Perform Operations With Scientific Notation

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8th Grade Math › Perform Operations With Scientific Notation

Questions 1 - 10
1

A computer stores two video files. One file is $9.1\times10^8$ bytes and the other is $3.4\times10^7$ bytes. How many more bytes is the larger file than the smaller file? Write your answer in scientific notation.

$9.44\times10^8$

$5.7\times10^1$

$8.76\times10^{15}$

$8.76\times10^8$

Explanation

This question tests operations with scientific notation: multiply/divide (apply to coefficients and exponents separately), add/subtract (adjust to same exponent first). Multiplication: (2×10³)×(4×10⁵)=(2×4)×10³⁺⁵=8×10⁸ (multiply coefficients, add exponents). Division: (6×10⁸)÷(2×10⁵)=(6÷2)×10⁸⁻⁵=3×10³ (divide coefficients, subtract exponents). Addition: requires same exponent—(3×10⁵)+(2×10⁴)=3×10⁵+0.2×10⁵=3.2×10⁵ (convert 2×10⁴ to 0.2×10⁵, then add); subtraction follows similarly. For this problem, subtract $9.1×10^8$ - $3.4×10^7$; convert $3.4×10^7$ to $0.34×10^8$, then 9.1 - 0.34 = $8.76×10^8$ bytes. This correct application adjusts for subtraction by aligning exponents. A common error is subtracting exponents instead of adjusting, like $10^{8-7}$$=10^1$, leading to wrong results. Steps: (1) identify operation as subtraction, (2) for ×/÷: not applicable, (3) for +/-: adjust to same exponent first (shift decimal), (4) verify proper form (1≤a<10, 8.76 is fine), (5) include units as bytes. Common errors: mixing operation rules (subtracting exponents for subtraction like division), forgetting adjustment (coefficients outside 1-10 range), wrong exponent arithmetic.

2

A video game shows two distances on a map: $6.0\times10^6$ meters and $4.0\times10^5$ meters. What is the total distance, in scientific notation?

$6.4\times10^6$

$6.04\times10^6$

$6.0\times10^{11}$

$10.0\times10^6$

Explanation

This question tests operations with scientific notation: multiply/divide (apply to coefficients and exponents separately), add/subtract (adjust to same exponent first). Multiplication: (2×10³)×(4×10⁵)=(2×4)×10³⁺⁵=8×10⁸ (multiply coefficients, add exponents). Division: (6×10⁸)÷(2×10⁵)=(6÷2)×10⁸⁻⁵=3×10³ (divide coefficients, subtract exponents). Addition: requires same exponent—(3×10⁵)+(2×10⁴)=3×10⁵+0.2×10⁵=3.2×10⁵ (convert 2×10⁴ to 0.2×10⁵, then add). Here, add $6.0×10^6$ and $4.0×10^5$: convert $4.0×10^5$ to $0.4×10^6$, then 6.0 + 0.4 = $6.4×10^6$. This correct application adjusts the smaller exponent by moving the decimal left and increasing the exponent. A common error is adding without adjustment, like 6.0 + 4.0 = $10.0×10^{11}$ or similar mismatch. Steps: (1) identify addition, (2) for +/-: adjust to same exponent first (shift decimal), (3) verify proper form (6.4 is between 1-10), (4) units are meters but not needed in answer. Common errors: forgetting adjustment, leading to wrong exponent, or wrong arithmetic on coefficients.

3

A student measures two lengths of wire: $0.0045$ meters and $3.2\times10^{-3}$ meters. What is the total length in scientific notation?

