All AP Calculus BC Resources
Example Questions
Example Question #171 : Ap Calculus Bc
In order to evaluate this integral, we will need to use partial fraction decomposition.
Multiply both sides of the equation by the common denominator, which is
This means that must equal 1, and
The answer is .
Example Question #2 : Substitution Of Variables (By Parts And Simple Partial Fractions)
Integrate:
To integrate, we must first make the following substitution:
Rewriting the integral in terms of u and integrating, we get
The following rule was used to integrate:
Finally, we replace u with our original x term:
Example Question #172 : Ap Calculus Bc
The temperature of an oven is increasing at a rate degrees Fahrenheit per miniute for minutes. The initial temperature of the oven is degrees Fahrenheit.
What is the temperture of the oven at ? Round your answer to the nearest tenth.
Integrating over an interval will tell us the total accumulation, or change, in temperature over that interval. Therefore, we will need to evaluate the integral
to find the change in temperature that occurs during the first five minutes.
A substitution is useful in this case. Let. We should also express the limits of integration in terms of . When , and when Making these substitutions leads to the integral
.
To evaluate this, you must know the antiderivative of an exponential function.
In general,
.
Therefore,
.
This tells us that the temperature rose by approximately degrees during the first five minutes. The last step is to add the initial temperature, which tells us that the temperature at minutes is
degrees.
Example Question #173 : Ap Calculus Bc
Find the equation for the velocity of a particle if the acceleration of the particle is given by:
and the velocity at time of the particle is .
In order to find the velocity function, we must integrate the accleration function:
We used the rule
to integrate.
Now, we use the initial condition for the velocity function to solve for C. We were told that
so we plug in zero into the velocity function and solve for C:
C is therefore 30.
Finally, we write out the velocity function, with the integer replacing C:
Example Question #174 : Ap Calculus Bc
Find the work done by gravity exerting an acceleration of for a block down from its original position with no initial velocity.
Remember that
, where is a force measured in , is work measured in , and and are initial and final positions respectively.
The force of gravity is proportional to the mass of the object and acceleration of the object.
Since the block fell down 5 meters, its final position is and initial position is .
Example Question #1 : Initial Conditions
Evaluate the following integral and find the specific function which satisfies the given initial conditions:
Evaluate the following integral and find the specific function which satisfies the given initial conditions:
To solve this problem,we need to evaluate the given integral, then solve for our constant of integration.
Let's begin by recalling the following integration rules:
Using these two, we can integrate f(x)
SO, we get:
We are almost there, but we need to find c. To do so, plug in our initial conditions and solve:
So, our answer is:
Example Question #1 : Volume Of A Solid
Determine the volume of the solid obtained by rotating the region with the following bounds about the x-axis:
From calculus, we know the volume of an irregular solid can be determined by evaluating the following integral:
Where A(x) is an equation for the cross-sectional area of the solid at any point x. We know our bounds for the integral are x=1 and x=4, as given in the problem, so now all we need is to find the expression A(x) for the area of our solid.
From the given bounds, we know our unrotated region is bounded by the x-axis (y=0) at the bottom, and by the line y=x^2-4x+5 at the top. Because we are rotating about the x-axis, we know that the radius of our solid at any point x is just the distance y=x^2-4x+5. Now that we have a function that describes the radius of the solid at any point x, we can plug the function into the formula for the area of a circle to give us an expression for the cross-sectional area of our solid at any point:
We now have our equation for the cross-sectional area of the solid, which we can integrate from x=1 to x=4 to find its volume:
Example Question #2 : Application Of Integrals
Suppose the functions , , and form a closed region. Rotate this region across the x-axis. What is the volume?
Write the formula for cylindrical shells, where is the shell radius and is the shell height.
Determine the shell radius.
Determine the shell height. This is done by subtracting the right curve, , with the left curve, .
Find the intersection of and to determine the y-bounds of the integral.
The bounds will be from 0 to 2. Substitute all the givens into the formula and evaluate the integral.
Example Question #3 : Volume Of Cross Sections And Area Of Region
Find the volume of the solid generated by revolving the region bounded by and the -axis in the first quadrant about the -axis.
Since we are revolving a region of interest around a horizontal line , we need to express the inner and outer radii in terms of x.
Recall the formula:
The outer radius is and the inner radius is . The x-limits of the region are between and . So the volume set-up is:
Using trigonometric identities, we know that:
Hence:
Example Question #2 : Volume Of A Solid
A man fills up a cup of water by leaving it outside during a rainstorm. The rate at which the height of the cup changes is equal to . What is the height of water at ? Assume the cup is empty at .
The rate at which the height changes is , which means .
To find the height after nine seconds, we need to integrate to get .
We can multiply both sides by to get and then integrate both sides.
This gives us
.
Since the cup is empty at , so .
This means . No units were given in the problem, so leaving the answer unitless is acceptable.
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