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Enzyme Structure and Catalysis (5E) Practice Test
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Q1
A soluble human hydrolase (E) catalyzes cleavage of an ester substrate (S) in buffered aqueous solution at 37°C. Initial rates were measured at varying $S$ with and without 10 µM inhibitor X. The data are summarized: without X, $V_{\max}=120$ nM·s$^{-1}$ and $K_m=15$ µM; with X, $V_{\max}=118$ nM·s$^{-1}$ and apparent $K_m=60$ µM. Assume enzyme concentration is unchanged and product inhibition is negligible. Based on the vignette, which outcome is most consistent with the presence of a competitive inhibitor?
Constants: none needed beyond values provided.
A soluble human hydrolase (E) catalyzes cleavage of an ester substrate (S) in buffered aqueous solution at 37°C. Initial rates were measured at varying $S$ with and without 10 µM inhibitor X. The data are summarized: without X, $V_{\max}=120$ nM·s$^{-1}$ and $K_m=15$ µM; with X, $V_{\max}=118$ nM·s$^{-1}$ and apparent $K_m=60$ µM. Assume enzyme concentration is unchanged and product inhibition is negligible. Based on the vignette, which outcome is most consistent with the presence of a competitive inhibitor?
Constants: none needed beyond values provided.