New SAT Math - Calculator - SAT Math
Card 0 of 1994

What is the average number of apples a student has?
What is the average number of apples a student has?
To calculate the average number of apples a student has, the following formula is used.

First, calculate the total number of apples there are. To do this multiply the number of apples by the number of students that have that many apples.


This number divided by the total number of students.

To calculate the average number of apples a student has, the following formula is used.
First, calculate the total number of apples there are. To do this multiply the number of apples by the number of students that have that many apples.
This number divided by the total number of students.
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The equation
represents a line. This line does NOT pass through which of the four quadrants?
The equation represents a line. This line does NOT pass through which of the four quadrants?
Plug in
for
to find a point on the line:


Thus,
is a point on the line.
Plug in
for
to find a second point on the line:


is another point on the line.
Now we know that the line passes through the points
and
.
A quick sketch of the two points reveals that the line passes through all but the third quadrant.
Plug in for
to find a point on the line:
Thus, is a point on the line.
Plug in for
to find a second point on the line:
is another point on the line.
Now we know that the line passes through the points and
.
A quick sketch of the two points reveals that the line passes through all but the third quadrant.
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Jesse has a large movie collection containing X movies. 1/3 of his movies are action movies, 3/5 of the remainder are comedies, and the rest are historical movies. How many historical movies does Jesse own?
Jesse has a large movie collection containing X movies. 1/3 of his movies are action movies, 3/5 of the remainder are comedies, and the rest are historical movies. How many historical movies does Jesse own?
1/3 of the movies are action movies. 3/5 of 2/3 of the movies are comedies, or (3/5)*(2/3), or 6/15. Combining the comedies and the action movies (1/3 or 5/15), we get 11/15 of the movies being either action or comedy. Thus, 4/15 of the movies remain and all of them have to be historical.
1/3 of the movies are action movies. 3/5 of 2/3 of the movies are comedies, or (3/5)*(2/3), or 6/15. Combining the comedies and the action movies (1/3 or 5/15), we get 11/15 of the movies being either action or comedy. Thus, 4/15 of the movies remain and all of them have to be historical.
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The length of an arc,
, of a circle is
and the radius,
, of the circle is
. What is the measure in degrees of the central angle,
, formed by the arc
?
The length of an arc, , of a circle is
and the radius,
, of the circle is
. What is the measure in degrees of the central angle,
, formed by the arc
?
The circumference of the circle is
.

The length of the arc S is
.
A ratio can be established:


Solving for _
_yields 90o.
Note: This makes sense. Since the arc S was one-fourth the circumference of the circle, the central angle formed by arc S should be one-fourth the total degrees of a circle.
The circumference of the circle is .
The length of the arc S is .
A ratio can be established:
Solving for __yields 90o.
Note: This makes sense. Since the arc S was one-fourth the circumference of the circle, the central angle formed by arc S should be one-fourth the total degrees of a circle.
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Jessica wishes to fill up a cylinder with water at a rate of
gallons per minute. The volume of the cylinder is
gallons. The hole at the bottom of the cylinder leaks out
gallons per minute. If there are
gallons in the cylinder when Jessica starts filling it, how long does it take to fill?
Jessica wishes to fill up a cylinder with water at a rate of gallons per minute. The volume of the cylinder is
gallons. The hole at the bottom of the cylinder leaks out
gallons per minute. If there are
gallons in the cylinder when Jessica starts filling it, how long does it take to fill?
Jessica needs to fill up
gallons at the effective rate of
.
divided by
is equal to
. Notice how the units work out.
Jessica needs to fill up gallons at the effective rate of
.
divided by
is equal to
. Notice how the units work out.
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A vase needs to be filled with water. If the vase is a cylinder that is
tall with a
radius, how much water is needed to fill the vase?
A vase needs to be filled with water. If the vase is a cylinder that is tall with a
radius, how much water is needed to fill the vase?
Cylinder




Cylinder
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Given the inequality above, which of the following MUST be true?
Given the inequality above, which of the following MUST be true?
Subtract
from both sides:


Subtract 7 from both sides:


Divide both sides by
:

Remember to switch the inequality when dividing by a negative number:

Since
is not an answer, we must find an answer that, at the very least, does not contradict the fact that
is less than (approximately) 4.67. Since any number that is less than 4.67 is also less than any number that is bigger than 4.67, we can be sure that
is less than 5.
Subtract
from both sides:
Subtract 7 from both sides:
Divide both sides by :
Remember to switch the inequality when dividing by a negative number:
Since is not an answer, we must find an answer that, at the very least, does not contradict the fact that
is less than (approximately) 4.67. Since any number that is less than 4.67 is also less than any number that is bigger than 4.67, we can be sure that
is less than 5.
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If
and
, then which of the following could be the value of
?
If and
, then which of the following could be the value of
?
To solve this problem, add the two equations together:





The only answer choice that satisfies this equation is 0, because 0 is less than 4.
To solve this problem, add the two equations together:
The only answer choice that satisfies this equation is 0, because 0 is less than 4.
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Solve for
.
Solve for .

