How to find slope - SSAT Upper Level Quantitative

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Find the slope of the line that passes through the points and .

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To find the slope of the line that passes through the given points, you can use the slope equation.

$\text{Slope}$=\frac{y_2-y_1}{x_2-x_1}$

$\text{Slope}$=\frac{3-b}{2-a}$

What is the slope of the line that passes through the points $(-1,4) $\text{ and }$ (-5,1)$ ?

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Use the following formula to find the slope:

$\text{Slope}$=\frac{y_2-y_1}{x_2-x_1}$

Substituting the values from the points given, we get the following slope:

$\text{Slope}$=\frac{1-4}{-5-(-1)}$=\frac{-3}{-4}$=\frac{3}{4}$

Find the slope of a line that passes through the points and .

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To find the slope of the line that passes through the given points, you can use the slope equation.

$\text{Slope}$=\frac{y_2-y_1}{x_2-x_1}$

$\text{Slope}$=\frac{-1-2}{-2-17}$=\frac{-3}{-19}$=\frac{3}{19}$

What is the slope of the line with the equation

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To find the slope, put the equation in the form of .

$y=-$\frac{2}{3}$x-3$

Since $m=-$\frac{2}{3}$$ , that is the value of the slope.

A line has the equation . What is the slope of this line?

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You need to put the equation in form before you can easily find out its slope.

$y=\frac{5}{9}$x-$\frac{4}{3}$$

Since $m=\frac{5}{9}$$ , that must be the slope.

Find the slope of the line that goes through the points and .

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Even though there are variables involved in the coordinates of these points, you can still use the slope formula to figure out the slope of the line that connects them.

$\text{Slope}$=\frac{y_2-y_1}{x_2-x_1}$

$\text{Slope}$=\frac{-9s-8s}{2t-4t}$=\frac{-17s}{-2t}$=\frac{17s}{2t}$

The equation of a line is . Find the slope of this line.

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To find the slope, you will need to put the equation in form. The value of will be the slope.

Subtract from either side:

Divide each side by :

$y=\frac{3}{2}$x-$\frac{3}{4}$$

You can now easily identify the value of .

$m=\frac{3}{2}$$

Find the slope of the line that passes through the points and .

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You can use the slope formula to figure out the slope of the line that connects these two points. Just substitute the specified coordinates into the equation and then subtract:

$\text{Slope}$=\frac{y_2-y_1}{x_2-x_1}$

$\text{Slope}$=\frac{3-1}{0-8}$=\frac{2}{-8}$=-$\frac{1}{4}$

Find the slope of the following function:

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Rewrite the equation in slope-intercept form, .

$$\frac{2x-3}{6}$=y$

$y=\frac{1}{3}$x-$\frac{1}{2}$$

The slope is the term, which is $\frac{1}{3}$ .

Find the slope of the line given the two points: $(5,8) \textup{ and } (-3,-7)$

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Write the formula to find the slope.

$m=\frac{y_2-y_1}{x_2-x_1}$=\frac{y_1-y_2}{x_1-x_2}$$

Either equation will work. Let's choose the latter. Substitute the points.

$m=\frac{y_1-y_2}{x_1-x_2}$=\frac{8-(-7)}{5-(-3)}$= $\frac{15}{8}$$

Consider the line of the equation . The line of a function has the same slope as that of . Which of the following could be the definition of ?

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The definition of is written in slope-intercept form , in which , the coefficient of , is the slope of its line. , so the slope of its line is .

We must select the choice whose line has this slope. The definition of in each choice is also written in slope-intercept form, so we select the alternative with -coefficient 5; the only such alternative is .

What is the slope of the line that passes through the points $(-1,4) $\text{ and }$ (-5,1)$ ?

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Use the following formula to find the slope:

$\text{Slope}$=\frac{y_2-y_1}{x_2-x_1}$

Substituting the values from the points given, we get the following slope:

$\text{Slope}$=\frac{1-4}{-5-(-1)}$=\frac{-3}{-4}$=\frac{3}{4}$

Find the slope of a line that passes through the points and .

Tap to see back →

To find the slope of the line that passes through the given points, you can use the slope equation.

$\text{Slope}$=\frac{y_2-y_1}{x_2-x_1}$

$\text{Slope}$=\frac{-1-2}{-2-17}$=\frac{-3}{-19}$=\frac{3}{19}$

Find the slope of the line that passes through the points and .

Tap to see back →

To find the slope of the line that passes through the given points, you can use the slope equation.

$\text{Slope}$=\frac{y_2-y_1}{x_2-x_1}$

$\text{Slope}$=\frac{3-b}{2-a}$

What is the slope of the line with the equation

Tap to see back →

To find the slope, put the equation in the form of .

$y=-$\frac{2}{3}$x-3$

Since $m=-$\frac{2}{3}$$ , that is the value of the slope.

A line has the equation . What is the slope of this line?

Tap to see back →

You need to put the equation in form before you can easily find out its slope.

$y=\frac{5}{9}$x-$\frac{4}{3}$$

Since $m=\frac{5}{9}$$ , that must be the slope.

Find the slope of the line that goes through the points and .

Tap to see back →

Even though there are variables involved in the coordinates of these points, you can still use the slope formula to figure out the slope of the line that connects them.

$\text{Slope}$=\frac{y_2-y_1}{x_2-x_1}$

$\text{Slope}$=\frac{-9s-8s}{2t-4t}$=\frac{-17s}{-2t}$=\frac{17s}{2t}$

The equation of a line is . Find the slope of this line.

Tap to see back →

To find the slope, you will need to put the equation in form. The value of will be the slope.

Subtract from either side:

Divide each side by :

$y=\frac{3}{2}$x-$\frac{3}{4}$$

You can now easily identify the value of .

$m=\frac{3}{2}$$

Find the slope of the line that passes through the points and .

Tap to see back →

You can use the slope formula to figure out the slope of the line that connects these two points. Just substitute the specified coordinates into the equation and then subtract:

$\text{Slope}$=\frac{y_2-y_1}{x_2-x_1}$

$\text{Slope}$=\frac{3-1}{0-8}$=\frac{2}{-8}$=-$\frac{1}{4}$

Find the slope of the following function:

Tap to see back →

Rewrite the equation in slope-intercept form, .

$$\frac{2x-3}{6}$=y$

$y=\frac{1}{3}$x-$\frac{1}{2}$$

The slope is the term, which is $\frac{1}{3}$ .