LSAT Logic Games : Grouping Games
Study concepts, example questions & explanations for LSAT Logic Games
All LSAT Logic Games Resources
Example Questions
Example Question #271 : Solving Grouping Games
The chef at a La Maison, a popular French restaurant, is famous for making nine different dishes: three beef dishes - A, B and C; three poultry dishes - L, M and N; and three fish dishes - X, Y and Z. La Maison's special tasting menu always consists of exactly five of its chef's famous dishes. Each month, the chef changes the dishes on the tasting menu, choosing from among his famous dishes in accordance with the following conditions:
There must be exactly one fish dish on the menu.
If Z is not on the menu, A cannot be on the menu.
No more than two beef dishes can be on the menu.
If both L and Y are on the menu, B cannot be on the menu.
If A is on the menu, N cannot be on the menu.
Unless both C and X are on the menu, M cannot be on the menu.
Which of the following dishes can never be chosen for any month's tasting menu?
B
A
M
X
L
A
If A is chosen, N CANNOT be chosen (fifth condition) and neither can both of B and C (third condition).
Further, if A is chosen, then Z must also be chosen (second condition) and, thus, neither X nor Y can be chosen (first condition), which means M cannot be chosen (last condition).
So, we have deduced that if A is chosen, there are five dishes that cannot also be chosen (M, N, X, Y and one of B or C), leaving only three dishes that could possibly be chosen with A (for a total of four dishes on the menu, including A). However, each menu must have exactly five dishes, so A can never be chosen.
All LSAT Logic Games Resources
