Sum and Difference Identities For Sine - Pre-Calculus

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Question

Use the sum or difference identity to find the exact value: $sin165^\circ$

Answer

Again, here we break up the 165 into and solve using the sin identity: $sin135\cdot cos30+cos135\cdot sin30\rightarrow \frac{\sqrt{2}}{2}\cdot \frac{\sqrt{3}}{2}+\frac{-\sqrt{2}}{2}\cdot \frac{1}{2}\rightarrow \frac{\sqrt{6}-\sqrt{2}}{4}$

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Question

Is the following equation an identity? $sin(x-\pi)=sin(x)$

Answer

$sin(x-\pi)=sinx\rightarrow sinxcos\pi-cosxsin\pi=sinx\rightarrow sinx\cdot (-1)-cosx\cdot (0)\rightarrow -sinx-0=sinx\rightarrow -sinx eq sinx$

and so this is again not an identity

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Question

Is the following equation an identity? $\sin \left ( x-\pi \right )=\sin \left ( x \right )$ ?

Answer

$\sin \left ( x-\pi \right )=\sin x\rightarrow \sin x\cos \pi -\cos x\sin \pi = \sin x\rightarrow \sin x\cdot \left ( -1 \right )-\cos x\cdot \left ( 0 \right )\rightarrow -\sin x-0=\sin x eq \sin x$

Therefore, this is not an identity.

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Question

Use the sum or difference identity to find the exact value: $sin165^\circ$

Answer

Again, here we break up the 165 into and solve using the sin identity: $sin135\cdot cos30+cos135\cdot sin30\rightarrow \frac{\sqrt{2}}{2}\cdot \frac{\sqrt{3}}{2}+\frac{-\sqrt{2}}{2}\cdot \frac{1}{2}\rightarrow \frac{\sqrt{6}-\sqrt{2}}{4}$

Compare your answer with the correct one above

Question

Is the following equation an identity? $sin(x-\pi)=sin(x)$

Answer

$sin(x-\pi)=sinx\rightarrow sinxcos\pi-cosxsin\pi=sinx\rightarrow sinx\cdot (-1)-cosx\cdot (0)\rightarrow -sinx-0=sinx\rightarrow -sinx eq sinx$

and so this is again not an identity

Compare your answer with the correct one above

Question

Is the following equation an identity? $\sin \left ( x-\pi \right )=\sin \left ( x \right )$ ?

Answer

$\sin \left ( x-\pi \right )=\sin x\rightarrow \sin x\cos \pi -\cos x\sin \pi = \sin x\rightarrow \sin x\cdot \left ( -1 \right )-\cos x\cdot \left ( 0 \right )\rightarrow -\sin x-0=\sin x eq \sin x$

Therefore, this is not an identity.

Compare your answer with the correct one above

Question

Use the sum or difference identity to find the exact value: $sin165^\circ$

Answer

Again, here we break up the 165 into and solve using the sin identity: $sin135\cdot cos30+cos135\cdot sin30\rightarrow \frac{\sqrt{2}}{2}\cdot \frac{\sqrt{3}}{2}+\frac{-\sqrt{2}}{2}\cdot \frac{1}{2}\rightarrow \frac{\sqrt{6}-\sqrt{2}}{4}$

Compare your answer with the correct one above

Question

Is the following equation an identity? $sin(x-\pi)=sin(x)$

Answer

$sin(x-\pi)=sinx\rightarrow sinxcos\pi-cosxsin\pi=sinx\rightarrow sinx\cdot (-1)-cosx\cdot (0)\rightarrow -sinx-0=sinx\rightarrow -sinx eq sinx$

and so this is again not an identity

Compare your answer with the correct one above

Question

Is the following equation an identity? $\sin \left ( x-\pi \right )=\sin \left ( x \right )$ ?

Answer

$\sin \left ( x-\pi \right )=\sin x\rightarrow \sin x\cos \pi -\cos x\sin \pi = \sin x\rightarrow \sin x\cdot \left ( -1 \right )-\cos x\cdot \left ( 0 \right )\rightarrow -\sin x-0=\sin x eq \sin x$

Therefore, this is not an identity.

Compare your answer with the correct one above

Question

Use the sum or difference identity to find the exact value: $sin165^\circ$

Answer

Again, here we break up the 165 into and solve using the sin identity: $sin135\cdot cos30+cos135\cdot sin30\rightarrow \frac{\sqrt{2}}{2}\cdot \frac{\sqrt{3}}{2}+\frac{-\sqrt{2}}{2}\cdot \frac{1}{2}\rightarrow \frac{\sqrt{6}-\sqrt{2}}{4}$

Compare your answer with the correct one above

Question

Is the following equation an identity? $sin(x-\pi)=sin(x)$

Answer

$sin(x-\pi)=sinx\rightarrow sinxcos\pi-cosxsin\pi=sinx\rightarrow sinx\cdot (-1)-cosx\cdot (0)\rightarrow -sinx-0=sinx\rightarrow -sinx eq sinx$

and so this is again not an identity

Compare your answer with the correct one above

Question

Is the following equation an identity? $\sin \left ( x-\pi \right )=\sin \left ( x \right )$ ?

Answer

$\sin \left ( x-\pi \right )=\sin x\rightarrow \sin x\cos \pi -\cos x\sin \pi = \sin x\rightarrow \sin x\cdot \left ( -1 \right )-\cos x\cdot \left ( 0 \right )\rightarrow -\sin x-0=\sin x eq \sin x$

Therefore, this is not an identity.

Compare your answer with the correct one above

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Sum and Difference Identities For Sine - Pre-Calculus

Use the sum or difference identity to find the exact value:

Again, here we break up the 165 into and solve using the sin identity:

Is the following equation an identity?

and so this is again not an identity

Is the following equation an identity? ?