$7.7\times10^{3}$

$7.7\times10^{-3}$

$4.82\times10^{-3}$

$0.77\times10^{-2}$

Explanation

This question tests operations with scientific notation: multiply/divide (apply to coefficients and exponents separately), add/subtract (adjust to same exponent first). Multiplication: (2×10³)×(4×10⁵)=(2×4)×10³⁺⁵=8×10⁸ (multiply coefficients, add exponents). Division: (6×10⁸)÷(2×10⁵)=(6÷2)×10⁸⁻⁵=3×10³ (divide coefficients, subtract exponents). Addition: requires same exponent—(3×10⁵)+(2×10⁴)=3×10⁵+0.2×10⁵=3.2×10⁵ (convert 2×10⁴ to 0.2×10⁵, then add). For this problem, first convert 0.0045 to $4.5×10^{-3}$, then add to $3.2×10^{-3}$, so (4.5 + 3.2) × $10^{-3}$ = 7.7 × $10^{-3}$. This correct application gives the total length in scientific notation as $7.7×10^{-3}$ meters. A common error is adding without converting to scientific notation first. Steps: (1) identify operation as addition, (2) for +/-: adjust to same exponent first (already same), (3) add coefficients, (4) verify proper form (1≤a<10, adjust if needed), (5) include units like meters. Common errors: mixing operation rules (adding exponents for addition), forgetting adjustment (coefficients outside 1-10 range), wrong exponent arithmetic.

4

A student measures two tiny lengths: $0.0045$ meters and $3.2\times10^{-3}$ meters. What is the sum, written in scientific notation?

$7.7\times10^3$

$4.82\times10^{-3}$

$7.7\times10^{-3}$

$0.77\times10^{-2}$

Explanation

This question tests operations with scientific notation: multiply/divide (apply to coefficients and exponents separately), add/subtract (adjust to same exponent first). Multiplication: (2×10³)×(4×10⁵)=(2×4)×10³⁺⁵=8×10⁸ (multiply coefficients, add exponents). Division: (6×10⁸)÷(2×10⁵)=(6÷2)×10⁸⁻⁵=3×10³ (divide coefficients, subtract exponents). Addition: requires same exponent—(3×10⁵)+(2×10⁴)=3×10⁵+0.2×10⁵=3.2×10⁵ (convert 2×10⁴ to 0.2×10⁵, then add). Here, add 0.0045 $(4.5×10^{-3}$) and $3.2×10^{-3}$: exponents match, 4.5 + 3.2 = $7.7×10^{-3}$. This correct application converts decimal to scientific notation first. A common error is adding without converting, treating as regular decimals incorrectly. Steps: (1) identify addition, (2) for +/-: adjust to same exponent (done by converting), (3) verify proper form (7.7 is fine), (4) units in meters. Common errors: not handling negative exponents properly, or coefficient sum outside 1-10 without adjustment.

5

A planet model in a classroom is scaled so that $1.5\times10^3$ km in real life becomes $3\times10^{-2}$ meters in the model. What is the product $\left(1.5\times10^3\right)\left(3\times10^{-2}\right)$ written in scientific notation?

$45\times10^{0}$

$4.5\times10^{1}$

$1.8\times10^{1}$

$4.5\times10^{-5}$

Explanation

This question tests operations with scientific notation: multiply/divide (apply to coefficients and exponents separately), add/subtract (adjust to same exponent first). Multiplication: (2×10³)×(4×10⁵)=(2×4)×10³⁺⁵=8×10⁸ (multiply coefficients, add exponents). Division: (6×10⁸)÷(2×10⁵)=(6÷2)×10⁸⁻⁵=3×10³ (divide coefficients, subtract exponents). Addition: requires same exponent—(3×10⁵)+(2×10⁴)=3×10⁵+0.2×10⁵=3.2×10⁵ (convert 2×10⁴ to 0.2×10⁵, then add). For this problem, multiply $1.5×10^3$ by $3×10^{-2}$, so (1.5 × 3) × 10^(3-2) = 4.5 × $10^1$. This correct application gives the product in scientific notation as $4.5×10^1$. A common error is adding exponents instead of subtracting the negative one. Steps: (1) identify operation as multiplication, (2) for ×/÷: coefficients and exponents separately, (3) multiply coefficients and add exponents (including negatives), (4) verify proper form (1≤a<10, here it's fine), (5) no units here. Common errors: mixing operation rules (adding exponents for addition), forgetting adjustment (coefficients outside 1-10 range), wrong exponent arithmetic.

