Trapezoids - Math

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Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{14+26}{2}$\times(20)=400$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{1+25}{2}$\times(17)=221$

A trapezoid has two bases measuring and , and a height measuring

What is its area?

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To find the area of a trapezoid, use this formula: $area= $\frac{base +base}{2}$\times height$ .

Use the information from the question to solve.

$a= $\frac{3cm+5cm}{2}$\times4cm$

$a=\frac{8cm}{2}$\times 4cm$

$a=4cm\times $4cm=16cm^2$$

The area is .

Calculate the area of the trapezoid:

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Break the figure into a rectangle and a triangle. Use the dotted line as a guide. The rectangle has a length of 8 and a width of 6. The triangle has a base of 6 and width of 6.

Area of the rectangle:

$A=l\times w$

$A=6\times 8=48\ $ft^2$$

Area of the triangle:

$A=\frac{1}{2}$b\times h$

$A=\frac{1}{2}$\times 6\times 6=3\times 6=18\ $ft^2$$

Add them together:

$A=48\ $ft^2$+18\ $ft^2$=66\ $ft^2$$

Figure not drawn to scale

Find the area of the trapezoid.

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In order to find the area of the trapezoid, we must follow the formula below:

One of the bases of the trapezoid

The other base of the trapezoid

The height of the trapezoid

In this question, , , and $h=6\ in$

$A=\frac{1}{2}$(24)6\rightarrow$

$A=126\rightarrow$

By following the formula and order of operations, we are able to solve the problem. The area of the trapezoid is 72 in.2

Find the area of the trapezoid:

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$A=\frac{1}{2}$(b_1+b_2)(h)$

$A=\frac{1}{2}$(6+10)(4)$

$A=\frac{1}{2}$(16)(4)$

In a trapezoid, the top base is equal to 5 and the bottom base is equal to 11. It has a height of 6. What is the area?

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The area of a trapezoid is equal to the sum of the bases, divided by 2, and then multiplied by the height:

$Area=\frac{base+base}{2}$\cdot height$

$$\frac{5+11}{2}$\cdot 6$

$$\frac{16}{2}$\cdot 6$

$8\cdot 6$

A trapezoid's bases are and long. It's height is . What is the area of this trapezoid?

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The formula to calculate the area of a trapezoid is:

$A = $\frac{base + base}{2}$\times height$

$A = $\frac{6cm+8cm}{2cm}$\times5cm$

$A= $\frac{14cm}{2cm}$\times5cm$

$A= 7cm\times5cm$

Find the area of a trapezoid whose bases are and and height is .

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To solve, simply use the formula for the area of a trapezoid. Thus,

$A=\frac{1}{2}$(B1+B2)h=\frac{1}{2}$(4+6)5=\frac{1}{2}$10*5=25$

Find the area of a trapezoid with bases and , and height .

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To solve, simply use the formula for the area of a trapezoid. Thus,

$A=\frac{1}{2}$(b1+b2)h=\frac{1}{2}$(5+4)6=\frac{1}{2}$9*6=27$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{9+30}{2}$\times(15)=292.5$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{15+30}{2}$\times(25)=562.5$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{2+20}{2}$\times(9)=99$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{6+20}{2}$\times(16)=208$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{9+3}{2}$\times(5)=30$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{3+6}{2}$\times(4)=18$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{11+5}{2}$\times(6)=48$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{2+4}{2}$\times(4)=12$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{3+1}{2}$\times(4)=8$

Find the area of the trapezoid.

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Recall the formula for finding the area of a trapezoid:

$$\text{Area}$=\frac{base_1+base_2}{2}$\times(height)$

Now, plug in the values for the bases and the height to find the area.

$$\text{Area}$=\frac{3+25}{2}$\times(12)=168$