Mass Affects Motion - Middle School Physical Science
Card 1 of 25
Identify the correct relationship between acceleration and net force when mass is constant.
Identify the correct relationship between acceleration and net force when mass is constant.
Tap to reveal answer
$a \propto F_{net}$. Acceleration is directly proportional to net force.
$a \propto F_{net}$. Acceleration is directly proportional to net force.
← Didn't Know|Knew It →
What is the weight equation in terms of mass and gravitational field strength?
What is the weight equation in terms of mass and gravitational field strength?
Tap to reveal answer
$W = mg$. Weight equals mass times gravitational acceleration.
$W = mg$. Weight equals mass times gravitational acceleration.
← Didn't Know|Knew It →
Choose the correct evidence-based claim: same push on empty vs loaded cart; which accelerates more?
Choose the correct evidence-based claim: same push on empty vs loaded cart; which accelerates more?
Tap to reveal answer
The empty cart accelerates more. Less mass means greater acceleration for same force.
The empty cart accelerates more. Less mass means greater acceleration for same force.
← Didn't Know|Knew It →
If an object's mass is cut in half while $F_{net}$ stays constant, what happens to its acceleration?
If an object's mass is cut in half while $F_{net}$ stays constant, what happens to its acceleration?
Tap to reveal answer
Acceleration doubles. Halving mass doubles acceleration: $a = \frac{F}{m/2}$.
Acceleration doubles. Halving mass doubles acceleration: $a = \frac{F}{m/2}$.
← Didn't Know|Knew It →
Calculate acceleration when $F_{net} = 10,\text{N}$ and $m = 5,\text{kg}$.
Calculate acceleration when $F_{net} = 10,\text{N}$ and $m = 5,\text{kg}$.
Tap to reveal answer
$a = 2,\text{m/s}^2$. Using $a = \frac{F_{net}}{m} = \frac{10}{5} = 2$.
$a = 2,\text{m/s}^2$. Using $a = \frac{F_{net}}{m} = \frac{10}{5} = 2$.
← Didn't Know|Knew It →
If an object's mass doubles while $F_{net}$ stays constant, what happens to its acceleration?
If an object's mass doubles while $F_{net}$ stays constant, what happens to its acceleration?
Tap to reveal answer
Acceleration becomes half as large. Doubling mass halves acceleration: $a = \frac{F}{2m}$.
Acceleration becomes half as large. Doubling mass halves acceleration: $a = \frac{F}{2m}$.
← Didn't Know|Knew It →
Which statement is correct: mass changes with location or mass stays the same with location?
Which statement is correct: mass changes with location or mass stays the same with location?
Tap to reveal answer
Mass stays the same with location. Mass is intrinsic; weight changes with gravity.
Mass stays the same with location. Mass is intrinsic; weight changes with gravity.
← Didn't Know|Knew It →
Two objects feel the same $F_{net}$. Object A has $2\times$ the mass of B. Which has greater acceleration?
Two objects feel the same $F_{net}$. Object A has $2\times$ the mass of B. Which has greater acceleration?
Tap to reveal answer
Object B. Less mass means greater acceleration for same force.
Object B. Less mass means greater acceleration for same force.
← Didn't Know|Knew It →
Calculate mass when $F_{net} = 15,\text{N}$ and $a = 3,\text{m/s}^2$.
Calculate mass when $F_{net} = 15,\text{N}$ and $a = 3,\text{m/s}^2$.
Tap to reveal answer
$m = 5,\text{kg}$. Using $m = \frac{F_{net}}{a} = \frac{15}{3} = 5$.
$m = 5,\text{kg}$. Using $m = \frac{F_{net}}{a} = \frac{15}{3} = 5$.
← Didn't Know|Knew It →
Calculate net force when $m = 2,\text{kg}$ and $a = 6,\text{m/s}^2$.
Calculate net force when $m = 2,\text{kg}$ and $a = 6,\text{m/s}^2$.
Tap to reveal answer
$F_{net} = 12,\text{N}$. Using $F_{net} = ma = 2 \times 6 = 12$.
$F_{net} = 12,\text{N}$. Using $F_{net} = ma = 2 \times 6 = 12$.
← Didn't Know|Knew It →
Calculate acceleration when $F_{net} = 12,\text{N}$ and $m = 3,\text{kg}$.
Calculate acceleration when $F_{net} = 12,\text{N}$ and $m = 3,\text{kg}$.
Tap to reveal answer
$a = 4,\text{m/s}^2$. Using $a = \frac{F_{net}}{m} = \frac{12}{3} = 4$.
$a = 4,\text{m/s}^2$. Using $a = \frac{F_{net}}{m} = \frac{12}{3} = 4$.
← Didn't Know|Knew It →
What happens to acceleration if net force stays constant and mass increases?
What happens to acceleration if net force stays constant and mass increases?
Tap to reveal answer
Acceleration decreases. From $a = \frac{F_{net}}{m}$, larger $m$ means smaller $a$.
Acceleration decreases. From $a = \frac{F_{net}}{m}$, larger $m$ means smaller $a$.
← Didn't Know|Knew It →
Which quantity measures an object's resistance to changes in motion and increases with mass?