6

A science club counted two types of bacteria in a petri dish: $3.6\times10^5$ bacteria of type A and $4.9\times10^5$ bacteria of type B. What is the total number of bacteria, in scientific notation?

$8.5\times10^0$

$0.85\times10^6$

$8.5\times10^5$

$8.5\times10^{10}$

Explanation

This question tests operations with scientific notation: multiply/divide (apply to coefficients and exponents separately), add/subtract (adjust to same exponent first). Multiplication: (2×10³)×(4×10⁵)=(2×4)×10³⁺⁵=8×10⁸ (multiply coefficients, add exponents). Division: (6×10⁸)÷(2×10⁵)=(6÷2)×10⁸⁻⁵=3×10³ (divide coefficients, subtract exponents). Addition: requires same exponent—(3×10⁵)+(2×10⁴)=3×10⁵+0.2×10⁵=3.2×10⁵ (convert 2×10⁴ to 0.2×10⁵, then add). Here, add $3.6×10^5$ and $4.9×10^5$: since exponents match, sum coefficients 3.6 + 4.9 = 8.5, so $8.5×10^5$. This correct application gives the total bacteria count directly without adjustment. A common error is adding exponents like in multiplication, yielding $8.5×10^{10}$. Steps: (1) identify addition, (2) for +/-: adjust to same exponent first (not needed here), (3) verify proper form (1≤a<10, 8.5 is fine), (4) no units given. Common errors: mixing rules by adding exponents, or not converting if exponents differed.

7

A student simplifies the expression for a science project: $$\frac{\left(4.8\times10^7\right)\left(2.5\times10^{-3}\right)}{6\times10^2}.$$ What is the value in scientific notation?

$2.0\times10^2$

$20\times10^1$

$2.0\times10^{0}$

$2.0\times10^{-2}$

Explanation

This question tests operations with scientific notation: multiply/divide (apply to coefficients and exponents separately), add/subtract (adjust to same exponent first). Multiplication: $(2\times10^3)\times(4\times10^5)=(2\times4)\times10^{3+5}=8\times10^8$ (multiply coefficients, add exponents). Division: $(6\times10^8)\div(2\times10^5)=(6\div2)\times10^{8-5}=3\times10^3$ (divide coefficients, subtract exponents). Addition: requires same exponent—$(3\times10^5)+(2\times10^4)=3\times10^5+0.2\times10^5=3.2\times10^5$ (convert $2\times10^4$ to $0.2\times10^5$, then add). For this problem, compute numerator $(4.8\times10^7)(2.5\times10^{-3}) = 1.2\times10^5$, then divide by $6\times10^2$ to get $2.0\times10^2$. This correct application simplifies the expression in scientific notation as $2.0\times10^2$. A common error is mishandling the exponents in combined operations. Steps: (1) identify operations as multiplication then division, (2) for $\times$/÷: coefficients and exponents separately, (3) handle numerator first, then divide, (4) verify proper form ($1\leq a<10$, adjust if needed), (5) no units here. Common errors: mixing operation rules (adding exponents for addition), forgetting adjustment (coefficients outside 1-10 range), wrong exponent arithmetic.

8

A science class measured two distances for a model rocket launch: $6.0\times10^6$ cm and $4.0\times10^5$ cm. Find the total distance, written in scientific notation.

