Assigning Ortho, Meta, Para

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Organic Chemistry › Assigning Ortho, Meta, Para

Questions 1 - 10
1

Which of the following are electron withdrawing substituents?

Screen shot 2015 10 24 at 10.14.50 am

1, 4 and 5

2 and 4

4 and 5

3, and 4

1 and 2

Explanation

Carbonyls (as in 4 and 5) are always electron withdrawing due to the Oxygen's electronegativity. Similarly, the oxygens on the nitrate (1) are electron withdrawing.

2

Which position will be most favored when adding chlorine to tert-butylbenzene?

Para

Ortho

Meta

Ortho and para

Meta and para

Explanation

A tert-butyl functional group is electron donating and will therefore activate the ortho and para positions. However, the ortho positions are sterically hindered by the bulky tert-butyl group. Therefore, the para position will be favored.

3

Which of the following substituents is electron-withdrawing when added to a benzene ring?

None of these substituents are electron-withdrawing

Explanation

is the only electron-withdrawing substituent because it contains two electronegative oxygen atoms which pull electrons from the benzene ring towards itself. This effect is electron-withdrawing and makes the ring slightly positive in charge. All the other substituents are electron-donating groups, which activate the ring for electrophilic addition.

4

Which of the following groups would be added on the para position to phenol?

Explanation

is the only electron-donating group listed. Therefore, it will add to the ortho and para positions on phenol. The rest of the substituents are highly electron-withdrawing groups and will add to the meta positions on phenol.

5

If the molecule nitrobenzene were to undergo an electrophilic aromatic substitution, on which carbon(s) will the incoming substituent likely be directed to? (When numbering carbons on the benzene ring, label the carbon containing the nitro group as carbon number , the one immediately next to it as carbon number , and continue around the ring in that direction.

and

and

, , and

All carbons are equally likely to be substituted.

Explanation

Several resonance structures can be drawn for the molecule nitrobenzene. These are shown below.

Screen shot 2015 12 26 at 9.11.16 pm

From these resonance structures, an overall molecular electronic distribution can be determined:

Screen shot 2015 12 26 at 9.11.29 pm

Because the overall charge distribution puts partial positive charges on carbons , , and , these carbons have an increased electrophilic character. Therefore, these carbons are less likely than the other carbons to accept an incoming electrophilic substituent, making these positions less likely to be substituted. By default, carbons , and , known as the meta positions are the only ones nucleophilic enough to carry out this reaction.

6

What is the product of the reaction shown?

Screen shot 2015 12 26 at 9.13.10 pm

I and III

I, II, and III

I only

III only

Explanation

In the molecule shown, the aldehyde group will direct incoming substituents to positions meta to it, and both the the hydroxyl group AND the fluorine group will direct incoming substituents to positions ortho or para to them. Options I and III show the incoming substituent meta to the aldehyde group, as well as either ortho or para to both the fluorine group and hydroxyl group. Therefore, they are both possible products.

Note: because option III shows attachment at a carbon that is slightly less sterically hindered than that of option I, option III will be produced in a slightly greater quantity.

7

Predict the major product in the reaction shown.

Screen shot 2015 12 26 at 9.14.15 pm

III

I

II

IV

Explanation

The reagents shown will add a bromine to an aromatic ring through an electrophilic aromatic substitution mechanism. A nitro group is a strong electron withdrawing group and a benzene deactivator. All benzene deactivators (with the exception of halogens) direct incoming substituents to the meta positions. Therefore, option III is the major product.

8

If the molecule phenol (hydroxybenzene) were to undergo electrophilic aromatic substitution, which carbon(s) will the hydroxyl group direct incoming substituents to? (Start labeling carbons with number being the carbon containing the hydroxyl group, being the one immediately next to it, and continuing around the ring).

, , and

and

, , , and

only

Explanation

Several resonance structures can be drawn for the molecule phenol. These are shown below.

Screen shot 2015 12 26 at 9.15.15 pm

Because the overall charge distribution puts partial negative charges on carbons , , and , these carbons have an increased nucleophilic character. Therefore, these carbons are more likely than the other carbons to accept an incoming electrophilic substituent, making these positions more likely to be substituted. Carbons and are known as the ortho positions, and carbon is known as the para position.

9

What is the best explanation for why phenol (shown) directs substitution products ortho and para?

Screen shot 2015 09 21 at 1.34.45 pm

Resonance structures exist that put slight negative charges on ortho and para positions.

Resonance structures exist that put slight positive charges on ortho and para positions.

Resonance structures exist that put slight negative charges on meta positions.

Resonance structures exist that put slight positive charges on meta positions.

None of the other answers

Explanation

Phenol contains the hydroxide group, which is an electron donor, puts electron density into the benzene ring. Resonance structures are drawn as follows

Screen shot 2015 09 21 at 1.53.32 pm

10

Which of these functional groups is a meta director?

None of these

Explanation

With the exception of halogens, meta directors deactivate a benzene ring. In other words, they make the benzene ring less reactive, especially in an electrophilic aromatic substitution (EAS) reaction. Meta directors have little electron density at the point of contact with the benzene ring. For example, a carboxylic acid is a meta director because it experiences resonance, a delocalization of electrons. All of the answer choices in this problem have a lone pair of electrons on the point of contact with the benzene ring and they all are ortho/para directors.

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