a leg to find the length of the hypotenuse.

$\displaystyle b=22\sqrt2$

Finally, recall how to find the perimeter of a triangle:

$\displaystyle \text{Perimeter}=a+a+b$

Plug in the values for this triangle to find its perimeter.

$\displaystyle \text{Perimeter}=22+22+22\sqrt2=75.11$

Make sure to round to two places after the decimal.

Notice that the given triangle is a right isosceles triangle. The two legs with the tick marks are the same length.

The lengths of the legs in the given triangle are then $\displaystyle 12$.

Next, find the length of the hypotenuse by using the Pythagorean Theorem.

$\displaystyle a^2+a^2=b^2$

$\displaystyle b^2=2a^2$

$\displaystyle b=a\sqrt2$

Plug in the value of the length of a leg to find the length of the hypotenuse.

$\displaystyle b=24\sqrt2$

Finally, recall how to find the perimeter of a triangle:

$\displaystyle \text{Perimeter}=a+a+b$

Plug in the values for this triangle to find its perimeter.

$\displaystyle \text{Perimeter}=24+24+24\sqrt2=81.94$

Make sure to round to two places after the decimal.

Notice that the given triangle is a right isosceles triangle. The two legs with the tick marks are the same length.

The lengths of the legs in the given triangle are then $\displaystyle 12$.

Next, find the length of the hypotenuse by using the Pythagorean Theorem.

$\displaystyle a^2+a^2=b^2$

$\displaystyle b^2=2a^2$

$\displaystyle b=a\sqrt2$

Plug in the value of the length of a leg to find the length of the hypotenuse.

$\displaystyle b=23\sqrt2$

Finally, recall how to find the perimeter of a triangle:

$\displaystyle \text{Perimeter}=a+a+b$

Plug in the values for this triangle to find its perimeter.

$\displaystyle \text{Perimeter}=23+23+23\sqrt2=78.53$

Make sure to round to two places after the decimal.

Notice that the given triangle is a right isosceles triangle. The two legs with the tick marks are the same length.

The lengths of the legs in the given triangle are then $\displaystyle 12$.

Next, find the length of the hypotenuse by using the Pythagorean Theorem.

$\displaystyle a^2+a^2=b^2$

$\displaystyle b^2=2a^2$

$\displaystyle b=a\sqrt2$

Plug in the value of the length of a leg to find the length of the hypotenuse.

$\displaystyle b=25\sqrt2$

Finally, recall how to find the perimeter of a triangle:

$\displaystyle \text{Perimeter}=a+a+b$

Plug in the values for this triangle to find its perimeter.

$\displaystyle \text{Perimeter}=25+25+25\sqrt2=85.36$

Make sure to round to two places after the decimal.

Notice that the given triangle is a right isosceles triangle. The two legs with the tick marks are the same length.

The lengths of the legs in the given triangle are then $\displaystyle 12$.

Next, find the length of the hypotenuse by using the Pythagorean Theorem.

$\displaystyle a^2+a^2=b^2$

$\displaystyle b^2=2a^2$

$\displaystyle b=a\sqrt2$

Plug in the value of the length of a leg to find the length of the hypotenuse.

$\displaystyle b=26\sqrt2$

Finally, recall how to find the perimeter of a triangle:

$\displaystyle \text{Perimeter}=a+a+b$

Plug in the values for this triangle to find its perimeter.

$\displaystyle \text{Perimeter}=26+26+26\sqrt2=88.77$

Make sure to round to two places after the decimal.

Notice that the given triangle is a right isosceles triangle. The two legs with the tick marks are the same length.

The lengths of the legs in the given triangle are then $\displaystyle 12$.

Next, find the length of the hypotenuse by using the Pythagorean Theorem.

$\displaystyle a^2+a^2=b^2$

$\displaystyle b^2=2a^2$

$\displaystyle b=a\sqrt2$

Plug in the value of the length of a leg to find the length of the hypotenuse.

$\displaystyle b=28\sqrt2$

Finally, recall how to find the perimeter of a triangle:

$\displaystyle \text{Perimeter}=a+a+b$

Plug in the values for this triangle to find its perimeter.

$\displaystyle \text{Perimeter}=28+28+28\sqrt2=95.60$

Make sure to round to two places after the decimal.

Notice that the given triangle is a right isosceles triangle. The two legs with the tick marks are the same length.

The lengths of the legs in the given triangle are then $\displaystyle 12$.

Next, find the length of the hypotenuse by using the Pythagorean Theorem.

$\displaystyle a^2+a^2=b^2$

$\displaystyle b^2=2a^2$

$\displaystyle b=a\sqrt2$

Plug in the value of the length of a leg to find the length of the hypotenuse.

$\displaystyle b=29\sqrt2$

Finally, recall how to find the perimeter of a triangle:

$\displaystyle \text{Perimeter}=a+a+b$

Plug in the values for this triangle to find its perimeter.

$\displaystyle \text{Perimeter}=29+29+29\sqrt2=99.01$

Make sure to round to two places after the decimal.

Notice that the given triangle is a right isosceles triangle. The two legs with the tick marks are the same length.

The lengths of the legs in the given triangle are then $\displaystyle 12$.

Next, find the length of the hypotenuse by using the Pythagorean Theorem.

$\displaystyle a^2+a^2=b^2$

$\displaystyle b^2=2a^2$

$\displaystyle b=a\sqrt2$

Plug in the value of the length of a leg to find the length of the hypotenuse.

$\displaystyle b=30\sqrt2$

Finally, recall how to find the perimeter of a triangle:

$\displaystyle \text{Perimeter}=a+a+b$

Plug in the values for this triangle to find its perimeter.

$\displaystyle \text{Perimeter}=30+30+30\sqrt2=102.43$

Make sure to round to two places after the decimal.