Properties of Triangles - SSAT Upper Level Quantitative

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The perimeter of an equilateral triangle is 39 meters. In meters, how long is one side of the triangle?

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An equilateral triangle has sides that are the same length. Then, to find the length of one side, you only need to divide the perimeter by 3.

$39\div3=13$

The perimeter of an equilateral triangle is . What is the length of one side of the triangle?

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Since an equilateral triangle has sides that are all the same, divide the perimeter by to get the length of each side.

$120t\div3=40t$

The perimeter of an equilateral triangle is . What is the length of one side of this triangle?

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Since an equilateral triangle has three equal sides, divide the perimeter by to find the length of each side.

$$\frac{75c+12}{3}$=25c+4$

The perimeter of an equilateral triangle is . What is the length of one side of this triangle?

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Since an equilateral triangle has three equal sides, divide the perimeter by to find the length of one side.

$$\frac{24d-18}{3}$=8d-6$

What is the difference between an equilateral triangle and a scalene triangle?

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Of the choices listed, the main difference between an equilateral triangle and a scalene triangle is their side lengths. An equilateral triangle has to have equal sides, but a scalene triangle can have all different side lengths.

The length of a side in a equilateral triangle is . Find the perimeter of this triangle.

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Since an equilateral triangle has side lengths that are all the same, multiply the length of one side by to find the perimeter.

Find the degree measure of in the right triangle below.

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The total number of degrees in a triangle is .

While is provided as the measure of one of the angles in the diagram, you are also told that the triangle is a right triangle, meaning that it must contain a angle as well. To find the value of , subtract the other two degree measures from .

One angle of a right triangle has measure . Give the measures of the other two angles.

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One of the angles of a right triangle is by definition a right, or , angle, so this is the measure of one of the missing angles. Since the measures of the angles of a triangle total , if we let the measure of the third angle be , then:

The other two angles measure $22 ^{\circ }, $90^{\circ }$$ .

One angle of a right triangle has measure . Give the measures of the other two angles.

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A right triangle must have one right angle and two acute angles; this means that no angle of a right triangle can be obtuse. But since , it is obtuse. This makes it impossible for a right triangle to have a angle.

What is the main difference between a right triangle and an isosceles triangle?

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By definition, a right triangle has to have one right angle, or a angle, and an isosceles triangle has equal base angles and two equal side lengths.

Find the angle value of .

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All the angles in a triangle must add up to 180 degrees.

Find the angle value of .

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All the angles in a triangle adds up to .

Find the angle value of .

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All the angles in a triangle add up to degrees.

Find the angle measure of .

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All the angles in a triangle add up to .

$\bigtriangleup ABC \cong \bigtriangleup DEF$ , where $\angle B$ is a right angle, , and .

Which of the following is true?

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$\bigtriangleup ABC \cong \bigtriangleup DEF$ , and corresponding parts of congruent triangles are congruent.

Since $\angle B$ is a right angle, so is $\angle E$ . and ; since , it follows that . $\bigtriangleup DEF$ is an isosceles right triangle; consequently, $m \angle A = m \angle C = $45^{\circ }$$ .

$\bigtriangleup DEF$ is a 45-45-90 triangle with hypotenuse of length . By the 45-45-90 Triangle Theorem, the length of each leg is equal to that of the hypotenuse divided by $\sqrt{2}$ ; therefore,

$DE=EF = $\frac{DF}{\sqrt{2}$} = $\frac{20}{\sqrt{2}$} =\frac{20 \cdot \sqrt{2}$}{$\sqrt{2}$ \cdot $\sqrt{2}$} = $\frac{20 \sqrt{2}$}{2} = 10 $\sqrt{2}$$

$DE = 20$\sqrt{2}$$ is eliminated as the correct choice.

Also, the perimeter of $\bigtriangleup DEF$ is

$P = DE+EF+DF = 10 $\sqrt{2}$ + 10 $\sqrt{2}$ + 20 = 20+ 20 $\sqrt{2}$ \ne 40$ .

This eliminates the perimeter of $\bigtriangleup DEF$ being 40 as the correct choice.

Also, $m \angle F = $60^{\circ }$$ is eliminated as the correct choice, since the triangle is 45-45-90.

The area of $\bigtriangleup DEF$ is half the product of the lengths of its legs:

$A = $\frac{1}{2}$ \cdot DE \cdot EF$

$= $\frac{1}{2}$ \cdot 10 $\sqrt{2}$\cdot 10 $\sqrt{2}$$

$= $\frac{1}{2}$ \cdot 10\cdot 10 \cdot $\sqrt{2}$ \cdot $\sqrt{2}$$

$= $\frac{1}{2}$ \cdot 10\cdot 10 \cdot 2$

The correct choice is the statement that $\bigtriangleup DEF$ has area 100.

