All GMAT Math Resources
Example Questions
Example Question #1 : Other Lines
What is the equation of a line with slope and a point ?
Since the slope and a point on the line are given, we can use the point-slope formula:
Example Question #2 : Other Lines
What is the equation of a line with slope and point ?
Since the slope and a point on the line are given, we can use the point-slope formula:
Example Question #3 : Calculating The Equation Of A Line
What is the equation of a line with slope and a point ?
Since the slope and a point on the line are given, we can use the point-slope formula:
slope: and point:
Example Question #3 : Other Lines
Find the equation of the line through the points and .
First find the slope of the equation.
Now plug in one of the two points to form an equation. Here we use (4, -2), but either point will produce the same answer.
Example Question #5 : Calculating The Equation Of A Line
Consider segment which passes through the points and .
Find the equation of in the form .
Given that JK passes through (4,5) and (144,75) we can find the slope as follows:
Slope is found via:
Plug in and calculate:
Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).
So our answer is:
Example Question #2 : Calculating The Equation Of A Line
Determine the equation of a line that has the points and ?
The equation for a line in standard form is written as follows:
Where is the slope and is the y intercept. We start by calculating the slope between the two given points using the following formula:
Now we can plug either of the given points into the formula for a line with the calculated slope and solve for the y intercept:
We now have the slope and the y intercept of the line, which is all we need to write its equation in standard form:
Example Question #7 : Calculating The Equation Of A Line
Give the equation of the line that passes through the -intercept and the vertex of the parabola of the equation
.
The -intercept of the parabola of the equation can be found by substituting 0 for :
This point is .
The vertex of the parabola of the equation has -coordinate , and its -coordinate can be found using substitution for . Setting and :
The vertex is
The line connects the points and . Its slope is
Since the line has -intercept and slope , the equation of the line is , or .