How to find the length of the diagonal of a rectangle - PSAT Math

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Question

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

Answer

The length and width of the rectangle are in a ratio of 3:4, so the sides can be written as 3_x_ and 4_x_.

We also know the area, so we write an equation and solve for x:

(3_x_)(4_x_) = 12_x_2 = 108.

x2 = 9

x = 3

Now we can recalculate the length and the width:

length = 3x = 3(3) = 9 centimeters

width = 4x = 4(3) = 12 centimeters

Using the Pythagorean Theorem we can find the diagonal, c:

length2 + width2 = c2

92 + 122 = _c_2

81 + 144 = c2

225 = c2

c = 15 centimeters

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Question

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

Answer

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

Compare your answer with the correct one above

Question

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

Answer

The length and width of the rectangle are in a ratio of 3:4, so the sides can be written as 3_x_ and 4_x_.

We also know the area, so we write an equation and solve for x:

(3_x_)(4_x_) = 12_x_2 = 108.

x2 = 9

x = 3

Now we can recalculate the length and the width:

length = 3x = 3(3) = 9 centimeters

width = 4x = 4(3) = 12 centimeters

Using the Pythagorean Theorem we can find the diagonal, c:

length2 + width2 = c2

92 + 122 = _c_2

81 + 144 = c2

225 = c2

c = 15 centimeters

Compare your answer with the correct one above

Question

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

Answer

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

Compare your answer with the correct one above

Question

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

Answer

The length and width of the rectangle are in a ratio of 3:4, so the sides can be written as 3_x_ and 4_x_.

We also know the area, so we write an equation and solve for x:

(3_x_)(4_x_) = 12_x_2 = 108.

x2 = 9

x = 3

Now we can recalculate the length and the width:

length = 3x = 3(3) = 9 centimeters

width = 4x = 4(3) = 12 centimeters

Using the Pythagorean Theorem we can find the diagonal, c:

length2 + width2 = c2

92 + 122 = _c_2

81 + 144 = c2

225 = c2

c = 15 centimeters

Compare your answer with the correct one above

Question

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

Answer

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

Compare your answer with the correct one above

Question

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

Answer

The length and width of the rectangle are in a ratio of 3:4, so the sides can be written as 3_x_ and 4_x_.

We also know the area, so we write an equation and solve for x:

(3_x_)(4_x_) = 12_x_2 = 108.

x2 = 9

x = 3

Now we can recalculate the length and the width:

length = 3x = 3(3) = 9 centimeters

width = 4x = 4(3) = 12 centimeters

Using the Pythagorean Theorem we can find the diagonal, c:

length2 + width2 = c2

92 + 122 = _c_2

81 + 144 = c2

225 = c2

c = 15 centimeters

Compare your answer with the correct one above

Question

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

Answer

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

Compare your answer with the correct one above

Question

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

Answer

The length and width of the rectangle are in a ratio of 3:4, so the sides can be written as 3_x_ and 4_x_.

We also know the area, so we write an equation and solve for x:

(3_x_)(4_x_) = 12_x_2 = 108.

x2 = 9

x = 3

Now we can recalculate the length and the width:

length = 3x = 3(3) = 9 centimeters

width = 4x = 4(3) = 12 centimeters

Using the Pythagorean Theorem we can find the diagonal, c:

length2 + width2 = c2

92 + 122 = _c_2

81 + 144 = c2

225 = c2

c = 15 centimeters

Compare your answer with the correct one above

Question

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

Answer

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

Compare your answer with the correct one above

Question

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

Answer

The length and width of the rectangle are in a ratio of 3:4, so the sides can be written as 3_x_ and 4_x_.

We also know the area, so we write an equation and solve for x:

(3_x_)(4_x_) = 12_x_2 = 108.

x2 = 9

x = 3

Now we can recalculate the length and the width:

length = 3x = 3(3) = 9 centimeters

width = 4x = 4(3) = 12 centimeters

Using the Pythagorean Theorem we can find the diagonal, c:

length2 + width2 = c2

92 + 122 = _c_2

81 + 144 = c2

225 = c2

c = 15 centimeters

Compare your answer with the correct one above

Question

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

Answer

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

Compare your answer with the correct one above

Question

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

Answer

The length and width of the rectangle are in a ratio of 3:4, so the sides can be written as 3_x_ and 4_x_.

We also know the area, so we write an equation and solve for x:

(3_x_)(4_x_) = 12_x_2 = 108.

x2 = 9

x = 3

Now we can recalculate the length and the width:

length = 3x = 3(3) = 9 centimeters

width = 4x = 4(3) = 12 centimeters

Using the Pythagorean Theorem we can find the diagonal, c:

length2 + width2 = c2

92 + 122 = _c_2

81 + 144 = c2

225 = c2

c = 15 centimeters

Compare your answer with the correct one above

Question

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

Answer

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

Compare your answer with the correct one above

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How to find the length of the diagonal of a rectangle - PSAT Math

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem: Therefore the diagonal of the rectangle is 5 feet.

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem: Therefore the diagonal of the rectangle is 5 feet.

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem: Therefore the diagonal of the rectangle is 5 feet.

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem: Therefore the diagonal of the rectangle is 5 feet.

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem: Therefore the diagonal of the rectangle is 5 feet.

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem: Therefore the diagonal of the rectangle is 5 feet.

The length and width of a rectangle are in the ratio of 3:4. If the rectangle has an area of 108 square centimeters, what is the length of the diagonal?

What is the length of the diagonal of a rectangle that is 3 feet long and 4 feet wide?

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem: Therefore the diagonal of the rectangle is 5 feet.

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.

The diagonal of the rectangle is equivalent to finding the length of the hypotenuse of a right triangle with sides 3 and 4. Using the Pythagorean Theorem:

$3^{2}+4^{2} = hypotenuse^{2}$

$25 = hypotenuse^{2}$

$hypotenuse = 5$

Therefore the diagonal of the rectangle is 5 feet.