Find all factors of 24
1, 2, 3,4, 6, 8, 12, 24
Now find two factors that add up to
and multiply to
;
and
are the two factors.
By factoring, you can set the equation to be 
If you FOIL it out, it gives you
.
Set each part of the equation equal to 0, and solve for
.
and 
and 
Find all factors of 24
1, 2, 3,4, 6, 8, 12, 24
Now find two factors that add up to and multiply to
;
and
are the two factors.
By factoring, you can set the equation to be
If you FOIL it out, it gives you .
Set each part of the equation equal to 0, and solve for .
and
and
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A square
has side lengths of
. A second square
has side lengths of
. How many
can you fit in a single
?
A square has side lengths of
. A second square
has side lengths of
. How many
can you fit in a single
?
The area of
is
, the area of
is
. Therefore, you can fit 5.06
in
.
The area of is
, the area of
is
. Therefore, you can fit 5.06
in
.
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Solve for x

Solve for x
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Sally sells custom picture frames. Her monthly fixed costs are $350. It costs $10 to make each frame. Sally sells her picture frames for $35 each.
How many picture frames must Sally sell in order to break even?
Sally sells custom picture frames. Her monthly fixed costs are $350. It costs $10 to make each frame. Sally sells her picture frames for $35 each.
How many picture frames must Sally sell in order to break even?
The break-even point is where the costs equal the revenues.
Let
= # of frames sold
Costs: 
Revenues: 
Thus, 
So 14 picture frames must be sold each month to break-even.
The break-even point is where the costs equal the revenues.
Let = # of frames sold
Costs:
Revenues:
Thus,
So 14 picture frames must be sold each month to break-even.
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A family with 6 children, aged 4, 4, 5, 7, 12, and 13 are moving to a new home. They all want the same bedroom, so the parents have a lottery. Each child places their name in once for every year of age (the four year olds each put their name in 4 times, the seven year old puts his name in 7 times, etc.) What is the probability of the chosen child being 4 years old?
A family with 6 children, aged 4, 4, 5, 7, 12, and 13 are moving to a new home. They all want the same bedroom, so the parents have a lottery. Each child places their name in once for every year of age (the four year olds each put their name in 4 times, the seven year old puts his name in 7 times, etc.) What is the probability of the chosen child being 4 years old?
First, we will determine the total number of ballots:

Since there are two four year olds, and this question is asking the probability of the chosen child being four, the probability is:

First, we will determine the total number of ballots:
Since there are two four year olds, and this question is asking the probability of the chosen child being four, the probability is:
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Jamie is three times her little brother's age, and her little brother is two years younger than his older brother. Collectively, the three of them are 27 years old. How old is Jamie?
Jamie is three times her little brother's age, and her little brother is two years younger than his older brother. Collectively, the three of them are 27 years old. How old is Jamie?
The algebraic expression for
being Jamie's youngest brother's age is:




Jamie's youngest brother is five, the next oldest brother is seven, and Jamie is 15.
The algebraic expression for being Jamie's youngest brother's age is:
Jamie's youngest brother is five, the next oldest brother is seven, and Jamie is 15.
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How many negative solutions are there to the equation below?

How many negative solutions are there to the equation below?
First, subtract 3 from both sides in order to obtain an equation that equals 0:

The left side can be factored. We need factors of
that add up to
.
and
work:

Set both factors equal to 0 and solve:

To solve the left equation, add 1 to both sides. To solve the right equation, subtract 3 from both sides. This yields two solutions:

Only one of these solutions is negative, so the answer is 1.
First, subtract 3 from both sides in order to obtain an equation that equals 0:
The left side can be factored. We need factors of that add up to
.
and
work:
Set both factors equal to 0 and solve:
To solve the left equation, add 1 to both sides. To solve the right equation, subtract 3 from both sides. This yields two solutions:
Only one of these solutions is negative, so the answer is 1.
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An amusement park charges both an entrance fee, and a fee for every ride. This fee is the same for all rides. Lisa went on 6 rides and paid 120 dollars. Tom went on only 4 rides and paid 95 dollars. What was the entrance fee?
An amusement park charges both an entrance fee, and a fee for every ride. This fee is the same for all rides. Lisa went on 6 rides and paid 120 dollars. Tom went on only 4 rides and paid 95 dollars. What was the entrance fee?
We need 2 equations, because we have 2 unkown variables. Let
= the entrance fee, and
= the fee per ride. One ride costs
dollars. We know that Lisa spent 120 dollars in total. Since Lisa went on 6 rides, she spent
dollars on rides. Her only other expense was the entrance fee,
:

Apply similar logic to Tom:

Subtracting the second equation from the first equation results in:

Divide both sides by 2:

So every ride costs 12.5 dollars. Plugging 12.5 back into one of the original equations allows us to solve for the entrance fee:


Subtract 50 from both sides:

