Begin by eliminating people in the class who are not students. Subtracting 1 teacher, 1 administrator and 30 evaluators leaves 192 students.

We also need to determine the ratio of male students to total students from the information in the question. Out of every thirty-two students, thirteen are male.

Now we can set up a proportion, and solve for the number of male students.

First, pick a number for the original length and width. To make it easy, you can choose a length of 1 and width of 1, which would give it an area of 1. If we increased the length by 50% and decreased the width by 20%, then the dimensions of the new rectangle would be , which would give it an area of 1.2. Thus, the ratio of the new rectangle to the original rectangle is 6:5

First find the total number that own both motorbikes and vans of each group separately:

Group A:

Group B:

Now we have a ratio that should be:

Quantity A: To determine the parts of sugar in the dessert, we use the following process. Let's first figure out the amount of sugar in the cake.  This is 4/20.  Next, find the amount of sugar in the icing topping: 3/20.  Then, we need to account for the amount of cake and icing in the dessert. Using the fact that there are 2 parts cake and 3 parts icing, we can say that 2/5 of the dessert is cake and 3/5 is icing.  Combining this information with the amount of sugar in both the cake and the icing, we obtain: 2/5 * 4/20 + 3/5 * 3/20 = 17/100.  So, there are 17 parts of sugar in the dessert. 

Quantity B: Use the same method to find the amount of milk: 2/5 * 5/20 + 3/5 * 2/20 = 16/100. So there are 16 parts milk in the dessert. Thus, Quantity A is larger. 

For this problem, we need to find the number of employees who fall into the categories described, keeping in mind that multiple portions of the pie chart must be accommodated for. Then, we can fit them into a ratio:

For the "2 to 9 years" portion of the financial industry, include

(0.2 + 0.18)(12,000,000) = 4,560,000 workers.

For the "0 to 4 years" portion of the construction industry, include

(0.15 + 0.2)(8,000,000) = 2,800,000 workers.

Now divide and simplify to find the ratio:

4,560,000/2,800,000 = 8/5.

Since the ratios are fixed, regardless of the actual values of , , or , we can let  and

In order to convert to a form where we can relate  to , we must set the coefficient of  of each ratio equal such that the ratio can be transferred. This is done most easily by finding a common multiple of  and  (the ratio of  to  and , respectively) which is

Thus, we now have  and .

Setting the  values equal, we get , or a ratio of 

You must convert all the measurements to inches first so the fence pieces will be  

.  

For one piece of fence, it would be two posts and one fence piece 

.

For two pieces of fence, it would be three posts and two pieces of fence which would be the answer of 

.

You know that the distance between these cars is defined by the following equation: Answer "250" = 500 – 90t. This is because the cars get 90 miles closer every t hours. You want to solve for t when the distance is 150: 150 = 500 – 90t; –350 = –90t; t = ³⁵/₉. Recall, however, that the question asked for the rounded-down number of minutes; therefore, multiply your answer by 60: 35 * ⁶⁰/₉ = 233¹/₃

Rounding down, you get 233.

First we set up two equations, one for Mary and one for Todd. Mary’s money growth is represented by y = 2x + 17 (she starts with $17 so this is our y-intercept and she gains $2 weekly so this is our slope).

Todd’s money growth is represented by y = 3x + 4 (he starts with $4 so this is our y-intercept and he gains $3 weekly so this is our slope). Set these two equal and solve for x. We find that after 13 weeks they have the same amount of money. But this is not what the question asked for. They want to know how many weeks it will take before Todd has MORE than Mary. Thus the answer must be 14 weeks.

This is a plug and chug sort of problem, where choosing values is arbitrary. Suppose the generators consume 5 cubic meters of fuel per day and there are 10 generators. Then the number of days that 100 cubic meters of fuel will last is expressed as 100/5*10. Switching back to variables, that comes out to t/fg.