Therefore, this is not an identity.

Use the sum or difference identity to find the exact value:

Again, here we break up the 165 into and solve using the sin identity:

Is the following equation an identity?

and so this is again not an identity

Is the following equation an identity? ?

Therefore, this is not an identity.

Use the sum or difference identity to find the exact value:

Again, here we break up the 165 into and solve using the sin identity:

Is the following equation an identity?

and so this is again not an identity

Is the following equation an identity? ?

Therefore, this is not an identity.

Use the sum or difference identity to find the exact value:

Again, here we break up the 165 into and solve using the sin identity:

Is the following equation an identity?

and so this is again not an identity

Is the following equation an identity? ?

Therefore, this is not an identity.

Use the sum or difference identity to find the exact value: $sin165^\circ$

Again, here we break up the 165 into and solve using the sin identity: $sin135\cdot cos30+cos135\cdot sin30\rightarrow \frac{\sqrt{2}}{2}\cdot \frac{\sqrt{3}}{2}+\frac{-\sqrt{2}}{2}\cdot \frac{1}{2}\rightarrow \frac{\sqrt{6}-\sqrt{2}}{4}$

Is the following equation an identity? $sin(x-\pi)=sin(x)$

$sin(x-\pi)=sinx\rightarrow sinxcos\pi-cosxsin\pi=sinx\rightarrow sinx\cdot (-1)-cosx\cdot (0)\rightarrow -sinx-0=sinx\rightarrow -sinx eq sinx$

and so this is again not an identity

Is the following equation an identity? $\sin \left ( x-\pi \right )=\sin \left ( x \right )$ ?

$\sin \left ( x-\pi \right )=\sin x\rightarrow \sin x\cos \pi -\cos x\sin \pi = \sin x\rightarrow \sin x\cdot \left ( -1 \right )-\cos x\cdot \left ( 0 \right )\rightarrow -\sin x-0=\sin x eq \sin x$

Therefore, this is not an identity.

Use the sum or difference identity to find the exact value: $sin165^\circ$

Again, here we break up the 165 into and solve using the sin identity: $sin135\cdot cos30+cos135\cdot sin30\rightarrow \frac{\sqrt{2}}{2}\cdot \frac{\sqrt{3}}{2}+\frac{-\sqrt{2}}{2}\cdot \frac{1}{2}\rightarrow \frac{\sqrt{6}-\sqrt{2}}{4}$

Is the following equation an identity? $sin(x-\pi)=sin(x)$

$sin(x-\pi)=sinx\rightarrow sinxcos\pi-cosxsin\pi=sinx\rightarrow sinx\cdot (-1)-cosx\cdot (0)\rightarrow -sinx-0=sinx\rightarrow -sinx eq sinx$

and so this is again not an identity

Is the following equation an identity? $\sin \left ( x-\pi \right )=\sin \left ( x \right )$ ?

$\sin \left ( x-\pi \right )=\sin x\rightarrow \sin x\cos \pi -\cos x\sin \pi = \sin x\rightarrow \sin x\cdot \left ( -1 \right )-\cos x\cdot \left ( 0 \right )\rightarrow -\sin x-0=\sin x eq \sin x$

Therefore, this is not an identity.

Use the sum or difference identity to find the exact value: $sin165^\circ$

Again, here we break up the 165 into and solve using the sin identity: $sin135\cdot cos30+cos135\cdot sin30\rightarrow \frac{\sqrt{2}}{2}\cdot \frac{\sqrt{3}}{2}+\frac{-\sqrt{2}}{2}\cdot \frac{1}{2}\rightarrow \frac{\sqrt{6}-\sqrt{2}}{4}$

Is the following equation an identity? $sin(x-\pi)=sin(x)$

$sin(x-\pi)=sinx\rightarrow sinxcos\pi-cosxsin\pi=sinx\rightarrow sinx\cdot (-1)-cosx\cdot (0)\rightarrow -sinx-0=sinx\rightarrow -sinx eq sinx$

and so this is again not an identity

Is the following equation an identity? $\sin \left ( x-\pi \right )=\sin \left ( x \right )$ ?

$\sin \left ( x-\pi \right )=\sin x\rightarrow \sin x\cos \pi -\cos x\sin \pi = \sin x\rightarrow \sin x\cdot \left ( -1 \right )-\cos x\cdot \left ( 0 \right )\rightarrow -\sin x-0=\sin x eq \sin x$

Therefore, this is not an identity.

Use the sum or difference identity to find the exact value: $sin165^\circ$

Again, here we break up the 165 into and solve using the sin identity: $sin135\cdot cos30+cos135\cdot sin30\rightarrow \frac{\sqrt{2}}{2}\cdot \frac{\sqrt{3}}{2}+\frac{-\sqrt{2}}{2}\cdot \frac{1}{2}\rightarrow \frac{\sqrt{6}-\sqrt{2}}{4}$

Is the following equation an identity? $sin(x-\pi)=sin(x)$

$sin(x-\pi)=sinx\rightarrow sinxcos\pi-cosxsin\pi=sinx\rightarrow sinx\cdot (-1)-cosx\cdot (0)\rightarrow -sinx-0=sinx\rightarrow -sinx eq sinx$

and so this is again not an identity

Is the following equation an identity? $\sin \left ( x-\pi \right )=\sin \left ( x \right )$ ?

$\sin \left ( x-\pi \right )=\sin x\rightarrow \sin x\cos \pi -\cos x\sin \pi = \sin x\rightarrow \sin x\cdot \left ( -1 \right )-\cos x\cdot \left ( 0 \right )\rightarrow -\sin x-0=\sin x eq \sin x$

Therefore, this is not an identity.