Circles
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PSAT Math › Circles
A chord of a circle is $10$ units long. The perpendicular distance from the center of the circle to the chord is $12$ units. What is the radius of the circle, in units?
$14$
$11$
$17$
$13$
Explanation
A chord is 10 units long with perpendicular distance 12 units from the center. When a perpendicular from the center meets a chord, it bisects the chord, creating a right triangle with legs 5 (half the chord) and 12 (perpendicular distance), and hypotenuse r (radius). Using the Pythagorean theorem: r² = 5² + 12² = 25 + 144 = 169, so r = 13 units. The key insight is that the perpendicular from the center always bisects the chord. This problem tests understanding of the perpendicular bisector property of chords.
In the coordinate plane, a circle has equation $(x-3)^2+(y+5)^2=64$. What are the center and radius of the circle?
center $(-3,5)$, $r=8$
center $(3,-5)$, $r=8$
center $(-3,-5)$, $r=8$
center $(3,5)$, $r=64$
Explanation
The equation is in standard form (x-h)² + (y-k)² = r², where (h,k) is the center and r is the radius. From (x-3)² + (y+5)² = 64, we identify: center = (3, -5) and r² = 64, so r = 8. Note that y+5 = y-(-5), so the y-coordinate of the center is -5, not 5. A common error is misreading the signs in the equation. When identifying the center from standard form, remember that (x-h) means the x-coordinate is h, and (y-k) means the y-coordinate is k.
In the coordinate plane, a circle has equation $(x-3)^2+(y+2)^2=49$. Which of the following gives the center and radius of the circle?
Center $(-3,-2)$, $r=49$
Center $(-3,2)$, $r=7$
Center $(3,-2)$, $r=7$
Center $(3,2)$, $r=49$
Explanation
This question asks to identify the center and radius from the standard form equation of a circle. The standard form is (x - h)² + (y - k)² = r², where (h, k) is the center and r is the radius. From (x - 3)² + (y + 2)² = 49, we can see the center is (3, -2) since we have (x - 3) and (y - (-2)). The radius is √49 = 7, not 49 itself. Common mistakes include misidentifying the signs of the center coordinates or confusing r² with r.
Two radii of a circle form a central angle of $150^\circ$. The radius is $8$ cm. What is the length of the intercepted arc, in centimeters? (Use $\pi$ in your answer.)
$\tfrac{15\pi}{4}\text{ cm}$
$\tfrac{40\pi}{3}\text{ cm}$
$\tfrac{64\pi}{15}\text{ cm}$
$\tfrac{20\pi}{3}\text{ cm}$
Explanation
This problem asks for the arc length intercepted by a 150° central angle in a circle with radius 8 cm. The formula for arc length is s = (θ/360°) × 2πr when θ is in degrees. Substituting: s = (150°/360°) × 2π(8) = (5/12) × 16π = 80π/12 = 20π/3 cm. A common error is forgetting to convert the angle fraction or miscalculating the simplification. Always check that your angle is in the correct units for your formula.
A line is tangent to a circle at point $P$. The circle has center $O$, and $OP=13$. If the distance from $O$ to the tangent line is $13$, what is the measure of the angle between $\overline{OP}$ and the tangent line at $P$?
$90^\circ$
$0^\circ$
$180^\circ$
$45^\circ$
Explanation
This question involves a fundamental property of tangent lines to circles. A tangent line to a circle is always perpendicular to the radius drawn to the point of tangency. Since OP is the radius to point P where the line is tangent, the angle between OP and the tangent line must be 90°. The given information that the distance from O to the tangent line equals OP = 13 confirms this is the perpendicular distance. Remember this key property for any tangent line problem.
A circle has diameter $18$ ft. What is the circumference of the circle, in feet? (Use $\pi$ in your answer.)
$81\pi\text{ ft}$
$9\pi\text{ ft}$
$18\pi\text{ ft}$
$36\pi\text{ ft}$
Explanation
This question asks for the circumference of a circle with diameter 18 ft. The circumference formula is C = πd when using diameter, or C = 2πr when using radius. Since diameter = 18 ft, the circumference is C = π(18) = 18π ft. A common mistake is confusing diameter with radius and using C = 2π(18) = 36π, which would double the correct answer. Remember that diameter is already twice the radius.
A pizza has radius $7$ in. A slice is cut with a central angle of $45^\circ$. What is the area of the slice, in square inches? (Use $\pi$ in your answer.)
$\tfrac{49\pi}{4}\text{ in}^2$
$49\pi\text{ in}^2$
$\tfrac{49\pi}{8}\text{ in}^2$
$\tfrac{49\pi}{2}\text{ in}^2$
Explanation
This question asks for the area of a pizza slice with a 45° central angle from a pizza with radius 7 inches. The formula for sector area is $A = \frac{\theta}{360^\circ} \times \pi r^2$. Substituting: $A = \frac{45^\circ}{360^\circ} \times \pi(7)^2 = \frac{1}{8} \times 49\pi = \frac{49\pi}{8}$ square inches. Common mistakes include using diameter instead of radius or incorrectly simplifying the fraction 45/360 to something other than 1/8. When dealing with pizza or pie problems, visualize the fraction of the whole circle.
In circle $O$, the measure of inscribed angle $\angle ACB$ is $35^\circ$, where points $A$, $B$, and $C$ lie on the circle. What is the measure of arc $\overset{\frown}{AB}$ that does not include $C$?
$325^\circ$
$35^\circ$
$70^\circ$
$145^\circ$
Explanation
This question asks for the measure of arc AB that does not include point C, given inscribed angle ∠ACB = 35° in circle O. The property is that an inscribed angle measures half the arc it subtends, so arc AB = 2 × 35° = 70°. The arc not including C is the one subtended by the angle, typically the minor arc. Confirm points A, B, C are on the circle with ∠ACB intercepting arc AB. A key error is confusing inscribed with central angles, which would equal the arc. For strategy, remember to double the inscribed angle for the arc and consider if it's minor or major based on context.
A circle has radius $7$ cm. What is the circumference of the circle, in centimeters?
$49\pi$ cm
$7\pi$ cm
$28\pi$ cm
$14\pi$ cm
Explanation
This question asks for the circumference of a circle given its radius. The formula for circumference is C = 2πr, where r is the radius. Substituting r = 7 cm into the formula: C = 2π(7) = 14π cm. A common error is using the area formula (πr²) instead of the circumference formula, which would give 49π. When you see radius given directly, remember to use 2πr for circumference.
In a circle, an inscribed angle intercepts an arc measuring $110^\circ$. What is the measure of the inscribed angle, in degrees?
$35^\circ$
$110^\circ$
$220^\circ$
$55^\circ$
Explanation
An inscribed angle intercepts an arc of 110°. The inscribed angle theorem states that an inscribed angle is half the measure of its intercepted arc. Therefore, the inscribed angle = 110°/2 = 55°. This fundamental theorem is often confused with central angles, which equal their intercepted arcs. A helpful memory device: inscribed angles are "inside" the circle and get half the arc measure, while central angles at the center get the full arc measure.