Polar - Math

Card 0 of 16

The polar coordinates of a point are $\left(2.1, $\frac{7\pi }{3}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

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Given the polar coordinates $(r,\theta )$ , the -coordinate is $y= r \sin \theta$ . We can find this coordinate by substituting $r = 2.1, \theta = $\frac{7\pi }{3}$$ :

$y = r \sin \theta = 2.1 \cdot \sin $\frac{7\pi }{3}$ \approx 2.1 \cdot 0.8660 \approx 1.82$

The polar coordinates of a point are $\left(2.1, $\frac{7\pi }{3}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

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Given the polar coordinates $(r,\theta )$ , the -coordinate is $x= r \cos \theta$ . We can find this coordinate by substituting $r = 2.1, \theta = $\frac{7\pi }{3}$$ :

$x = r \cos \theta = 2.1 \cdot \cos $\frac{7\pi }{3}$ = 2.1 \cdot 0.5 = 1.05$

The polar coordinates of a point are $\left(1.2, $\frac{2\pi }{5}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

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Given the polar coordinates $(r,\theta )$ , the -coordinate is $x= r \cos \theta$ . We can find this coordinate by substituting $r = 1.2, \theta = $\frac{2\pi }{5}$$ :

$x = r \cos \theta = 1.2 \cdot \cos $\frac{2\pi }{5}$ \approx 1.2 \cdot 0.3090 \approx 0.37$

The polar coordinates of a point are $\left(1.2, $\frac{2\pi }{5}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

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Given the polar coordinates $(r,\theta )$ , the -coordinate is $y= r \sin \theta$ . We can find this coordinate by substituting $r = 1.2, \theta = $\frac{2\pi }{5}$$ :

$y = r \cos \theta = 1.2 \cdot \sin $\frac{2\pi }{5}$ \approx 1.2 \cdot 0.9511 \approx 1.14$

The polar coordinates of a point are $\left(2.1, $\frac{7\pi }{3}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $y= r \sin \theta$ . We can find this coordinate by substituting $r = 2.1, \theta = $\frac{7\pi }{3}$$ :

$y = r \sin \theta = 2.1 \cdot \sin $\frac{7\pi }{3}$ \approx 2.1 \cdot 0.8660 \approx 1.82$

The polar coordinates of a point are $\left(2.1, $\frac{7\pi }{3}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $x= r \cos \theta$ . We can find this coordinate by substituting $r = 2.1, \theta = $\frac{7\pi }{3}$$ :

$x = r \cos \theta = 2.1 \cdot \cos $\frac{7\pi }{3}$ = 2.1 \cdot 0.5 = 1.05$

The polar coordinates of a point are $\left(1.2, $\frac{2\pi }{5}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $x= r \cos \theta$ . We can find this coordinate by substituting $r = 1.2, \theta = $\frac{2\pi }{5}$$ :

$x = r \cos \theta = 1.2 \cdot \cos $\frac{2\pi }{5}$ \approx 1.2 \cdot 0.3090 \approx 0.37$

The polar coordinates of a point are $\left(1.2, $\frac{2\pi }{5}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $y= r \sin \theta$ . We can find this coordinate by substituting $r = 1.2, \theta = $\frac{2\pi }{5}$$ :

$y = r \cos \theta = 1.2 \cdot \sin $\frac{2\pi }{5}$ \approx 1.2 \cdot 0.9511 \approx 1.14$

The polar coordinates of a point are $\left(1.2, $\frac{2\pi }{5}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $x= r \cos \theta$ . We can find this coordinate by substituting $r = 1.2, \theta = $\frac{2\pi }{5}$$ :

$x = r \cos \theta = 1.2 \cdot \cos $\frac{2\pi }{5}$ \approx 1.2 \cdot 0.3090 \approx 0.37$

The polar coordinates of a point are $\left(1.2, $\frac{2\pi }{5}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $y= r \sin \theta$ . We can find this coordinate by substituting $r = 1.2, \theta = $\frac{2\pi }{5}$$ :

$y = r \cos \theta = 1.2 \cdot \sin $\frac{2\pi }{5}$ \approx 1.2 \cdot 0.9511 \approx 1.14$

The polar coordinates of a point are $\left(2.1, $\frac{7\pi }{3}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $y= r \sin \theta$ . We can find this coordinate by substituting $r = 2.1, \theta = $\frac{7\pi }{3}$$ :

$y = r \sin \theta = 2.1 \cdot \sin $\frac{7\pi }{3}$ \approx 2.1 \cdot 0.8660 \approx 1.82$

The polar coordinates of a point are $\left(2.1, $\frac{7\pi }{3}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $x= r \cos \theta$ . We can find this coordinate by substituting $r = 2.1, \theta = $\frac{7\pi }{3}$$ :

$x = r \cos \theta = 2.1 \cdot \cos $\frac{7\pi }{3}$ = 2.1 \cdot 0.5 = 1.05$

The polar coordinates of a point are $\left(1.2, $\frac{2\pi }{5}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $x= r \cos \theta$ . We can find this coordinate by substituting $r = 1.2, \theta = $\frac{2\pi }{5}$$ :

$x = r \cos \theta = 1.2 \cdot \cos $\frac{2\pi }{5}$ \approx 1.2 \cdot 0.3090 \approx 0.37$

The polar coordinates of a point are $\left(1.2, $\frac{2\pi }{5}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $y= r \sin \theta$ . We can find this coordinate by substituting $r = 1.2, \theta = $\frac{2\pi }{5}$$ :

$y = r \cos \theta = 1.2 \cdot \sin $\frac{2\pi }{5}$ \approx 1.2 \cdot 0.9511 \approx 1.14$

The polar coordinates of a point are $\left(2.1, $\frac{7\pi }{3}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $y= r \sin \theta$ . We can find this coordinate by substituting $r = 2.1, \theta = $\frac{7\pi }{3}$$ :

$y = r \sin \theta = 2.1 \cdot \sin $\frac{7\pi }{3}$ \approx 2.1 \cdot 0.8660 \approx 1.82$

The polar coordinates of a point are $\left(2.1, $\frac{7\pi }{3}\right )$ . Give its -coordinate in the rectangular coordinate system (nearest hundredth).

Tap to see back →

Given the polar coordinates $(r,\theta )$ , the -coordinate is $x= r \cos \theta$ . We can find this coordinate by substituting $r = 2.1, \theta = $\frac{7\pi }{3}$$ :

$x = r \cos \theta = 2.1 \cdot \cos $\frac{7\pi }{3}$ = 2.1 \cdot 0.5 = 1.05$