Which quantity measures an object's resistance to changes in motion and increases with mass?
Tap to reveal answer
Inertia. More massive objects resist motion changes more.
Inertia. More massive objects resist motion changes more.
← Didn't Know|Knew It →
Identify the correct relationship between acceleration and mass when net force is constant.
Identify the correct relationship between acceleration and mass when net force is constant.
Tap to reveal answer
$a \propto \frac{1}{m}$. Acceleration is inversely proportional to mass.
$a \propto \frac{1}{m}$. Acceleration is inversely proportional to mass.
← Didn't Know|Knew It →
What happens to acceleration if mass stays constant and net force increases?
What happens to acceleration if mass stays constant and net force increases?
Tap to reveal answer
Acceleration increases. From $a = \frac{F_{net}}{m}$, larger $F_{net}$ means larger $a$.
Acceleration increases. From $a = \frac{F_{net}}{m}$, larger $F_{net}$ means larger $a$.
← Didn't Know|Knew It →
What is the acceleration equation solved from Newton's second law in terms of net force and mass?
What is the acceleration equation solved from Newton's second law in terms of net force and mass?
Tap to reveal answer
$a = \frac{F_{net}}{m}$. Rearranging $F_{net} = ma$ by dividing both sides by $m$.
$a = \frac{F_{net}}{m}$. Rearranging $F_{net} = ma$ by dividing both sides by $m$.
← Didn't Know|Knew It →
A graph shows $a$ decreases as $m$ increases for constant $F_{net}$. Identify the relationship.
A graph shows $a$ decreases as $m$ increases for constant $F_{net}$. Identify the relationship.
Tap to reveal answer
Inverse relationship between $a$ and $m$. As mass increases, acceleration decreases proportionally.
Inverse relationship between $a$ and $m$. As mass increases, acceleration decreases proportionally.
← Didn't Know|Knew It →
What is Newton's second law equation that relates net force, mass, and acceleration?
What is Newton's second law equation that relates net force, mass, and acceleration?
Tap to reveal answer
$F_{net} = ma$. Net force equals mass times acceleration.
$F_{net} = ma$. Net force equals mass times acceleration.
← Didn't Know|Knew It →
Which option best describes mass in motion: amount of matter or force due to gravity?
Which option best describes mass in motion: amount of matter or force due to gravity?
Tap to reveal answer
Amount of matter. Mass is a measure of matter, not a force.
Amount of matter. Mass is a measure of matter, not a force.
← Didn't Know|Knew It →
Which option best describes weight: mass or gravitational force on an object?
Which option best describes weight: mass or gravitational force on an object?
Tap to reveal answer
Gravitational force on an object. Weight is the force gravity exerts on mass.
Gravitational force on an object. Weight is the force gravity exerts on mass.
← Didn't Know|Knew It →
What is inertia, in terms of how an object responds to changes in motion?
What is inertia, in terms of how an object responds to changes in motion?
Tap to reveal answer
Resistance to changes in motion. Objects with more inertia resist acceleration more.
Resistance to changes in motion. Objects with more inertia resist acceleration more.
← Didn't Know|Knew It →
Calculate acceleration: $F_{net} = 12\ \text{N}$ on $m = 3\ \text{kg}$. What is $a$?
Calculate acceleration: $F_{net} = 12\ \text{N}$ on $m = 3\ \text{kg}$. What is $a$?
Tap to reveal answer
$4\ \text{m/s}^2$. Using $a = \frac{F_{net}}{m} = \frac{12}{3} = 4$.
$4\ \text{m/s}^2$. Using $a = \frac{F_{net}}{m} = \frac{12}{3} = 4$.
← Didn't Know|Knew It →
Calculate acceleration: $F_{net} = 12\ \text{N}$ on $m = 6\ \text{kg}$. What is $a$?
Calculate acceleration: $F_{net} = 12\ \text{N}$ on $m = 6\ \text{kg}$. What is $a$?
Tap to reveal answer
$2\ \text{m/s}^2$. Using $a = \frac{F_{net}}{m} = \frac{12}{6} = 2$.
$2\ \text{m/s}^2$. Using $a = \frac{F_{net}}{m} = \frac{12}{6} = 2$.
← Didn't Know|Knew It →
If $m$ doubles and $F_{net}$ stays constant, by what factor does $a$ change?
If $m$ doubles and $F_{net}$ stays constant, by what factor does $a$ change?
Tap to reveal answer
$a$ becomes $\frac{1}{2}$ as large. Doubling $m$ in $a = \frac{F_{net}}{m}$ halves $a$.
$a$ becomes $\frac{1}{2}$ as large. Doubling $m$ in $a = \frac{F_{net}}{m}$ halves $a$.
← Didn't Know|Knew It →
If $m$ is cut in half and $F_{net}$ stays constant, by what factor does $a$ change?
If $m$ is cut in half and $F_{net}$ stays constant, by what factor does $a$ change?
Tap to reveal answer
$a$ becomes $2$ times as large. Halving $m$ in $a = \frac{F_{net}}{m}$ doubles $a$.
$a$ becomes $2$ times as large. Halving $m$ in $a = \frac{F_{net}}{m}$ doubles $a$.
← Didn't Know|Knew It →