We need 2 equations, because we have 2 unkown variables. Let = the entrance fee, and
= the fee per ride. One ride costs
dollars. We know that Lisa spent 120 dollars in total. Since Lisa went on 6 rides, she spent
dollars on rides. Her only other expense was the entrance fee,
:
Apply similar logic to Tom:
Subtracting the second equation from the first equation results in:
Divide both sides by 2:
So every ride costs 12.5 dollars. Plugging 12.5 back into one of the original equations allows us to solve for the entrance fee:
Subtract 50 from both sides:
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Fred has $100 in quarters and nickels. He initially has 260 quarters. He then exchanges some of his nickels for the dimes of a friend. He is left with a total of 650 coins (consisting of quarters, dimes and nickels) still worth $100. How many nickels does Fred have now?
Fred has $100 in quarters and nickels. He initially has 260 quarters. He then exchanges some of his nickels for the dimes of a friend. He is left with a total of 650 coins (consisting of quarters, dimes and nickels) still worth $100. How many nickels does Fred have now?
Fred has $100 in quarters and nickels initially. We are also told that he has 260 quarters. This is worth $65. Thus Fred initially has $35 in nickels or 700 nickels.
Fred now exchanges some of his nickels for the dimes of a friend. He ends up with 650 coins. We know that Fred started with 960 coins (700 nickels + 260 quarters). He ends up with 650 coins. The number of quarters remains unchanged, meaning he now has 390 nickels and dimes. These must have the same value as the initial 700 nickels, though, since he didn't lose any money.
Now we can finally set up our solution:


Thus Fred has 80 nickels and 310 dimes.

An alternative solution step is to notice that turning nickels into dimes always occurs in exactly one way: 2 nickels to 1 dime. Every time you do this conversion, you will lose exactly one coin. We then notice that the number of coins drops from 960 to 650, or drops by 310 coins. We thus need to get rid of 310 coins. Since we're only allowed to change nickels into dimes (and lose 1 coin each time), we simply do this 310 times to reach the requisite number of coin losses. We are left with the proper number of coins with the proper value immediately. Since every replacement replaced 2 nickels, we also lost
nickels. Our final number of nickels is thus
nickels.
Fred has $100 in quarters and nickels initially. We are also told that he has 260 quarters. This is worth $65. Thus Fred initially has $35 in nickels or 700 nickels.
Fred now exchanges some of his nickels for the dimes of a friend. He ends up with 650 coins. We know that Fred started with 960 coins (700 nickels + 260 quarters). He ends up with 650 coins. The number of quarters remains unchanged, meaning he now has 390 nickels and dimes. These must have the same value as the initial 700 nickels, though, since he didn't lose any money.
Now we can finally set up our solution:
Thus Fred has 80 nickels and 310 dimes.
An alternative solution step is to notice that turning nickels into dimes always occurs in exactly one way: 2 nickels to 1 dime. Every time you do this conversion, you will lose exactly one coin. We then notice that the number of coins drops from 960 to 650, or drops by 310 coins. We thus need to get rid of 310 coins. Since we're only allowed to change nickels into dimes (and lose 1 coin each time), we simply do this 310 times to reach the requisite number of coin losses. We are left with the proper number of coins with the proper value immediately. Since every replacement replaced 2 nickels, we also lost nickels. Our final number of nickels is thus
nickels.
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As is clear from the graph, in the interval between
(
included) to
, the
is constant at
and then from
(
not included) to
(
not included), the
is a decreasing function.
As is clear from the graph, in the interval between (
included) to
, the
is constant at
and then from
(
not included) to
(
not included), the
is a decreasing function.
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Define an operation
as follows:
For all real numbers
,

Evaluate:
.
Define an operation as follows:
For all real numbers ,
Evaluate: .
, or, equivalently,







, or, equivalently,
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Jack has
,
to invest. If he invests two-thirds of it into a high-yield savings account with an annual interest rate of
, compounded quarterly, and the other third in a regular savings account at
simple interest, how much does Jack earn after one year?
Jack has ,
to invest. If he invests two-thirds of it into a high-yield savings account with an annual interest rate of
, compounded quarterly, and the other third in a regular savings account at
simple interest, how much does Jack earn after one year?
First, break the problem into two segments: the amount Jack invests in the high-yield savings, and the amount Jack invests in the simple interest account (10,000 and 5,000 respectively).
Now let's work with the high-yield savings account. $10,000 is invested at an annual rate of 8%, compounded quarterly. We can use the compound interest formula to solve:

Plug in the values given:



Therefore, Jack makes $824.32 off his high-yield savings account. Now let's calculate the other interest:



Add the two together, and we see that Jack makes a total of,
off of his investments.
First, break the problem into two segments: the amount Jack invests in the high-yield savings, and the amount Jack invests in the simple interest account (10,000 and 5,000 respectively).
Now let's work with the high-yield savings account. $10,000 is invested at an annual rate of 8%, compounded quarterly. We can use the compound interest formula to solve:
Plug in the values given:
Therefore, Jack makes $824.32 off his high-yield savings account. Now let's calculate the other interest:
Add the two together, and we see that Jack makes a total of, off of his investments.
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