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Prealgebra Question of the Day

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Thursday, September 17, 2026

A polynomial is written as P(x)=2x3x2+4x+1+kx23x+2P(x) = 2x^3 - x^2 + 4x + 1 + kx^2 - 3x + 2, where kk is a constant. For what value of kk will P(x)P(x) have no x2x^2 term after combining like terms?

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A polynomial is written as P(x)=2x3x2+4x+1+kx23x+2P(x) = 2x^3 - x^2 + 4x + 1 + kx^2 - 3x + 2, where kk is a constant. For what value of kk will P(x)P(x) have no x2x^2 term after combining like terms?

  1. k=0k = 0
  2. k=1k = -1
  3. k=1k = 1 (correct answer)
  4. k=3k = 3

Explanation: When you encounter a polynomial with like terms that need to be combined, your goal is to group terms with the same power of xx and simplify the expression. Let's rewrite P(x)=2x3x2+4x+1+kx23x+2P(x) = 2x^3 - x^2 + 4x + 1 + kx^2 - 3x + 2 by grouping like terms:

  • x3x^3 terms: 2x32x^3
  • x2x^2 terms: x2+kx2=(1+k)x2-x^2 + kx^2 = (-1 + k)x^2
  • xx terms: 4x3x=x4x - 3x = x
  • Constant terms: 1+2=31 + 2 = 3
So P(x)=2x3+(1+k)x2+x+3P(x) = 2x^3 + (-1 + k)x^2 + x + 3. For the x2x^2 term to disappear completely, its coefficient must equal zero: 1+k=0-1 + k = 0, which means k=1k = 1. Looking at the wrong answers: Choice A (k=0k = 0) would give us (1+0)x2=x2(-1 + 0)x^2 = -x^2, so the x2x^2 term remains. Choice B (k=1k = -1) results in (1+(1))x2=2x2(-1 + (-1))x^2 = -2x^2, making the x2x^2 term even larger. Choice D (k=3k = 3) gives us (1+3)x2=2x2(-1 + 3)x^2 = 2x^2, which also leaves an x2x^2 term. Only choice C (k=1k = 1) eliminates the x2x^2 term entirely. Study tip: When asked to eliminate a term from a polynomial, set the coefficient of that term equal to zero after combining like terms. This type of question tests your ability to manipulate algebraic expressions systematically.