Given: $\bigtriangleup ABC$ and $\bigtriangleup DEF$ with right angles $\angle B$ and $\angle E$ ; $\angle A \cong \angle D$ .

Which of the following statements alone, along with this given information, would prove that $\bigtriangleup ABC \cong \bigtriangleup DEF$ ?

I) $\overline{AB }$ \cong $\overline{DE}$

II) $\overline{BC }$\cong $\overline{EF}$

III) $\overline{AC }$ \cong $\overline{DF}$

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$\angle A \cong \angle D$ ; $\angle B \cong \angle E$ since both are right angles.

Given that two pairs of corresponding angles are congruent and any one side of corresponding sides is congruent, it follows that the triangles are congruent. In the case of Statement I, the included sides are congruent, so by the Angle-Side-Angle Congruence Postulate, $\bigtriangleup ABC \cong \bigtriangleup DEF$ . In the case of the other two statements, a pair of nonincluded sides are congruent, so by the Angle-Angle-Side Congruence Theorem, $\bigtriangleup ABC \cong \bigtriangleup DEF$ . Therefore, the correct choice is I, II, or III.

Given:

$\bigtriangleup ABC$ , where $\angle B$ is a right angle; ;

$\bigtriangleup DEF$ , where $\angle E$ is a right angle and ;

$\bigtriangleup GHI$ , where $\angle H$ is a right angle and $\bigtriangleup GHI$ has perimeter 60;

$\bigtriangleup JKL$ , where $\angle K$ is a right angle and $\bigtriangleup JKL$ has area 120;

$\bigtriangleup MNO$ , where $\angle N$ is a right triangle and $\angle M \cong \angle A$

Which of the following must be a false statement?

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$\bigtriangleup ABC$ has as its leg lengths 10 and 24, so the length of its hypotenuse, $\overline{AC}$ , is

$AC = $$\sqrt{(AB)^{2}$$$+(BC)^{2}$} = $$\sqrt{10^{2}$$$+24^{2}$} = $\sqrt{100+576}$ = $\sqrt{676 }$ = 26$

Its perimeter is the sum of its sidelengths:

Its area is half the product of the lengths of its legs:

$A = $\frac{1}{2}$ \cdot 10 \cdot 24 = 120$

$\bigtriangleup GHI$ and $\bigtriangleup JKL$ have the same perimeter and area, respectively, as $\bigtriangleup ABC$ ; also, between $\bigtriangleup MNO$ and $\bigtriangleup ABC$ , corresponding angles are congruent. In the absence of other information, none of these three triangles can be eliminated as being congruent to $\bigtriangleup ABC$ .

However, and . Therefore, $\overline{AC}$ \ncong $\overline{DF}$ . Since a pair of corresponding sides is noncongruent, it follows that $\bigtriangleup DEF \ncong \bigtriangleup ABC$ .

If a right triangle is similar to a right triangle, which of the other triangles must also be a similar triangle?

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For the triangles to be similar, the dimensions of all sides must have the same ratio by dividing the 3-4-5 triangle.

The 6-8-10 triangle will have a scale factor of 2 since all dimensions are doubled the original 3-4-5 triangle.

The only correct answer that will yield similar ratios is the triangle with a scale factor of 4 from the 3-4-5 triangle.

The other answers will yield different ratios.

What is the area of a right triangle whose hypotenuse is 13 inches and whose legs each measure a number of inches equal to an integer?

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We are looking for a Pythagorean triple - that is, three integers that satisfy the relationship . We know that , and the only Pythagorean triple with is . The legs of the triangle are therefore 5 and 12, and the area of the right triangle is

$A = $\frac{1}{2}$ bh= $\frac{1}{2}$ \cdot 5\cdot 12 = 30$

Right Triangle A has legs of lengths 10 inches and 14 inches; Right Triangle B has legs of length 20 inches and 13 inches; Rectangle C has length 30 inches. The area of Rectangle C is the sum of the areas of the two right triangles. What is the height of Rectangle C?

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The area of a right triangle is half the product of its legs. The area of Right Triangle A is equal to $$\frac{1}{2}$ \times 10 \times 14 = 70$ square inches; that of Right Triangle B is equal to $$\frac{1}{2}$ \times 20 \times 13 = 130$ square inches. The sum of the areas is square inches, which is the area of Rectangle C.

The area of a rectangle is the product of its length and its height. Therefore, the height is the quotient of the area and the length, which, for Rectangle C, is $200 \div 30 = 6 $\frac{2}{3}$$ inches.