Compounding Ingredient Quantities - NAPLEX

$1:50$. Converts 2% w/v to ratio 1:x by dividing 100 by 2.

$8,mL$. Based on %v/v: 10% means 10 mL solute per 100 mL total, for 80 mL.

$2.4,g$. Applies %w/v definition: 2% means 2 g per 100 mL, scaled to 120 mL.

$mg = \frac{mEq \times MW}{valence}$. Solves for milligrams using milliequivalents, molecular weight, and ion valence.

$0.4%,w/v$. Converts 1:250 ratio to percent by dividing 100 by 250.

$mEq = \frac{mg \times valence}{MW}$. Computes milliequivalents accounting for ion valence and molecular weight from milligrams.

$g = mol \times MW$. Determines mass in grams by multiplying moles by molecular weight.

$mol = \frac{g}{MW}$. Calculates the number of moles by dividing mass in grams by molecular weight.

$x = \frac{100}{%w/v}$. Rearranges percent strength to find x in 1:x ratio by dividing 100 by the percentage.

$%w/v = \frac{100}{x}$. Converts ratio strength where 1 part solute in x parts solution equals 100/x percent.

$625,mg$. Divides required active amount by assay fraction (0.8) to find weighed mass.

$450,mg$. Uses %w/w: 1.5% means 1.5 g per 100 g, for 30 g converted to mg.

$1.8,g$. Applies %w/v: 4% means 4 g per 100 mL, scaled to 45 mL.

$0.25,mL$. Calculates volume as dose divided by concentration to deliver required amount.

$75,mL$. Uses dilution formula $C_1V_1 = C_2V_2$ to find stock volume needed.

$C_1V_1 = C_2V_2$. Applies the principle that the amount of solute remains constant before and after dilution.

$parts_{high} = C_{target} - C_{low}$. In alligation, parts of higher concentration equal the difference between target and lower concentration.

$parts_{low} = C_{high} - C_{target}$. In alligation, parts of lower concentration equal the difference between higher and target concentration.

$\text{Weigh} = \frac{\text{required amount}}{\text{assay fraction}}$. Adjusts the weighed amount to compensate for less than 100% potency as indicated by assay.

$g_{needed} = g_{target} \times \frac{MW_{available}}{MW_{target}}$. Corrects for differences in molecular weights between available and target forms of the compound.

$12.5,g$. Uses %w/w: 5% means 5 g solute per 100 g total, applied to 250 g.

$g_{solute} = \frac{%w/w}{100} \times g_{total}$. Derives from the definition of %w/w as the mass of solute per 100 grams of total preparation.

$g_{solute} = \frac{%w/v}{100} \times mL_{total}$. Based on %w/v definition as grams of solute per 100 mL of total solution volume.

$mL_{solute} = \frac{%v/v}{100} \times mL_{total}$. Stems from %v/v as the volume of solute per 100 mL of total solution volume.