How to subtract rational expressions with different denominators - PSAT Math

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Question

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Answer

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Determine an LCD (Least Common Denominator) between and $x^{2}$ .

LCD = $x^{2}$

$\frac{x(x+5)}{(x)x}-\frac{2x-3}{x^{2}}$

Multiply the top and bottom of the first rational expression by , so that the denominator will be $x^{2}$ .

Distribute the to .

$\frac{x^{2}+5x}{x^{2}}-\frac{2x-3}{x^{2}}$

Now you can subtract because both rational expressions have the same denominators.

$\frac{x^{2}+5x-2x+3}{x^{2}}$

Final Answer.

$\frac{x^{2}+3x+3}{x^{2}}$

Compare your answer with the correct one above

Question

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Answer

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Determine an LCD (Least Common Denominator) between and $x^{2}$ .

LCD = $x^{2}$

$\frac{x(x+5)}{(x)x}-\frac{2x-3}{x^{2}}$

Multiply the top and bottom of the first rational expression by , so that the denominator will be $x^{2}$ .

Distribute the to .

$\frac{x^{2}+5x}{x^{2}}-\frac{2x-3}{x^{2}}$

Now you can subtract because both rational expressions have the same denominators.

$\frac{x^{2}+5x-2x+3}{x^{2}}$

Final Answer.

$\frac{x^{2}+3x+3}{x^{2}}$

Compare your answer with the correct one above

Question

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Answer

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Determine an LCD (Least Common Denominator) between and $x^{2}$ .

LCD = $x^{2}$

$\frac{x(x+5)}{(x)x}-\frac{2x-3}{x^{2}}$

Multiply the top and bottom of the first rational expression by , so that the denominator will be $x^{2}$ .

Distribute the to .

$\frac{x^{2}+5x}{x^{2}}-\frac{2x-3}{x^{2}}$

Now you can subtract because both rational expressions have the same denominators.

$\frac{x^{2}+5x-2x+3}{x^{2}}$

Final Answer.

$\frac{x^{2}+3x+3}{x^{2}}$

Compare your answer with the correct one above

Question

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Answer

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Determine an LCD (Least Common Denominator) between and $x^{2}$ .

LCD = $x^{2}$

$\frac{x(x+5)}{(x)x}-\frac{2x-3}{x^{2}}$

Multiply the top and bottom of the first rational expression by , so that the denominator will be $x^{2}$ .

Distribute the to .

$\frac{x^{2}+5x}{x^{2}}-\frac{2x-3}{x^{2}}$

Now you can subtract because both rational expressions have the same denominators.

$\frac{x^{2}+5x-2x+3}{x^{2}}$

Final Answer.

$\frac{x^{2}+3x+3}{x^{2}}$

Compare your answer with the correct one above

Question

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Answer

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Determine an LCD (Least Common Denominator) between and $x^{2}$ .

LCD = $x^{2}$

$\frac{x(x+5)}{(x)x}-\frac{2x-3}{x^{2}}$

Multiply the top and bottom of the first rational expression by , so that the denominator will be $x^{2}$ .

Distribute the to .

$\frac{x^{2}+5x}{x^{2}}-\frac{2x-3}{x^{2}}$

Now you can subtract because both rational expressions have the same denominators.

$\frac{x^{2}+5x-2x+3}{x^{2}}$

Final Answer.

$\frac{x^{2}+3x+3}{x^{2}}$

Compare your answer with the correct one above

Question

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Answer

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Determine an LCD (Least Common Denominator) between and $x^{2}$ .

LCD = $x^{2}$

$\frac{x(x+5)}{(x)x}-\frac{2x-3}{x^{2}}$

Multiply the top and bottom of the first rational expression by , so that the denominator will be $x^{2}$ .

Distribute the to .

$\frac{x^{2}+5x}{x^{2}}-\frac{2x-3}{x^{2}}$

Now you can subtract because both rational expressions have the same denominators.

$\frac{x^{2}+5x-2x+3}{x^{2}}$

Final Answer.

$\frac{x^{2}+3x+3}{x^{2}}$

Compare your answer with the correct one above

Question

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Answer

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Determine an LCD (Least Common Denominator) between and $x^{2}$ .

LCD = $x^{2}$

$\frac{x(x+5)}{(x)x}-\frac{2x-3}{x^{2}}$

Multiply the top and bottom of the first rational expression by , so that the denominator will be $x^{2}$ .

Distribute the to .

$\frac{x^{2}+5x}{x^{2}}-\frac{2x-3}{x^{2}}$

Now you can subtract because both rational expressions have the same denominators.

$\frac{x^{2}+5x-2x+3}{x^{2}}$

Final Answer.

$\frac{x^{2}+3x+3}{x^{2}}$

Compare your answer with the correct one above

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How to subtract rational expressions with different denominators - PSAT Math

Simplify.

Determine an LCD (Least Common Denominator) between and . LCD = Multiply the top and bottom of the first rational expression by , so that the denominator will be . Distribute the to . Now you can subtract because both rational expressions have the same denominators. Final Answer.

Simplify.

Determine an LCD (Least Common Denominator) between and . LCD = Multiply the top and bottom of the first rational expression by , so that the denominator will be . Distribute the to . Now you can subtract because both rational expressions have the same denominators. Final Answer.

Simplify.

Determine an LCD (Least Common Denominator) between and . LCD = Multiply the top and bottom of the first rational expression by , so that the denominator will be . Distribute the to . Now you can subtract because both rational expressions have the same denominators. Final Answer.

Simplify.

Determine an LCD (Least Common Denominator) between and . LCD = Multiply the top and bottom of the first rational expression by , so that the denominator will be . Distribute the to . Now you can subtract because both rational expressions have the same denominators. Final Answer.

Simplify.

Determine an LCD (Least Common Denominator) between and . LCD = Multiply the top and bottom of the first rational expression by , so that the denominator will be . Distribute the to . Now you can subtract because both rational expressions have the same denominators. Final Answer.

Simplify.

Determine an LCD (Least Common Denominator) between and . LCD = Multiply the top and bottom of the first rational expression by , so that the denominator will be . Distribute the to . Now you can subtract because both rational expressions have the same denominators. Final Answer.

Simplify.

Determine an LCD (Least Common Denominator) between and . LCD = Multiply the top and bottom of the first rational expression by , so that the denominator will be . Distribute the to . Now you can subtract because both rational expressions have the same denominators. Final Answer.

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$

Simplify.

$\frac{x+5}{x}-\frac{2x-3}{x^{2}}$