$10.0\times10^6$

$1.0\times10^{12}$

$6.4\times10^6$

$6.04\times10^6$

Explanation

This question tests operations with scientific notation: multiply/divide (apply to coefficients and exponents separately), add/subtract (adjust to same exponent first). Multiplication: (2×10³)×(4×10⁵)=(2×4)×10³⁺⁵=8×10⁸ (multiply coefficients, add exponents). Division: (6×10⁸)÷(2×10⁵)=(6÷2)×10⁸⁻⁵=3×10³ (divide coefficients, subtract exponents). Addition: requires same exponent—(3×10⁵)+(2×10⁴)=3×10⁵+0.2×10⁵=3.2×10⁵ (convert 2×10⁴ to 0.2×10⁵, then add). For this problem, add $6.0×10^6$ and $4.0×10^5$; convert $4.0×10^5$ to $0.4×10^6$, then sum: 6.0 + 0.4 = $6.4×10^6$ cm. This correct application involves adjusting the smaller exponent by moving the decimal left and increasing the exponent. A common error is adding without adjustment, like 6.0 + 4.0 = $10.0×10^{something}$, but that ignores exponents. Steps: (1) identify operation as addition, (2) for ×/÷: not applicable, (3) for +/-: adjust to same exponent first (shift decimal), (4) verify proper form (1≤a<10, 6.4 is fine), (5) include units if given, here cm but not in final answer. Common errors: mixing operation rules (adding exponents for addition), forgetting adjustment (coefficients outside 1-10 range), wrong exponent arithmetic.

9

A microscope slide has $6\times10^8$ cells spread evenly across $2\times10^5$ tiny squares on a grid. About how many cells are in each square? Write your answer in scientific notation.

$3\times10^3$

$12\times10^3$

$3\times10^{13}$

$3\times10^4$

Explanation

This question tests operations with scientific notation: multiply/divide (apply to coefficients and exponents separately), add/subtract (adjust to same exponent first). Multiplication: (2×10³)×(4×10⁵)=(2×4)×10³⁺⁵=8×10⁸ (multiply coefficients, add exponents). Division: (6×10⁸)÷(2×10⁵)=(6÷2)×10⁸⁻⁵=3×10³ (divide coefficients, subtract exponents). Addition: requires same exponent—(3×10⁵)+(2×10⁴)=3×10⁵+0.2×10⁵=3.2×10⁵ (convert 2×10⁴ to 0.2×10⁵, then add). For this problem, divide $6×10^8$ by $2×10^5$, so (6 ÷ 2) × 10^(8-5) = 3 × $10^3$. This correct application estimates cells per square in scientific notation as $3×10^3$. A common error is adding exponents instead of subtracting for division. Steps: (1) identify operation as division, (2) for ×/÷: coefficients and exponents separately, (3) divide coefficients and subtract exponents, (4) verify proper form (1≤a<10, here it's fine), (5) no units specified. Common errors: mixing operation rules (adding exponents for addition), forgetting adjustment (coefficients outside 1-10 range), wrong exponent arithmetic.

10

A sports field is $1.2\times10^2$ meters long. A student walks the length of the field $3.5\times10^1$ times. How many meters does the student walk in total? Write your answer in scientific notation.

$4.2\times10^1$

$42\times10^2$

$4.2\times10^3$

$4.7\times10^3$

Explanation

This question tests operations with scientific notation: multiply/divide (apply to coefficients and exponents separately), add/subtract (adjust to same exponent first). Multiplication: (2×10³)×(4×10⁵)=(2×4)×10³⁺⁵=8×10⁸ (multiply coefficients, add exponents). Division: (6×10⁸)÷(2×10⁵)=(6÷2)×10⁸⁻⁵=3×10³ (divide coefficients, subtract exponents). Addition: requires same exponent—(3×10⁵)+(2×10⁴)=3×10⁵+0.2×10⁵=3.2×10⁵ (convert 2×10⁴ to 0.2×10⁵, then add). For this problem, multiply $1.2×10^2$ by $3.5×10^1$, so (1.2 × 3.5) × 10^(2+1) = 4.2 × $10^3$. This correct application gives the total distance in scientific notation as $4.2×10^3$ meters. A common error is subtracting exponents instead of adding for multiplication. Steps: (1) identify operation as multiplication, (2) for ×/÷: coefficients and exponents separately, (3) multiply coefficients and add exponents, (4) verify proper form (1≤a<10, here it's fine), (5) include units like meters. Common errors: mixing operation rules (adding exponents for addition), forgetting adjustment (coefficients outside 1-10 range), wrong exponent arithmetic.

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